var s1,s:ansistring;
i,t,c,co,h:longint;
begin
readln(s);
t:=0;
h:=0;
for i:=1 to length(s)-1 do
begin
if (s[i]>='0') and (s[i]<='9') then
begin
h:=h+1;
val(s[i],c,co);
t:=t+c*h;
end;
end;
t:=t mod 11;
if chr(t+48)=s[length(s)] then write('Right')
else if (t=10) and (s[length(s)]='X') then write('Right')
else begin for i:=1 to length(s)-1 do write(s[i]); if t=10 then write('X') else write(t); end;
end.

#include<stdio.h>
int main()
{
int sum=0;
int a;
char isbn[13];
scanf("%s-%s%s%s-%s%s%s%s%s-%s",&isbn[0],&isbn[1],&isbn[2],&isbn[3],&isbn[4],&isbn[5],&isbn[6],&isbn[7],&isbn[8],&isbn[9],&isbn[10],&isbn[11],&isbn[12]);
sum+=((isbn[0]-48)*1);
sum+=((isbn[2]-48)*2);
sum+=((isbn[3]-48)*3);
sum+=((isbn[4]-48)*4);
sum+=((isbn[6]-48)*5);
sum+=((isbn[7]-48)*6);
sum+=((isbn[8]-48)*7);
sum+=((isbn[9]-48)*8);
sum+=((isbn[10]-48)*9);
a=sum%11;
if(a==10)
{
a='X'-88;
}
if((a==isbn[12]-48)&&(a!='X'-88)||(a==isbn[12]-88)&&(a=='X'-88))
printf("Right");
else if(a!='X'-88)
{
printf("%c-%c%c%c-%c%c%c%c%c-%d",isbn[0],isbn[2],isbn[3],isbn[4],isbn[6],isbn[7],isbn[8],isbn[9],isbn[10],a);
}
else
{
printf("%c-%c%c%c-%c%c%c%c%c-X",isbn[0],isbn[2],isbn[3],isbn[4],isbn[6],isbn[7],isbn[8],isbn[9],isbn[10]);
}
}

#include <stdio.h>

int main()
{
char s[10000];
int i;
int sum=0;
int a;
int b = 1;
for(i=0;i<13;i++)
{
scanf("%c",&s[i]);
}
for(i=0;i<11;i++)
{
if(s[i]!='-')
sum+=(s[i]-48)*(b++);
}
a = sum % 11;
if(a==10)
{
if(s[12]=='X')
printf("Right");
else
{
s[12] = 'X';
printf("%s",s);
}
}
else if(a==(s[12]-48))
printf("Right");
else
{
s[12] = a+48;

printf("%s",s);
}
return 0;
}

#include <iostream>
#include <cstring>
#include <algorithm>

using namespace std;
char str[100];
int sum=0;
int main(){
    for(int i = 1; i<=13;i++){
        str[i]=getchar();
    }
//  cin>>str+1;
    sum+=(str[1]-'0')*1;
    sum+=(str[3]-'0')*2;
    sum+=(str[4]-'0')*3;
    sum+=(str[5]-'0')*4;
    sum+=(str[7]-'0')*5;
    sum+=(str[8]-'0')*6;
    sum+=(str[9]-'0')*7;
    sum+=(str[10]-'0')*8;
    sum+=(str[11]-'0')*9;
    sum = sum%11;
    if(sum==str[13]-'0'||sum==10&&str[13]=='X'){
        cout<<"Right"<<endl;
    }else{
        if(sum==10){
            str[13]='X';
            
        }else{
            str[13]='0'+sum;
        }
        cout<<str+1<<endl;
    }
    return 0;   
} 

当求余之后为10的时候需要判断 标识位是否为‘X’这很重要 ：：：：~~~！！！！@@@@

#include <iostream>

using namespace std;
int main()
{
int i=0,j=1,s=0;
char str[14];
cin >> str;
while(i<12)
{
if(str[i] >= '0' && str[i] <= '9')
{
s = s + (str[i] - '0') * j;
j++;
}
i++;
}
str[i+1] = '\0';
if(s%11 == (str[i] - '0'))
cout << "Right" <<endl;
else if((s%11 == 10)&&(str[i] == 'X'))
cout << "Right" <<endl;
else if(s%11 == 10)
{
str[i] = 'X';
cout << str << endl;
}
else
{
str[i] = s%11 + '0';
cout << str << endl;
}
return 0;
}

#include<iostream>
#include<algorithm>
#include<string>
#include<cstdio>
#include<cmath>
#include<cstdlib>
#include<set>
#include<stack>
#include<sstream>
#include<map>
#include<vector>
#include<queue>
using namespace std;
string isbn;
int main(){
cin>>isbn;
int cnt;
cnt+=(isbn[0]-'0')*1;
cnt+=(isbn[2]-'0')*2;
cnt+=(isbn[3]-'0')*3;
cnt+=(isbn[4]-'0')*4;
cnt+=(isbn[6]-'0')*5;
cnt+=(isbn[7]-'0')*6;
cnt+=(isbn[8]-'0')*7;
cnt+=(isbn[9]-'0')*8;
cnt+=(isbn[10]-'0')*9;
if(isbn[12]=='X'&&cnt%11==10) cout<<"Right"<<endl;
else if(isbn[12]-'0'==cnt%11) cout<<"Right"<<endl;
else
{
for(int i=0;i<=11;i++)
printf("%c",isbn[i]);
if(cnt%11==10) cout<<"X"<<endl;
else printf("%d\n",cnt%11);
}

return 0;
}

#include<iostream>
using namespace std;
int main()
{
    char a[20] = {};
    cin.getline(a, 15);
    int b[15] = {};

    b[1] = a[0] - '0';
    b[2] = a[2] - '0';
    b[3] = a[3] - '0';
    b[4] = a[4] - '0';
    b[5] = a[6] - '0';
    b[6] = a[7] - '0';
    b[7] = a[8] - '0';
    b[8] = a[9] - '0';
    b[9] = a[10] - '0';
    /*for (int i = 1; i <= 9; i++)
    {
        cout << b[i];
    }*/
    int stdan = 0;
    for (int i = 1; i < 10; i++)
    {

        stdan += (b[i] * i);
    }
    //cout << stdan << endl;
    stdan %= 11;
    //cout << stdan << endl;
    if (stdan == 10)
    {
        //cout << "stdan == 10" << endl;
        if (a[12] == 'X')
            cout << "Right" << endl;
        else
        {
            cout << b[1] << '-' << b[2] << b[3] << b[4];
            cout << '-' << b[5] << b[6] << b[7] << b[8] << b[9] << '-';
            cout << 'X' << endl;
        }
    }
    else
    {
        // cout << std;
        // cout << a[12] << endl;
        int temp = (a[12] - 48);
        // cout << "temp = " << temp << endl;
        if (temp == stdan)
        {
            //cout << stdan;
            cout << "Right" << endl;
        }
        else
        {
            cout << b[1] << '-' << b[2] << b[3] << b[4];
            cout << '-' << b[5] << b[6] << b[7] << b[8] << b[9] << '-';
            cout << stdan << endl;
        }
        //temp = '0';
        //cout << temp;
        system("pause");
        return 0;

    }
}

c++代码：

#include<iostream>
#include<cstring>
using namespace std;//头文件
int main()
{
char s[20]; //isbn号码需要使用的字符串
int i,ans=0,sum=0;
cin>>s;//输入isbn号码
for(i=0;i<=11;i++){
if(s[i]>=48&&s[i]<=57){
sum++;//数字的位数
ans+=sum*(s[i]-48);//累乘计算mod前的值
}
else continue;//遇到“-”不处理
}
ans%=11;//mod11得到isbn的识别码
ans+=48;//转换为ASCII码
if(ans==58) ans='X';//处理“X”
if(ans==s[12]) cout<<"Right"<<endl;//判断是否正确
else {
s[12]=ans;//将正确的值赋给最后一位
for(i=0;i<=12;i++) cout<<s[i];//输出正确的值
cout<<endl;
}
return 0;
}

卧槽。。。。。。。。。。拿这个题恢复一下手感，寒假刚开始堕落。。。。做题挽救下自己
```c++
#include<cstdio>
#include<algorithm>
#include<cstdlib>
#include<cstring>
int main()
{
char s[13];
scanf("%s",s);
int c = (s[0]-'0') + (s[2]-'0')*2+(s[3]-'0')*3+(s[4]-'0')*4+(s[6]-'0')*5+(s[7]-'0')*6+(s[8]-'0')*7+(s[9]-'0')*8+(s[10]-'0')*9;
//对余数为10特殊处理
if(c%11 == 10)
{
if(s[12] == 'X')printf("Right");
else
{
s[12] = 'X';
printf("%s",s);
}
}
else
{
if((s[12]-'0') == c%11) printf("Right");
else
{
s[12] = c%11+'0';
printf("%s",s);
}
}
return 0 ;
}

比起立体图来，这个简单多了！
代码仅供参考，最好**不要**ctrlC+ctrlV照搬！
```c++
#include <bits/stdc++.h>
using namespace std;

int main()
{
string str;
char ch;
int i,n=1,sum=0;
getline(cin,str);
for(i=0;i<11;i++)
if(i!=1&&i!=5)
{
sum=sum+(str[i]-48)*n;
n++;
}
sum=sum%11;
if(sum==10) ch='X';
else ch=sum+48;
if(str[12]==ch) cout<<"Right"<<endl;
else
{
for(i=0;i<12;i++) cout<<str[i];
cout<<ch<<endl;
}
return 0;
}
```

比起立体图来，这个简单多了！
代码仅供参考，最好**不要**ctrlC+ctrlV照搬！

···c++
#include <bits/stdc++.h>
using namespace std;

int main()
{
string str;
char ch;
int i,n=1,sum=0;
getline(cin,str);
for(i=0;i<11;i++)
if(i!=1&&i!=5)
{
sum=sum+(str[i]-48)*n;
n++;
}
sum=sum%11;
if(sum==10) ch='X';
else ch=sum+48;
if(str[12]==ch) cout<<"Right"<<endl;
else
{
for(i=0;i<12;i++) cout<<str[i];
cout<<ch<<endl;
}
return 0;
}
```

#include <stdio.h>
#include <stdlib.h>

char a[15],b[15];
main(){

int i = 1,k = 1,ans = 0;
char c;
while((c = getchar()) != '\n'){

a[i] = c;
i ++;
}
char x[10] = {'0','1','2','3','4','5','6','7','8','9'};
for(i = 1;i <= 12;i ++)
{
for(int j = 0;j <= 9;j ++)
{
if(a[i] == x[j]){
ans += j*k;
k++;
}
}
}
ans = ans%11;
if(ans == 10)
{
if(a[13] == 'X')
printf("Right");
else
{
a[13] = 'X';
for(i = 1;i <= 13;i ++)
printf("%c",a[i]);
}
}
else {
int tail;
for(i = 0;i <= 9;i ++)
{
if(a[13] == x[i])
tail = i;
}
if(ans == tail){
printf("Right");
}
if(ans != tail){
for(i = 1;i <= 12;i ++)
printf("%c",a[i]);
printf("%d",ans);
}
}
}

#include <cstdio>
#include <cstdlib>
#include <iostream>

using namespace std;

int main()
{

string s;
cin >> s;

int num(0);

for (int i(0),j(1); i < 12; i++)
if( s[i] != '-')
num += (s[i] - '0') * j++;

if(s[12] == 'X' && num % 11 == 10 || (s[12] -'0') == num % 11)
cout << "Right";
else if(num % 11 == 10){

s[12] = 'X';
cout<< s;

}else{

s[12] += num % 11 - (s[12] - '0');
cout << s;
}

}
//2333333333333

#include<iostream>
#include<string>
using namespace std;
int main(){
    string s;
    cin>>s;
    int tot(0);
    char mod[12]="0123456789X";
    for(int i(0),j(1);i<12;i++){
        if(s[i]=='-')continue;
        tot+=(s[i]-'0')*j++;
    }
    if(mod[tot%11]==s[12])cout<<"Right";
    else s[12]=mod[tot%11],cout<<s;
    return 0;
}

#include <iostream>
#include <cstdio>

using namespace std;

int main()
{
char a[10];
char ans;
int i, temp = 0;
scanf("%c-%c%c%c-%c%c%c%c%c-%c", &a[0], &a[1], &a[2], &a[3], &a[4], &a[5], &a[6], &a[7], &a[8], &a[9]);
for(i=1;i<=9;++i)
temp+=((int)a[i-1]-48)*i;
temp%=11;
if(temp==10)temp='X'-48;
if((char)(temp+48)==a[9])cout<<"Right";
else printf("%c-%c%c%c-%c%c%c%c%c-%c", a[0], a[1], a[2], a[3], a[4], a[5], a[6], a[7], a[8], temp+48);
// system("pause");
return 0;
}

#include <iostream>
#include <cstdio>

using namespace std;

int main()
{
char a[10];
char ans;
int i, temp = 0;
a[0]=getchar();
getchar();
a[1]=getchar();
a[2]=getchar();
a[3]=getchar();
getchar();
a[4]=getchar();
a[5]=getchar();
a[6]=getchar();
a[7]=getchar();
a[8]=getchar();
getchar();
a[9]=getchar();
for(i=1;i<=9;++i)
temp+=((int)a[i-1]-48)*i;
temp%=11;
if(temp==10)temp='X'-48;
if((char)(temp+48)==a[9])cout<<"Right";
else printf("%c-%c%c%c-%c%c%c%c%c-%c", a[0], a[1], a[2], a[3], a[4], a[5], a[6], a[7], a[8], temp+48);
// system("pause");
return 0;
}

代码
#include<cstdio>
#include<algorithm>
#include<cstring>
using namespace std;
char a[14];
int main()
{
scanf("%s",a);
int n=1;
int ans=0;
for(int i=0;i<=11;i++)
{
if(a[i]!='-')
{
ans=ans+(a[i]-'0')*n;
n++;
}
}
ans=ans%11;
if(ans!=10)
{
if(ans==a[12]-'0')
{
printf("Right");
}
else
{
for(int i=0;i<=11;i++)
{
printf("%c",a[i]);
}
printf("%d",ans);
}

}
else
{
if(a[12]=='X')
{
printf("Right");
}
else
{
for(int i=0;i<=11;i++)
{
printf("%c",a[i]);
}
printf("X");
}
}
}

pascal
var s:string;
t,i,j:longint;
begin
 readln(s);
 j:=1;
 for i:=1 to length(s)-2 do
 begin
  if(s[i]>='0')and(s[i]<='9')
  then begin
   t:=t+(ord(s[i])-ord('0'))*j;
   inc(j);
  end;
 end;
 t:=t mod 11;
 if(ord(s[length(s)])-ord('0')=t)or((t=10)and(s[length(s)]='X'))
 then writeln('Right')
 else begin
  if(t=10)then s[length(s)]:='X'
  else s[length(s)]:=chr(ord('0')+t);
  writeln(s);
 end;
end.

正则水过。人生苦短，我用python
```python
import re

m = re.match(r'(\d)-(\d{3})-(\d{5})-(\w)', raw_input())
x = m.group(1)+m.group(2)+m.group(3)
if m.group(4) == 'X':
gt = 10
else:
gt = int(m.group(4))-int('0')
rk = 1
ans = 0
for i in x:
ans += rk*(int(i)-int('0'))
rk += 1
if ans%11 == gt:
print "Right"
else:
if ans%11 == 10:
res = 'X'
else:
res = str(ans%11)
print m.group(1)+'-'+m.group(2)+'-'+m.group(3)+'-'+res
```

#include <cstdio>

int main(){
freopen("in.txt","r",stdin);
int a[11],sum=0;
char c;
scanf("%1d-%1d%1d%1d-%1d%1d%1d%1d%1d-%c",
&a[1],&a[2],&a[3],&a[4],&a[5],
&a[6],&a[7],&a[8],&a[9],&c);
for(int i=1;i<=9;i++)
sum+=i*a[i];
sum%=11;
int flag=0;
if(sum==c-'0'||(c=='X'&&sum==10)){
printf("Right");
return 0;
}
printf("%d-%d%d%d-%d%d%d%d%d-",
a[1],a[2],a[3],a[4],a[5],
a[6],a[7],a[8],a[9]);
if(sum==10)
printf("X");
else
printf("%d",sum);
return 0;
}