#include <iostream>
#include <cstdio>
#include <string>
using namespace std;
int main()
{
string c;
cin >> c;
int s = 0;
int k = 1;

for (int i = 0; i < c.size()-1; i++)
{
if (c[i] >= '0'&&c[i] <= '9')
{
/*cout <<c[i];*/
/*cout << k;*/
s = s + (c[i] - '0')*k;
k++;
}
}
int dd= c.size() - 1;
int vis = s % 11;
if (vis == c[dd] - '0')
{
cout << "Right" << endl;
}
else
{
if (vis == 10&& c[dd] == 'X')
{
cout << "Right" << endl;
}
else
{
for (int i = 0; i < c.size() - 1; i++)
{
cout << c[i];
}
if (vis == 10)
{
cout << "X" << endl;
}
else
{
cout << vis << endl;
}
}
}
return 0;
}

50次终于AC....输入数据坑人啊！！！！！！！！
第4个点和第7个点输入的识别码是X！
对没错，也就是说需要在原来程序的基础上添加判断输入数据是X的判定
var st:string;
a:array[1..10]of longint;
i,j,t,s:longint;
begin
readln(st);s:=0;
delete(st,2,1);
delete(st,5,1);
delete(st,10,1);
for i:=1 to 9 do
a[i]:=ord(st[i])-48;
if st[10]='X' then a[10]:=10 else a[10]:=ord(st[10])-48;
for i:=1 to 9 do
s:=s+a[i]*i;
if s mod 11=a[10] then begin writeln('Right');exit;end else
if s mod 11=10 then
writeln(a[1],'-',a[2],a[3],a[4],'-',a[5],a[6],a[7],a[8],a[9],'-','X') else
writeln(a[1],'-',a[2],a[3],a[4],'-',a[5],a[6],a[7],a[8],a[9],'-',s mod 11);
end.

#include<iostream>
using namespace std;
char a[18];
int b,sum;
int main()
{
//freopen("p.in","r",stdin);
//freopen("p.out","w",stdout);
cin>>a;
b=((a[0]-'0')*1+(a[2]-'0')*2+(a[3]-'0')*3+(a[4]-'0')*4+(a[6]-'0')*5+(a[7]-'0')*6+(a[8]-'0')*7+(a[9]-'0')*8+(a[10]-'0')*9)%11;

if (b==10&&a[12]=='X')

{
cout<<"Right";
return 0;
}
if(a[12]-'0'==b)
{
cout<<"Right";
return 0;
}
else
{
for(int i=0;i<12;i++) cout<<a[i];
if (b==10) cout<<'X';
else cout<<b;
}
return 0;
}
//c++

注意还有一个X的情况
c
#include <stdio.h>
#define toint(x) (int)((x)-48)
int main(){
char isbn[50];
int i,vari = 0,cur;
scanf("%s",isbn);
for(i = 0,cur = 1;i<12;i++,cur++){
vari += (toint(isbn[i]) * cur);
if(i<11) {
if(isbn[i+1]=='-') i++;
}
}
vari %= 11;
if(vari!=10?isbn[12] == (vari + 48):isbn[12] == 'X') printf("Right\n");
else{
isbn[12] = vari == 10?'X':(vari+48);
printf("%s\n",isbn);
}
return 0;
}


题目中没有说 余数是10的情况，上网搜了一下，余数为10的用'X‘代替
```
/* ***********************************************
Author :guanjun
Created Time :2016/2/18 18:17:28
File Name :vijosp1484.cpp
************************************************ */
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <stdio.h>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <math.h>
#include <stdlib.h>
#include <iomanip>
#include <list>
#include <deque>
#include <stack>
#define ull unsigned long long
#define ll long long
#define mod 90001
#define INF 0x3f3f3f3f
#define maxn 10000+10
#define cle(a) memset(a,0,sizeof(a))
const ull inf = 1LL << 61;
const double eps=1e-5;
using namespace std;

bool cmp(int a,int b){
return a>b;
}
int a[11];
int main()
{
#ifndef ONLINE_JUDGE
//freopen("in.txt","r",stdin);
#endif
//freopen("out.txt","w",stdout);
string s,t,p;
while(cin>>s){
t=s;
int num=0;
for(int i=0;i<s.size();i++){
if(s[i]!='-')
if(s[i]=='X')a[++num]=10;
else a[++num]=int(s[i]-'0');
}
int sum=0;
for(int i=1;i<=num-1;i++){
sum+=a[i]*i;
}
//cout<<sum<<endl;
sum%=11;
if(sum==a[num]){
puts("Right");
}
else{
if(sum<10)
t[t.size()-1]=char(sum+'0');
else t[t.size()-1]='X';
cout<<t<<endl;
}
}
return 0;
}

var
s:string[13];
a:array[1..9]of 0..9;
i,t,n:longint;
b:boolean;
begin
{assign(input,'isbn.in');
reset(input);
assign(output,'isbn.out');
rewrite(output);}
readln(s);
fillchar(a,sizeof(a),0);
delete(s,2,1);
delete(s,5,1);
delete(s,10,1);
for i:=1 to 9 do
a[i]:=ord(s[i])-48;
if s[10]='X' then n:=10
else n:=ord(s[10])-48;
t:=0;
for i:=1 to 9 do
t:=t+i*a[i];
t:=t mod 11;
b:=true;
if t=n then begin
writeln('Right');
b:=false;
end;
if b then write(a[1],'-',a[2],a[3],a[4],'-',a[5],a[6],a[7],a[8],a[9],'-');
if b then begin
if t=10 then writeln('X')
else writeln(t);
end;
{close(input);
close(output);}
end.

C Code

#include<stdio.h>
int main()
{
char isbni[14];
int isbn[9];
// FILE *in=fopen("isbn.in","r"),*out=fopen("isbn.out","w");
int i,p=0,tol=0,last;
// fscanf(in,"%s",isbni);
scanf("%s",isbni);
for(i=0;i<=11;i++)
if(isbni[i]!='-')
{
isbn[p]=isbni[i]-48;
p++;
}
for(i=0;i<=8;i++)
tol+=isbn[i]*(i+1);
tol%=11;
if(isbni[12]!='X')
last=isbni[12]-48;
else
last=10;
if(last==tol)
printf("Right");
else
{
if(tol==10)
isbni[12]='X';
else
isbni[12]=tol+48;
printf("%s",isbni);
}
// fclose(out);
return 0;
}

so easy!

var s:string;
i,x:integer;
y:int64;
a:array[1..13] of integer;
begin
readln(s);
for i:=1 to 12 do
if s[i]<>'-' then begin inc(x); a[x]:=ord(s[i])-ord('0'); end;
if (s[13]='x') or (s[13]='X') then a[x+1]:=10
else a[x+1]:=ord(s[13])-ord('0');
for i:=1 to x do y:=y+a[i]*i;
y:=y mod 11;
if y=a[x+1] then writeln('Right')
else
begin
if y=10 then s[13]:='X'
else s[13]:=chr(y+ord('0'));
writeln(s);
end;
end.

不解，为什么不能AC？

#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int main()
{
char input1[64];
int weight = 1;
int h=0;
int sum1 = 0;
char *p;
FILE * fp;
FILE * fout;
fp = fopen("isbn.in","r");
fout=fopen("isbn.out","w");
fscanf(fp,"%s",input1);
p = input1;
while (*p!=0 && h<3)
{
if (*p=='-')
{
h++;
p++;
continue;
}
sum1 +=(*p++-'0')*weight;
weight++;
}
int y =sum1%11;

if(y==10)
{
if (*p=='X')
{
//printf("Right");
fprintf(fout,"Right");
}else if(*p!='X')
{
*p='X';
fprintf(fout,"%s",input1);
//printf("%s",input1);
}
}
else if ((*p-'0')==y && *p<='9')
fprintf(fout,"Right");
//printf("Right");
else
{
fix1:
*p=y+'0';
//printf("%s",input1);
fprintf(fout,"%s",input1);
}
fclose(fout);
fclose(fp);
}

只要注意X的特判就行了，也没什么难度。
#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstring>
using namespace std;
int main()
{
char a[15];
int b[15],c[15],i,j=1,s=0,n;
for(i=1;i<=13;i++){
cin>>a[i];
if(a[i]=='X')
b[i]=10;
else
b[i]=a[i]-48;
c[i]=b[i];
}
for(i=1;i<=9;i++){
if(b[j]<0||b[j]>9){
j++;
}
b[j]*=i;
s+=b[j];
j++;
}
n=s%11;
if(n==c[13]){
cout<<"Right";
}
else{
c[13]=n;
for(j=1;j<=13;j++){
if(j==2||j==6||j==12){
cout<<"-";
}

else{
if(c[j]==10){
cout<<"X";
break;
}
cout<<c[j];
}
}
}
return 0;
}

var
i,j,k,l,m,n,ans:longint;
s:string;
a,b:array[1..20] of longint;
begin
read(s);
for i:=1 to 12 do
if (s[i]<>'-') then
begin
j:=j+1;
a[j]:=ord(s[i])-48;
end;
for j:=1 to 9 do
begin
ans:=ans+a[j]*j;
end;
n:=ans mod 11;
if n=10 then
if s[13]='X' then write('Right') else
begin
for i:=1 to 12 do write(s[i]);
write('X');
end
else
if n=ord(s[13])-48 then write('Right')
else
begin
for i:=1 to 12 do write(s[i]); write(n);
end;
end.

注意X这个特殊情况别忘了- -平时写写不注意点没啥事。多交一次。要是比赛就炸了。
这道题不需要文件读入读出。害我还去写了文件。醉了。

基础的模拟题。自己按题目意思模拟吧！

###pascal code
program P1484;
var ISBN,add:string;
sum,i,s:longint;
begin //main
read(ISBN); s:=0;
for i:=1 to length(ISBN)-1 do
begin
if ISBN[i]<>'-' then
begin
inc(s);
sum:=sum+(ord(ISBN[i])-ord('0'))*s;
end;
end;
sum:=sum mod 11; str(sum,add);
if add='10' then add:='X';
if add=ISBN[i+1] then
write('Right')
else
begin
ISBN:=copy(ISBN,1,12); ISBN:=ISBN+add;
write(ISBN);
end;
end.

####Code:
#include<stdio.h>
main()
{
char a[13];
int i,sum;
for(i=1;i<=13;i++)
scanf("%c",&a[i]);
sum=(a[1]-48)*1+(a[3]-48)*2+(a[4]-48)*3+(a[5]-48)*4+(a[7]-48)*5
+(a[8]-48)*6+(a[9]-48)*7+(a[10]-48)*8+(a[11]-48)*9;
if(sum%11==(a[13]-48)||(sum%11==10&&a[13]=='X'))printf("Right");
else
{
if(sum%11==10)a[13]='X';
else a[13]=sum%11+48;
for(i=1;i<=13;i++)
printf("%c",a[i]);
}

}

var
s:string;
a:array[1..10] of longint;
i,j,p:longint;
begin
readln(s);
val(s[1],a[1],i);
val(s[3],a[2],i);
val(s[4],a[3],i);
val(s[5],a[4],i);
val(s[7],a[5],i);
val(s[8],a[6],i);
val(s[9],a[7],i);
val(s[10],a[8],i);
val(s[11],a[9],i);
val(s[13],p,i);
for i:=1 to 10 do
j:=j+a[i]*i;
j:=j mod 11;
if (j=p)or((j=10)and(s[13]='X')) then writeln('Right')
else
begin
for i:=1 to 12 do write(s[i]);
if j<>10 then writeln(j)
else writeln('X');
end;
end.

评测结果
编译成功

测试数据 #0: Accepted, time = 0 ms, mem = 548 KiB, score = 10
测试数据 #1: Accepted, time = 0 ms, mem = 548 KiB, score = 10
测试数据 #2: Accepted, time = 0 ms, mem = 548 KiB, score = 10
测试数据 #3: Accepted, time = 0 ms, mem = 556 KiB, score = 10
测试数据 #4: Accepted, time = 0 ms, mem = 552 KiB, score = 10
测试数据 #5: Accepted, time = 0 ms, mem = 552 KiB, score = 10
测试数据 #6: Accepted, time = 15 ms, mem = 552 KiB, score = 10
测试数据 #7: Accepted, time = 0 ms, mem = 548 KiB, score = 10
测试数据 #8: Accepted, time = 0 ms, mem = 552 KiB, score = 10
测试数据 #9: Accepted, time = 0 ms, mem = 552 KiB, score = 10
Accepted, time = 15 ms, mem = 556 KiB, score = 100

#include<cstdio>
#include<iostream>
using namespace std;
char c;
int a[11],ver;
void output(int veri){
cout<<a[1]<<"-";
for ( int i= 2;i<=4;i++) cout<<a[i];
cout<<"-";
for ( int i=5;i<=9;i++) cout<<a[i];
if ( veri == 10 ) printf("-X\n");else printf("-%d\n",veri);
}
int main()
{
c=getchar();
a[1]=c-'0';
getchar();
for ( int i = 2; i <= 4; i++){
c=getchar();
a[i]=c - '0';
}
getchar();
for ( int i = 5; i <= 9; i++){
c=getchar();
a[i]=c-'0';
}
getchar();c=getchar();
ver = (c == 'X') ? 10 : c - '0';
int tmp = 0;
for ( int i=1;i<=9;i++){
tmp += a[i]*i;
}
if ( ver == tmp%11 ) cout<<"Right"<<endl;else output(tmp%11);
return 0;
}

好水 但是看看自己半年前写的代码 发上来让大家嘲笑一下~！ 那时候还小啊~

#include <cstdio>
#include<iostream>
#include<cstring>
#include<algorithm>
using namespace std;
char isbn[13];
int end,tmp;
int main()
{
cin>>isbn;
end=isbn[0]+2*isbn[2]+3*isbn[3]+4*isbn[4]+5*isbn[6]+6*isbn[7]+7*isbn[8]+8*isbn[9]+9*isbn[10]-45*48;
tmp=end%11;
if(tmp==isbn[12]-48)
cout<<"Right"<<endl;
else if(tmp==10&&isbn[12]=='X')
cout<<"Right"<<endl;
else if(isbn[12]!='X'&&tmp==10)
cout<<isbn[0]<<isbn[1]<<isbn[2]<<isbn[3]<<isbn[4]<<isbn[5]<<isbn[6]<<isbn[7]<<isbn[8]<<isbn[9]<<isbn[10]<<isbn[11]<<"X";
else
cout<<isbn[0]<<isbn[1]<<isbn[2]<<isbn[3]<<isbn[4]<<isbn[5]<<isbn[6]<<isbn[7]<<isbn[8]<<isbn[9]<<isbn[10]<<isbn[11]<<tmp;
//system("pause");
return 0;
}
//0-670-82162-4

超级大水题！！
#include<iostream>
#include <cstring>
#include <cstdlib>

using namespace std;

bool func(string &a)
{
string ans = a;
ans.erase(ans.begin() + 1);
ans.erase(ans.begin() + 4);
ans.erase(ans.begin() + 9);
int sum = 0;
for(int i = 0; i < ans.length() - 1; ++i)
{
sum += (ans.c_str()[i] - '0') * (i + 1);
}
sum %= 11;
if(sum == 10 && ans.c_str()[ans.length() - 1] == 'X')
return true;
if(sum == ans.c_str()[ans.length() - 1] - '0')
return true;
else
{
a.erase(a.end() - 1);
if(sum == 10)
a += 'X';
else
a += sum + '0';
return false;
}
}
int main()
{
string a;
std::cin>>a;
if(func(a))
std::cout<<"Right";
else
std::cout<<a;
return 0;
}

var a,b,i,j:longint; n:int64;
x:string;
begin
read(x);
j:=0;
for i:=1 to 11 do
if (i<>2)and(i<>6) then
begin
j:=j+1;
n:=(ord(x[i])-48)*j+n;
end;
a:=n mod 11;
if (ord(x[13])-48=a) or(ord(x[13])-78=a) then begin writeln('Right'); halt; end
else begin
if a=10 then begin for i:=1 to 12 do write(x[i]);write('X') end
else begin for i:=1 to 12 do write(x[i]);write(a); end; end;
end.
要注意大写

水翻天的题目，纯模拟就过，全程序没有一个for循环，求虐！
#include <iostream>
#include <string>
#include <cstdio>
using namespace std;
string s;
unsigned int total,i;
int main(){
cin>>s;
total=((s[0]-'0')+(s[2]-'0')*2+(s[3]-'0')*3+(s[4]-'0')*4+(s[6]-'0')*5+(s[7]-'0')*6+(s[8]-'0')*7+(s[9]-'0')*8+(s[10]-'0')*9)%11;
if(total==10)
{if(s[12]=='X')printf("Right");
else {s[12]='X';cout<<s;}
}
else{
if((s[12]-'0')==total)printf("Right");
else {s[12]=total+'0';cout<<s;}
}
return 0;
}

#include<cstdio>
main(){
int i,j=1,s=0;char a[13];
for(i=0;i<12;i++){scanf("%c",&a[i]);if(a[i]!='-'){s=s+(a[i]-48)*j;j++;}}
s=s%11;
scanf("%c",&a[12]);
if(s==a[12]-48)printf("Right");
else if((s==10)&&(a[12]=='X'))printf("Right");
else{for(i=0;i<12;i++)printf("%c",a[i]);
if(s==10)printf("X");else printf("%d\n",s);}
}