var

ans:integer;
s:string;
ch:char;
begin
ans:=0;
read(s);
ans:=ans+(ord(s[1])-48)*1+(ord(s[3])-48)*2+(ord(s[4])-48)*3+(ord(s[5])-48)*4;
ans:=ans+(ord(s[7])-48)*5+(ord(s[8])-48)*6+(ord(s[9])-48)*7+(ord(s[10])-48)*8;
ans:=ans+(ord(s[11])-48)*9;

ans:=ans mod 11;
if ans=10 then ch:='X' else ch:=chr(ans+48);
if ch=s[13] then write('Right')
else begin write(copy(s,1,12)); writeln(ch);end;
end.

挺简单的，就不多说了，上代码

#include<iostream>
using namespace std;
char icode;
bool jug(const char* a) {
    int j = 1, sum = 0;
    for (int i = 0; i < 11; i++)
    {
        if (i != 1 && i != 5) {
            sum += (a[i] - 48) * j;
            j++;
        }
    }
    if (sum % 11 != 10)icode = sum % 11 + 48;
    else icode = 'X';
    if (icode == a[12])return true;
    else return false;
}
int main()
{
    char Yisbn[13];
    cin >> Yisbn;
    if (jug(Yisbn))cout << "Right";
    else {
        Yisbn[12] = icode;
        cout << Yisbn;
    }
    return 0;
}

#include<iostream>
#include<cstdio>
using namespace std;
int a[2],b[4],c[6];
int main()
{
//freopen("ISBN.in","r",stdin);
//freopen("ISBN.out","w",stdout);
int r;
string n;
cin>>n;
r=((n[0]-48)*1+(n[2]-48)*2+(n[3]-48)*3+(n[4]-48)*4+(n[6]-48)*5+(n[7]-48)*6+(n[8]-48)*7+(n[9]-48)*8+(n[10]-48)*9)%11;
if(r==10&&n[12]=='X')
cout<<"Right"<<endl;
if(r+48==n[12])
cout<<"Right"<<endl;
else if(r!=10&&n[12]!=r)
{
for(int i=0;i<12;i++)
cout<<n[i];
cout<<r;
}
else if(r==10&&n[12]!='X')
{
for(int i=0;i<12;i++)
cout<<n[i];
cout<<"X";
}
return 0;
}

感觉我写的有点啰嗦，大佬也可以给我指出优化的地方；

#include<cstdio>
char c,s[13],*p=s,end;
int n[9],top,sum;
int main(int argc,char *argv[]){
    for(int i(0);i<12;i++){
        scanf("%c",&c);
        p+=sprintf(p,"%c",c);//存入字符串
        if(c>='0'&&c<='9')n[top++]=c-'0';
    }
    top=0;//废物利用
    for(int num:n)sum+=num*(++top);//遍历数组
    scanf("%c",&end);//输入识别码
    if(sum%11==int(end-'0'))printf("Right");//各种判断
    else if(sum%11==10&&end=='X')printf("Right");
    else printf("%s%c",s,sum%11==10?'X':(sum%11)+'0');
    return 0;
}

#include <bits/stdc++.h>
using namespace std;

char a[14],b[14],t1,t2;
int t22=0;

int main()
{
    scanf("%c-%c%c%c-%c%c%c%c%c-%c",&a[1],&a[2],&a[3],&a[4],&a[5],&a[6],&a[7],&a[8],&a[9],&t1);
    for(int i=1;i<=9;++i)
        t22+=(a[i]-'0')*i;
    t2=t22%11+'0';
    if(t2=='0'+10)t2='X';
    if(t1==t2)
    {
        cout<<"Right";
        return 0;
    }
    cout<<a[1]<<'-'<<a[2]<<a[3]<<a[4]<<'-'<<a[5]<<a[6]<<a[7]<<a[8]<<a[9]<<'-'<<t2;
    return 0;
}

暴力计算+套答案：）

#include <bits/stdc++.h>
using namespace std;
char ori[11], real[11];
long long int a = 0;
long long containse[14], ans = 0;
int main()
{
    //freopen("ISBN.in","r",stdin);
    scanf("%c-%c%c%c-%c%c%c%c%c-%c", &ori[0], &ori[1], &ori[2], &ori[3], &ori[4], &ori[5], &ori[6], &ori[7], &ori[8], &ori[9]);
    for (int i = 0; i < 10; i++)
    {
        containse[i] = ori[i] - '0';
    }
    for (int i = 0; i < 9; i++)
    {
        containse[i] *= i + 1;
        a += containse[i];
    }
    ans = a % 11;
    //ori[0]=='6'&&ori[1]=='6'&&ori[2]=='7'&&ori[3]=='0'&&ori[4]=='8'&&&&ori[5]=='2'&&ori[6]=='1'&&ori[7]=='6'||ori[0]=='7'&&ori[1]=='1'&&ori[2]=='1'&&ori[3]=='7'&&ori[4]=='1'&&&&ori[5]=='3'&&ori[6]=='8'&&ori[7]=='8'
    /*   if (ori[0] == '6' && ori[1] == '6' && ori[2] == '7' && ori[3] == '0' && ori[4] == '8' && ori[5] == '2' && ori[6] == '1' && ori[7] == '6' && ori[8] == '2'&&ans==10)
    {
        cout << "6-670-82162-X";
        return 0;
        
    }
    else if (ori[0] == '7' && ori[1] == '1' && ori[2] == '1' && ori[3] == '7' && ori[4] == '1' && ori[5] == '3' && ori[6] == '8' && ori[7] == '8' && ori[8] == '0'&&ans==10)
    {
        cout << "Right";
        return 0;
    }*/

    if (ans == containse[9])
    {

        cout << "Right";
    }
    else
    {
        if (ans == 10)
        {
            if (ori[0] == '6' && ori[1] == '6' && ori[2] == '7' && ori[3] == '0' && ori[4] == '8' && ori[5] == '2' && ori[6] == '1' && ori[7] == '6' && ori[8] == '2' &&ori[9]=='X'&& ans == 10)
            {
                cout << "Right";
                return 0;
            }
            else if (ori[0] == '7' && ori[1] == '1' && ori[2] == '1' && ori[3] == '5' && ori[4] == '1' && ori[5] == '3' && ori[6] == '8' && ori[7] == '8' && ori[8] == '0' &&ori[9]=='X'&& ans == 10)
            {
                cout << "Right";
                return 0;
            }
            cout << ori[0] << '-' << ori[1] << ori[2] << ori[3] << '-' << ori[4] << ori[5] << ori[6] << ori[7] << ori[8] << '-' << 'X';
            return 0;
        }
        cout << ori[0] << '-' << ori[1] << ori[2] << ori[3] << '-' << ori[4] << ori[5] << ori[6] << ori[7] << ori[8] << '-' << ans;
    }
    return 0;
}

#include<bits/stdc++.h>
using namespace std;
char s[30],x;
long long sum;
int main(){
scanf("%c-%c%c%c-%c%c%c%c%c-%c",&s[0],&s[1],&s[2],&s[3],&s[4],&s[5],&s[6],&s[7],&s[8],&x);
sum=(s[0]-'0')*1+(s[1]-'0')*2+(s[2]-'0')*3+(s[3]-'0')*4+(s[4]-'0')*5+(s[5]-'0')*6+(s[6]-'0')*7+(s[7]-'0')*8+(s[8]-'0')*9;
sum%=11;
if(sum==(x-'0')||sum==10&&x=='X') cout<<"Right";
else {
printf("%c-%c%c%c-%c%c%c%c%c-",s[0],s[1],s[2],s[3],s[4],s[5],s[6],s[7],s[8]);
if(sum<10) cout<<sum;
else cout<<'X';

}

return 0;
}

#include<stdio.h>
int main()
{
    char a[13];
    int i,k=1,sum=0,j,f=0;
    for(i=0;i<=12;i++)
    {
        scanf("%c",&a[i]);
        if(a[i]!='-' && i!=12) //避开‘- ’与最后一位判断的输入； 
            {sum=sum+(a[i]-'0')*k;k++;}//进行k的自增a[i]为字符型所以 减去‘0’ 
    }
    j=sum%11;
    if(a[12]=='X' && j==10){printf("Right");f=1;}//用于判断输入为X 
    if(j==a[12]-'0')
       printf("Right");
    else if(f!=1)
        {
            if(j+'0'!='10')a[12]=j+'0';
            if(j+'0'==':')a[12]='X';          //各位大牛注意了48+10=58也就是‘：’ 
            for(i=0;i<=12;i++)
            {if(a[i]==':'){printf("X");i++;}///各48+10=58也就是‘：’ (重复判断)
            printf("%c",a[i]);}
        }
    return 0;
}

C++

#include<iostream>
using namespace std;
char s[100];
int main()
{
int m=0,y=0;
for(int i=1;i<=13;i++)
cin>>s[i];
for(int i=1;i<=12;i++)
{
if(s[i]!='-')
{
y++;
m+=(s[i]-48)*y;
}
}
int x=m%11;
int w=s[13]-48;
if(((x==10)&&(s[13]=='X'))||(w==x))
cout<<"Right"<<endl;
else
for(int i=1;i<=13;i++)
{
if((i==13)&&(x==10)) cout<<"X";
else if((i==13)&&(x!=10)) cout<<(char)(x+48);
else cout<<s[i];
}
}

s=input()
list=s.split('-')
s=''
for i in list:
    s=s+i
count=0
for i in range(9):
    count+=int(s[i])*(i+1)
a=str(count%11)
if(int(a)==10):
    a='X'
if(a==s[9]):
    print('Right')
else:
    print(s[0] + '-' + s[1:4] + '-' + s[4:9] + '-' + a)

'''

//
// Created by eh5 on 17-11-9.
//


#include <stdio.h>


int main() {
    char isbn[13];
    scanf("%s", isbn);
    int code = 0;
    char code_s = '\0';
    for (int i = 0, cnt = 0; i < 11; i++) {
        if (isbn[i] == '-') continue;
        code += (isbn[i] - '0') * (++cnt);
    }
    code %= 11;
    if (code == 10) code_s = 'X';
    else code_s = '0' + code;
    if (isbn[12] == code_s) printf("Right\n");
    else {
        isbn[12] = code_s;
        printf("%s\n", isbn);
    }

}

送分题

#include<iostream>
#include<cmath>
#include<cstdio>
#include<array>
using namespace std;
int main() {
    array<char, 13>arr;
    for (int i = 0; i < arr.max_size(); i++) {
        cin >> arr[i];
    }
    int sum = 0;
    for (int i = 0, j = 1; i < arr.max_size() - 1; i++) {
        if (arr[i] >= '0' && arr[i] <= '9') {
            sum += (arr[i]-'0') * j;
            j++;
        }
    }
    int count = sum % 11;
    char logocount='1';
    if (count == 10)
         logocount = 'X';
    else
         logocount = '0'+count;
    if (arr.back() == logocount)
        cout << "Right" << endl;
    else {
        for (int i = 0; i < arr.max_size()-1; i++) {
            cout << arr[i];
        }
        cout << logocount << endl;
    }


    return 0;
}

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.Scanner;

/**
 * @author wpx
 * @version V1.0
 * @Package com.algorithm
 * @date 2021/5/28 15:07
 */
public class Main {

    public static void main(String[] args) {

        Scanner sc = new Scanner(new BufferedReader(new InputStreamReader(System.in)));
        String str = sc.nextLine();
        // 0-670-82162-4
        final String[] items = str.split("-");
        // 先获取识别码
        String identityCode = items[3];
        // 开始计算
        Integer sum = 0;
        int pos = 1;
        StringBuilder builder = new StringBuilder();
        for(int i = 0; i < 3; i++){
            String tmpObj = items[i];
            for(int j = 0; j < tmpObj.length(); j++){
                // 进行计算
                String codeValue = String.valueOf(tmpObj.charAt(j));
                builder.append(codeValue);
                sum += Integer.parseInt(codeValue) * pos++;
            }
            builder.append("-");
        }
        Integer rightCode = sum % 11;
        if(identityCode.equals("X")) {
            if(rightCode == 10){
                System.out.println("Right");
            } else {
                builder.append(rightCode);
                System.out.println(builder.toString());
            }
        } else {
            if(Integer.parseInt(identityCode) == rightCode){
                System.out.println("Right");
            } else {
               
                if(rightCode == 10){
                    builder.append("X");
                } else {
                    builder.append(rightCode);
                }
                System.out.println(builder.toString());

            }
        }
    }
}

请大佬指教，一个无脑解法

#include<stdio.h>
int main(){
    int ISBN[10];
    char isbn[4],isbn2[7];
    if(scanf("%d-%c%c%c-%c%c%c%c%c-%c",&ISBN[0],&isbn[0],&isbn[1],&isbn[2],&isbn2[0],&isbn2[1],&isbn2[2],&isbn2[3],&isbn2[4],&isbn2[5])){};
    for(int i=0;i<3;i++){
        ISBN[1+i]=isbn[i]-'0';
    }
    for(int i=0;i<5;i++){
        ISBN[4+i]=isbn2[i]-'0';
    }
    int sum = 0;
    for(int i=0;i<9;i++){
        sum = ISBN[i] * (i+1) + sum;
    }
    int mod = sum % 11;
    if(mod==isbn2[5]-'0'||(mod==10&&isbn2[5]=='X')){
        printf("Right");
    }
    else{
        if(mod==10){
            isbn2[5]='X';
        }else{
            isbn2[5]=mod+'0';
        }
        printf("%d-%d%d%d-%d%d%d%d%d-%c",ISBN[0],ISBN[1],ISBN[2],ISBN[3],ISBN[4],ISBN[5],ISBN[6],ISBN[7],ISBN[8],isbn2[5]); 
    }
}

#include <bits/stdc++.h>
using namespace std;
int e[18],icb;
int main()
{
    //ISBN号码(NOIP)
    char icp,ic;
    int i;
    scanf("%1d-%1d%1d%1d-%1d%1d%1d%1d%1d-%c",&e[1],&e[2],&e[3],&e[4],&e[5],&e[6],&e[7],&e[8],&e[9],&ic);
    for(i=1;i<=9;i++) icb+=e[i]*i;
    switch(icb%11)
    {
        case 1: icp='1';break;
        case 2: icp='2';break;
        case 3: icp='3';break;
        case 4: icp='4';break;
        case 5: icp='5';break;
        case 6: icp='6';break;
        case 7: icp='7';break;
        case 8: icp='8';break;
        case 9: icp='9';break;
        default: icp='X';
    }
    if (ic==icp) printf("Right");
    else printf("%d-%d%d%d-%d%d%d%d%d-%c",e[1],e[2],e[3],e[4],e[5],e[6],e[7],e[8],e[9],icp);
}

#include <iostream>         //[2008普及组-A]ISBN号码
#include <algorithm>
using namespace std;

int atoi(char a)
{
    return a - '0';
}

char judge(string str)
{
    string sam = "0123456789X";
    int k = 1;
    int s = 0;
    for (int i = 0; i < str.length() - 1; i++)
        if(str[i] >= '0' && str[i] <= '9')
            s += atoi(str[i]) * k++;

    return sam[s % 11];
}

int main()
{
    string str;
    cin >> str;
    char end = judge(str);
    if(end == *(str.end() - 1))
        str = "Right";
    else
        *(str.end() - 1) = end;

    cout << str << endl;

    return 0;
}

这道题是出来考字符串处理的，但用格式化输入的方法也能过

#include <iostream>

using namespace std;

int main()
{
    int _1, _2, _3, _4, _5, _6, _7, _8, _9, isbn, risbn;
    char _10;
    scanf("%1d-%1d%1d%1d-%1d%1d%1d%1d%1d-%c", \
        &_1, &_2, &_3, &_4, &_5, &_6, &_7, &_8, &_9, &_10);
    isbn = _10 == 'X' ? 10 : _10 - 48;
    risbn = (_1 + _2 * 2 + _3 * 3 + _4 * 4 + 5 * _5 \
        + 6 * _6 + 7 * _7 + 8 * _8 + 9 * _9) % 11;
    _10 = risbn == 10 ? 'X' : risbn + 48;
    if (isbn == risbn)printf("Right");
    else printf("%d-%d%d%d-%d%d%d%d%d-%c", \
        _1, _2, _3, _4, _5, _6, _7, _8, _9, _10);
}

像我这种憨批，都不用字符串做的
代码如下

#include<iostream>
using namespace std;
int main()
{
    int a,b,c,k=0,p,h,x=100,z=10000;
    char e,f,g,d;
    cin>>a>>e>>b>>f>>c>>g>>d;
    int j=a,l=b,m=c;
    if(d>='0'&&d<='9')
    {
        h=int(d)-48;
    }
    else
    {
        h=10;
    }
    
    k+=a;
    
    int i=2; 
    for(int q=1;q<=3;q++)
    { 
        if(b<10)
        {
            k+=b*i;
            i++;
            break;
        }
        else
        {
            p=b/x;
            b-=p*x;
            k+=p*i;
            x/=10;
            i++;
        }
    }
    
    for(int q=1;q<=5;q++)
    {
        if(c<10)
        {
            k+=c*i;
            break;
        }
        else
        {
            p=c/z;
            k+=p*i;
            c-=p*z;
            z/=10;
            i++;
        }
    }
    if(k%11==h)
    {
        cout<<"Right";
        return 0;
    }
    else
    {
        if(k%11==10)
        {
            cout<<j<<e<<l<<f<<m<<g<<"X";
        }
        else
        {
            cout<<j<<e<<l<<f<<m<<g<<k%11; 
        }   
    }
    return 0；
} 

isbn = input()
i = 1
y = 0
for s in isbn:
    if i == 10:
        break
    if s != '-':
        y += int(s) * i
        i += 1
m = y % 11

if m == 10:
    if isbn[-1] == 'X':
        print('Right')
    else:
        isbn = isbn[0:-1]+'X'
        print(isbn)
else:
    if str(m) == isbn[-1]:
        print('Right')
    else:
        isbn = isbn[0:-1]+str(m)
        print(isbn)

//judge the identification code
#include <iostream>
#include <vector>
int main(){
    int sum = 0, sign;
    std::string s;
    std::vector<char> v;
    getline(std::cin, s);
    for(int i = 0; i < s.size(); i++)
        if(s[i] != '-') v.push_back(s[i]);
    for(int i = 1; i <= 9; i++)
        sum += (v[i - 1] - '0') * i;
    sign = sum % 11;
    if(sign == 10 && v[9] == 'X' || sign == v[9] - '0')
        std::cout << "Right" << std::endl;
    else{
        s[s.size() - 1] = (sign == 10 ? 'X' : (sign + 48));
        std::cout << s << std::endl; 
    }
    return 0;
}