281 条题解
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0
zyxbcde LV 7 @ 2017-10-24 20:54:11
ss=raw_input() s=ss.replace("-","") ans=0 for i in range(9): ans+=int(s[i])*(i+1) ans=ans%11 if ans==10: sol="X" else: sol=ans if str(sol)==s[9]: print "Right" else: print ss[:12]+str(sol)送的
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0
#include<stdio.h>
char a[25];
int main()
{
int s=0,j=1;
scanf("%s",&a);
for(int i=0;i<=10;i++)
{
if (a[i]=='-');
else
{
s=s+(a[i]-48)*j;j++;
}
}
s=s%11;
if((s==10)&&(a[12]=='X')||(s==a[12]-48))
printf("Right\n") ;
else
{
if (s==10)
a[12]='X';
else a[12]=s+48;
printf("%s",a);
}
return 0;
} -
0
#include<iostream>
#include<cstdio>
#include<string>
using namespace std;
int in[14];
int main()
{
int a,b,c,sum;
char e,f,g,d;
cin>>a>>e>>b>>f>>c>>g>>d;
sum=(a*1+b/100*2+b/10%10*3+b%10*4+c/10000*5+c/1000%10*6+c/100%10*7+c/10%10*8+c%10*9)%11;
if(sum==d-48) {cout<<"Right";return 0;}
if((sum==10&&d=='X')){
cout<<"Right";return 0;}
if(sum!=10)
cout<<a<<e<<b<<f<<c<<g<<sum;
if(sum==10)
cout<<a<<e<<b<<f<<c<<g<<"X";
return 0;
} -
0
#include<iostream>
#include<string>
#include<cctype>
using namespace std;
int main() {
string str;
cin >> str;
int key = 0;
int m = 0;
for (int i = 0; i < 11; i++)
{
if (isdigit(str[i]))
{
m++;
key += (str[i] - '0') * (m);
}
}
if (key % 11 == 10)
{
if (str[12] == 'X')
cout << "Right" << endl;
else {
str[12] = 'X';
cout << str << endl;
}
}
else
{
if (str[12] - '0' == key % 11)
cout << "Right" << endl;
else
{
str[12] = key % 11 + '0';
cout << str << endl;
}
}
return 0;
} -
0
str1 = input() dt = {1:'1',2:'2',3:'3',4:'4',5:'5',6:'6',7:'7',8:'9',9:'9',10:'X'} numlst = [str1[0],str1[2],str1[3],str1[4],str1[6],str1[7],str1[8],str1[9],str1[10]] numlst1 = list(map(int,numlst)) ids = numlst1[0] + numlst1[1] * 2 +numlst1[2] * 3 +numlst1[3] * 4 +numlst1[4] * 5 +numlst1[5] * 6 +numlst1[6] * 7 +numlst1[7] * 8 +numlst1[8] * 9 ids = ids%11 if dt[ids] == str1[-1]: print('Right') else: print(str1[:-1]+dt[ids]) -
0
//锻炼细心。。。。 #include <iostream> #include <string> #define s ISBN using namespace std; string ISBN; inline int todig(char c) { if (c != 'X')return c - '0'; return 10; } inline char tochar() { if ((todig(s[0]) + todig(s[2]) * 2 + todig(s[3]) * 3 + todig(s[4]) * 4 + todig(s[6]) * 5 + todig(s[7]) * 6 + todig(s[8]) * 7 + todig(s[9]) * 8 + todig(s[10]) * 9) % 11 != 10)return (todig(s[0]) + todig(s[2]) * 2 + todig(s[3]) * 3 + todig(s[4]) * 4 + todig(s[6]) * 5 + todig(s[7]) * 6 + todig(s[8]) * 7 + todig(s[9]) * 8 + todig(s[10]) * 9) % 11 + '0'; return 'X';} int main() { cin >> s; if ((todig(s[0]) + todig(s[2]) * 2 + todig(s[3]) * 3 + todig(s[4]) * 4 + todig(s[6]) * 5 + todig(s[7]) * 6 + todig(s[8]) * 7 + todig(s[9]) * 8 + todig(s[10]) * 9) % 11 == todig(s[12])) cout << "Right" << endl; else cout << s.substr(0, 12) << tochar() << endl; return 0; } -
0
#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int main()
{
int i,sum=0,ans,a10;
char a[11],bin1,bin2,bin3,ch;
cin>>a[1]>>bin1>>a[2]>>a[3]>>a[4]>>bin2>>a[5]>>a[6]>>a[7]>>a[8]>>a[9]>>bin3>>a[10];
for(i=1;i<=9;i++)
{
sum+=(a[i]-'0')*i;
}
a10=sum%11;
if(a10<=9)
{
ch=a10+'0';
if(ch==a[10]) cout<<"Right";
else cout<<a[1]<<bin1<<a[2]<<a[3]<<a[4]<<bin2<<a[5]<<a[6]<<a[7]<<a[8]<<a[9]<<bin3<<ch;
}
else
{
ch=a10+'N';
if(ch==a[10]) cout<<"Right";
else cout<<a[1]<<bin1<<a[2]<<a[3]<<a[4]<<bin2<<a[5]<<a[6]<<a[7]<<a[8]<<a[9]<<bin3<<ch;
}
} -
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//isbn号码
#include<stdio.h>
#include<ctype.h>
#include<string.h>
char isbn[13];
int main(){
int sum=0,rec=0;
scanf("%s",isbn);
for(int i=0,j=1;i<12;i++){
if(isdigit(isbn[i])){
sum+=(isbn[i]-'0')*j;
j++;
}
}
rec=sum%11;
if(rec!=10)
{
if(rec==isbn[12]-'0')
{
printf("Right");
}
if(rec!=isbn[12]-'0')
{
isbn[12]=rec+'0';
for(int i=0;i<13;i++)
{
printf("%c",isbn[i]);
}
}
}
/*if(isbn[12]=='X'){
if(sum%11==10)
printf("Right");
else
printf("%c-%c%c%c-%c%c%c%c%c-%d",isbn[0],isbn[2],isbn[3],isbn[4],isbn[6],isbn[7],isbn[8],isbn[9],isbn[10],rec);
}if(isbn[12]-'0'==rec){
printf("Right");
}
else if(rec!=10)
printf("%c-%c%c%c-%c%c%c%c%c-%d",isbn[0],isbn[2],isbn[3],isbn[4],isbn[6],isbn[7],isbn[8],isbn[9],isbn[10],rec);
else
printf("%c-%c%c%c-%c%c%c%c%c-X",isbn[0],isbn[2],isbn[3],isbn[4],isbn[6],isbn[7],isbn[8],isbn[9],isbn[10]);
*/
if(rec==10)
{
if(isbn[12]=='X')
{
printf("Right");
}
if(isbn[12]!='X')
{
isbn[12]='X';
for(int i=0;i<13;i++)
{
printf("%c",isbn[i]);
}
}
}
return 0;
} -
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#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <cstring>
#include <algorithm>
using namespace std;int main(){
int i,All=0,j;
char a[12];
gets(a);
for(i=0,j=1;i<=10;i++,j++)
{
if(i==1||i==5)
i++;
All=(a[i]-48)*j+All;
}
All=All%11;
if(All==10)
{
if(a[12]=='X')
printf("Right");
else
{
for(i=0;i<=11;i++)
printf("%c",a[i]);
printf("X");
}
}
else
{
if(a[12]-48==All)
printf("Right");
else
{
for(i=0;i<=11;i++)
printf("%c",a[i]);
printf("%d",All);
}
}
return 0;
} -
0
丧心病狂
#include<iostream> using namespace std; int num[10]; char c; int main() { cin>>c; num[0]=c-'0'; cin>>c; cin>>c; num[1]=c-'0'; cin>>c; num[2]=c-'0'; cin>>c; num[3]=c-'0'; cin>>c; cin>>c; num[4]=c-'0'; cin>>c; num[5]=c-'0'; cin>>c; num[6]=c-'0'; cin>>c; num[7]=c-'0'; cin>>c; num[8]=c-'0'; cin>>c; cin>>c; if(c=='X') num[9]=10; else num[9]=c-'0'; if((num[0]+2*num[1]+3*num[2]+4*num[3]+5*num[4]+6*num[5]+7*num[6]+8*num[7]+9*num[8])%11==num[9]) cout<<"Right"; else { num[9]=(num[0]+2*num[1]+3*num[2]+4*num[3]+5*num[4]+6*num[5]+7*num[6]+8*num[7]+9*num[8])%11; cout<<num[0]<<"-"<<num[1]<<num[2]<<num[3]<<"-"<<num[4]<<num[5]<<num[6]<<num[7]<<num[8]<<'-'; if(num[9]==10) cout<<"X"; else cout<<num[9]; } return 0; } -
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pascal 暴力解决..
var s:string;x,n,i:integer; begin read(s); for i:=1 to 3 do begin x:=pos('-',s); delete(s,x,1); end; x:=0;n:=0; for i:= 1 to 9 do begin val(s[i],x); n:=x*i+n; end; n:=n mod 11; if (n=10)and(s[10]='X') then write('Right'); if (n=10)and(s[10]<>'X')then write(s[1],'-',s[2],s[3],s[4],'-',s[5],s[6],s[7],s[8],s[9],'-','X'); if n<>10 then begin val(s[10],x); if x=n then write('Right') else write(s[1],'-',s[2],s[3],s[4],'-',s[5],s[6],s[7],s[8],s[9],'-',n); end; end . -
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#include <stdio.h> int main(int argc, char const *argv[]) { int num1, num2; char num4; long int num3; scanf("%d-%d-%ld-%c", &num1, &num2, &num3, &num4); int s; if (num4 == 'X') { s = 10; } else { s = num4 - '0'; } int sum = num1 * 1 + num2 / 100 * 2 + num2 / 10 % 10 * 3 + num2 % 10 * 4; sum += (num3/10000)*5 + (num3/1000%10)*6 + (num3/100%10)*7 + (num3%100/10)*8 + (num3%10)*9; if (sum%11 == s) { printf("Right"); } else { printf("%d-%03d-%05ld-", num1, num2, num3); if (sum % 11 == 10) { printf("X"); } else { printf("%d", sum % 11); } } return 0; } -
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#include<iostream>
using namespace std;
int main() {
char a[13];
int i, sum=0, b,d=1;
for (i = 0; i < 13; i++)
cin >> a[i];
for (i = 0; i < 11; i++){
if (a[i] != '-'){
sum+= (a[i] - '0')*d;
d++;
}
}
b = sum % 11;
if ((a[12] - '0') == b)
{
cout << "Right" << endl;
}
else
{
a[12] = (b + '0');
for (i = 0; i < 13; i++)
cout << a[i];
cout << endl;
}
return 0;
} -
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#include<stdio.h> #include<string.h> #include<math.h> char ISBN[20]; void judge(char isbn[]) { int n; int i = 0; int index = 0; int disnum = 0; int t = 0; n = strlen(isbn); for (i = 0; i < n-1; i++) { if (isbn[i] == '-') continue; else { index++; t = t+(isbn[i] - '0')*index; } } disnum = t % 11; if (disnum == 10) { if (isbn[n - 1] == 'X') printf("Right\n"); else { isbn[n - 1] = 'X'; printf("%s\n", isbn); } } else { if (disnum == (isbn[n - 1] - '0')) { printf("Right\n"); } else { isbn[n - 1] = disnum + '0'; printf("%s\n", isbn); } } } int main() { //freopen("data.in", "r", stdin); //freopen("data.out", "w", stdout); scanf("%s", ISBN); judge(ISBN); return 0; } -
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难点在于字符串的分割和拼接以及char和int的转换
#include<iostream> #include<string> #include<cstring> #include<sstream> std::string init(); std::string compute(std::string str); int main() { // using namespace std; string test = init(); cout << compute(test) << endl; return 0; } std::string init() { using namespace std; string str; cin >> str; char *temp = new char[str.size()]; for(int i = 0;i < str.size();i++) { temp[i] = str[i]; } string *result = new string[4]; result[0] = strtok(temp, "-"); result[1] = strtok(NULL, "-"); result[2] = strtok(NULL, "-"); result[3] = strtok(NULL, "-"); return result[0] + result[1] + result[2] + result[3]; } std::string compute(std::string str) { using namespace std; int temp = 0; for(int i = 0;i < 9;i++) { temp += ((int)(str[i]) - (int)('0')) * (i+1); } if(temp % 11 == 10) { if(str[9] == 'X') { return "Right"; }else { string result = str; result.insert(1, "-"); result.insert(5, "-"); result.insert(11, "-"); result.replace(12, 1, "X"); return result; } }else { if((int)(str[9] - '0') == temp % 11) { return "Right"; }else { string result = str; result.insert(1, "-"); result.insert(5, "-"); result.insert(11, "-"); ostringstream oss; oss << (temp % 11); result.replace(12, 1, oss.str()); return result; } } } -
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#include<iostream>
#include<string>
using namespace std;
int main(){
string ISBN,ISBN_C;
int Last_Number=0;
cin>>ISBN;
for(int i=0;i<ISBN.length();i++){
if(ISBN[i]!='-')
ISBN_C+=ISBN[i];
}
for(int i=0;i<ISBN_C.length()-1;i++){
Last_Number+=(ISBN_C[i]-48)*(i+1);
}
Last_Number%=11;
if(ISBN_C[ISBN_C.length()-1]-48==Last_Number)
cout<<"Right";
else if(ISBN_C[ISBN_C.length()-1]=='X'&&Last_Number==10)
cout<<"Right";
else {
ISBN[ISBN.length()-1]=Last_Number+48;
if(Last_Number==10)
ISBN[ISBN.length()-1]='X';
cout<<ISBN;
}
return 0;
} -
0
#include <iostream>
#include <cstdio>
#include <string.h>
#include <cmath>
using namespace std;
const int maxn = 20;
char a[maxn];
int main(){
scanf("%s",a);
int t = 1,i;
int sum = 0;
for(i=0;i<strlen(a)&&t<=9;i++){
if(a[i]<='9'&&a[i]>='0'){
sum += (a[i]-'0')*t;
t++;
}
}
i++; //跳过间隔符
sum %= 11;
if(sum != 10&&sum==(a[i])-'0'){ //识别不是X的情况
cout<<"Right"<<endl;
}else if(sum == 10&&a[i]=='X'){ //识别X
cout<<"Right"<<endl;
}else{
if(sum == 10)
a[i] = 'X';
else
a[i] = '0' + sum;
cout<<a<<endl;
}
return 0;
} -
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#include<stdio.h> int main() { char c1, c2, c3, c4, c5, c6, c7, c8, c9, c10; int n1, n2, n3, n4, n5, n6, n7, n8, n9, n10, rightn10; scanf("%c-%c%c%c-%c%c%c%c%c-%c", &c1, &c2, &c3, &c4, &c5, &c6, &c7, &c8, &c9, &c10); //需要注意这里的输入，只能通过char类型输入. n1 = c1 - '0', n2 = c2 - '0', n3 = c3 - '0', n4 = c4 - '0', n5 = c5 - '0', n6 = c6 - '0', n7 = c7 - '0', n8 = c8 - '0', n9 = c9 - '0', n10 = c10 - '0'; //转为int rightn10 = (n1 + 2 * n2 + 3 * n3 + 4 * n4 + 5 * n5 + 6 * n6 + 7 * n7 + 8 * n8 + 9 * n9) % 11; //正确的识别码 if (c10=='X') //如果识别符是X的情况 { if (rightn10 == 10) printf("Right"); else printf("%d-%d%d%d-%d%d%d%d%d-%d", n1, n2, n3, n4, n5, n6, n7, n8, n9, rightn10); } else //识别符不是X的情况，即0~9 { if (rightn10 == 10) printf("%d-%d%d%d-%d%d%d%d%d-X", n1, n2, n3, n4, n5, n6, n7, n8, n9); else if (n10 == rightn10) printf("Right"); else printf("%d-%d%d%d-%d%d%d%d%d-%d", n1, n2, n3, n4, n5, n6, n7, n8, n9, rightn10); } getchar(); getchar(); return 0; } -
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#include<iostream> #include<string> #include<cstring> using namespace std; int main(){ string isbn; int i,j=1,temp = 0; cin>>isbn; for(i = 0;i<11;i++){ if(isbn[i]!= '-'){ temp += (isbn[i] - '0')*j++; } } temp %= 11; if(temp == 10) temp = 'X'; if(temp == (isbn[12] - '0')||(temp == isbn[12])) cout<<"Right"; else{ if(temp != 'X') isbn[12] = (char)(temp+'0'); else isbn[12] = temp; cout<<isbn; } return 0; }
zyxbcde
LV 7
@ 2017-10-24 20:54:11
