#include <iostream>
#include <vector>
using namespace std;
struct stu
{
string name, lead, west;
int fin, grade, paper;
int money = 0;
};
int main()
{
int n;
cin >> n;
vector<stu> stus(n);
int max = 0;
int where = 0;
int sum = 0;
for (int i = 0; i != n; i++)
{
cin >> stus[i].name >> stus[i].fin >> stus[i].grade >> stus[i].lead >> stus[i].west >> stus[i].paper;
if (stus[i].fin > 80 && stus[i].paper != 0){
stus[i].money += 8000;}
if (stus[i].fin > 85 && stus[i].grade > 80){
stus[i].money += 4000;}
if (stus[i].fin > 90){
stus[i].money += 2000;}
if (stus[i].fin > 85 && stus[i].west == "Y"){
stus[i].money += 1000;}
if (stus[i].grade > 80 && stus[i].lead == "Y"){
stus[i].money += 850;}
sum+=stus[i].money;
}
for (int i = 0; i != n; i++)
{
if (max < stus[i].money)
{
max = stus[i].money;
where = i;
}
}
cout << stus[where].name << endl
<< stus[where].money << endl
<< sum << endl;
}

#include<iostream>
using namespace std;
struct STUDENT{
string name;
int n1,n2;
char xsgb,xb;
int lw;
int jxj;
};
int main(){
int n;
int sum=0;
cin>>n;
struct STUDENT stu[n];
struct STUDENT zdz;
zdz.jxj=0;
for(int i=0;i<n;i++)stu[i].jxj=0;
for(int i=0;i<n;i++){
cin>>stu[i].name>>stu[i].n1>>stu[i].n2>>stu[i].xsgb>>stu[i].xb>>stu[i].lw;
if(stu[i].n1>80&&stu[i].lw>=1)stu[i].jxj+=8000;
if(stu[i].n1>85&&stu[i].n2>80)stu[i].jxj+=4000;
if(stu[i].n1>90)stu[i].jxj+=2000;
if(stu[i].n1>85&&stu[i].xb=='Y')stu[i].jxj+=1000;
if(stu[i].n2>80&&stu[i].xsgb=='Y')stu[i].jxj+=850;
if(stu[i].jxj>zdz.jxj)zdz=stu[i];
sum+=stu[i].jxj;
}
cout<<zdz.name<<endl<<zdz.jxj<<endl<<sum;
return 0;

}

#include<iostream>
#include<string>
using namespace std;

int main()
{
int stdNum, averageScore, commentScore, papareNum;
string name,iscadre,iswest,maxName;
int allSum = 0, perSum = 0, maxSum = 0;
cin >> stdNum;
for (int i = 0; i < stdNum; i++)
{
cin >> name >> averageScore >> commentScore >> iscadre >> iswest >> papareNum;
if (papareNum>0&&averageScore>80) //院士奖学金
{
perSum += 8000;
}
if (averageScore>85&&commentScore>80) //五四奖学金
{
perSum += 4000;
}
if (averageScore>90) // 成绩优秀奖
{
perSum += 2000;
}
if (iswest=="Y"&&averageScore>85) // 西部奖学金
{
perSum += 1000;
}
if (iscadre=="Y"&&commentScore>80) // 班级贡献奖
{
perSum += 850;
}
if (perSum>maxSum)
{
maxSum = perSum;
maxName = name;
}
allSum += perSum;
perSum = 0;
}
cout << maxName << endl;
cout << maxSum << endl;
cout << allSum << endl;
return 0;
}

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.Scanner;

/**
 * @author wpx
 * @version V1.0
 * @Package com.algorithm
 * @date 2021/5/18 10:08
 */
public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(new BufferedReader(new InputStreamReader(System.in)));
        int studentNum = Integer.valueOf(sc.nextLine());
        int allTotalScore = 0;
        int maxScore = 0;
        String studentName = "";
        for(int i = 0; i < studentNum; i++){
            final String[] infos = sc.nextLine().split(" ");
            int avgScore = Integer.valueOf(infos[1]);
            int classScore = Integer.valueOf(infos[2]);
            boolean isStudentCadres =  "Y".equals(infos[3]) ? true : false;
            boolean isWestStudent =  "Y".equals(infos[4])  ? true : false;
            int paperNum = Integer.valueOf(infos[5]);
            // 计算总分
            int totalScore = 0;
            if(avgScore > 80 && paperNum >= 1) {
                // 院士奖学金，每人8000元，期末平均成绩高于80分（>80），并且在本学期内发表1篇或1篇以上论文的学生均可获得；
                totalScore += 8000;
            }
            if(avgScore > 85  && classScore > 80) {
                // 五四奖学金，每人4000元，期末平均成绩高于85分（>85），并且班级评议成绩高于80分（>80）的学生均可获得
                totalScore += 4000;
            }
            if(avgScore > 90) {
                // 成绩优秀奖，每人2000元，期末平均成绩高于90分（>90）的学生均可获得；
                totalScore += 2000;
            }
            if(avgScore > 85 && isWestStudent){
                // 西部奖学金，每人1000元，期末平均成绩高于85分（>85）的西部省份学生均可获得；
                totalScore += 1000;
            }
            if(classScore > 80 && isStudentCadres){
                //班级贡献奖，每人850元，班级评议成绩高于80分（>80）的学生干部均可获得
                totalScore += 850;
            }
            if(totalScore > maxScore){
                studentName = infos[0];
                maxScore = totalScore;
            }
            allTotalScore += totalScore;
        }
        System.out.println(studentName);
        System.out.println(maxScore);
        System.out.println(allTotalScore);
    }
     
}

#include<bits/stdc++.h>
using namespace std;
int main()
{
int n,score1,score2,sum=0,max=0,total=0,x,i;
char a,b;
string name,maxn;
cin>>n;
for(i=1;i<=n;i++)
{
cin>>name>>score1>>score2>>a>>b>>x;
if(score1>80 && x>0)//判断是否获得院士奖学金
sum+=8000;
if(score1>85 && score2>80)//判断是否获得五四奖学金
sum+=4000;
if(score1>90)//判断是否获得成绩优秀奖
sum+=2000;
if(score1>85 && b=='Y')//判断是否获得西部奖学金
sum+=1000;
if(score2>80 && a=='Y')//判断是否获得班级贡献奖
sum+=850;
total+=sum;//累加奖学金
if(sum>max)//找出最牛学生
maxn=name,max=sum;//sum的用处
sum=0;
}
cout<<maxn<<endl<<max<<endl<<total;
return 0;
}

。

简单的结构体问题
```c
#include <stdio.h>
struct student
{
char name[30];
int score1;
int score2;
char y1;
char y2;
int num;
}st[120];
int main()
{
int n=0;
scanf("%d",&n);
int max=0,all=0;
int who;
for(int i=0;i<n;i++)
{
scanf("%s %d %d %c %c %d",&st[i].name,&st[i].score1,&st[i].score2,&st[i].y1,&st[i].y2,&st[i].num);
int prize=0;
if (st[i].score1>80&&st[i].num>0)
prize+=8000;
if (st[i].score1>85&&st[i].score2>80)
prize+=4000;
if (st[i].score1>90)
prize+=2000;
if (st[i].score1>85&&st[i].y2=='Y')
prize+=1000;
if (st[i].score2>80&&st[i].y1=='Y')
prize+=850;

if (prize>max)
{
max=prize;
who=i;
}

all+=prize;
}
printf("%s\n%d\n%d",st[who].name,max,all);
return 0;
}
```

#include<cstdio>
#include<iostream>
#include<algorithm>
using namespace std;
struct Student
{
    string name;
    int id,aver,comm,acti,total;
    bool west,stu;
}student[105];
int cmp(Student a,Student b)
{
    if(a.total==b.total)
    return a.id<b.id;
    return a.total>b.total;
}
int main()
{
    int n;
    cin>>n;
    for(int i=1;i<=n;i++)
    {
        char isWest,isStu;
        cin>>student[i].name>>student[i].aver>>student[i].comm>>isStu>>isWest>>student[i].acti;
        student[i].stu=(isStu=='Y')?true:false;
        student[i].west=(isWest=='Y')?true:false;
        student[i].id=i;
    }
    int res=0;
    for(int i=1;i<=n;i++)
    {
        if(student[i].aver>80&&student[i].acti>=1)
        student[i].total+=8000,res+=8000;
        else;
        if(student[i].aver>85&&student[i].comm>80)
        student[i].total+=4000,res+=4000;
        else;
        if(student[i].aver>90)
        student[i].total+=2000,res+=2000;
        else;
        if(student[i].aver>85&&student[i].west)
        student[i].total+=1000,res+=1000;
        else;
        if(student[i].comm>80&&student[i].stu)
        student[i].total+=850,res+=850;
        else;
    }
    sort(student+1,student+1+n,cmp);
    cout<<student[1].name<<endl<<student[1].total<<endl<<res<<endl;
    return 0;
}

#include<bits/stdc++.h>
using namespace std;
struct student 
{
    string name;
    int qm;
    int py;
    char mas;
    char wes;
    int lw;
    int mai;
};
student a[1001];
int main() 
{
    int n;
    int addmai=0;
    int k=0;
    int maxmai=-100;
    cin>>n;
    for(int i=0; i<n; i++) 
{
        cin>>a[i].name;
        cin>>a[i].qm>>a[i].py;
        cin>>a[i].mas>>a[i].wes;
        cin>>a[i].lw;
    }
    for(int i=0; i<n; i++) 
{
        if(a[i].qm>80&&a[i].lw>=1)a[i].mai+=8000;
        if(a[i].qm>85&&a[i].py>80)a[i].mai+=4000;
        if(a[i].qm>90)a[i].mai+=2000;
        if(a[i].qm>85&&a[i].wes=='Y')a[i].mai+=1000;
        if(a[i].py>80&&a[i].mas=='Y')a[i].mai+=850;
        addmai+=a[i].mai;
        if(maxmai!=a[i].mai) 
        {
            maxmai=max(maxmai,a[i].mai);
            if(maxmai==a[i].mai)k=i;
        }
    }
    cout<<a[k].name<<endl<<maxmai<<endl<<addmai<<endl;
    return 0;
}

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n,cj1,cj2,sum=0,max=0,s=0,x,i;
    char a,b;
    string ne,maxx;
    cin>>n;
    for(i=1;i<=n;i++)
    {
        cin>>ne>>cj1>>cj2>>a>>b>>x;
        if(cj1>80 && x>0)
            sum+=8000;
        if(cj1>85 && cj2>80)
            sum+=4000;
        if(cj1>90)
            sum+=2000;
        if(cj1>85 && b=='Y')
            sum+=1000;
        if(cj2>80 && a=='Y')
            sum+=850;
        s+=sum;
        if(sum>max)
            maxx=ne,max=sum;
        sum=0;
    }
    cout<<maxx<<endl<<max<<endl<<s;
    return 0;
}

#include<iostream>
#include<algorithm>
#include<cstring>
using namespace std;
const int N = 100;
struct Student
{
    string name;
    int p;
    int y;
    char x;
    char g;
    int paper;
    int money;
};
Student cls[N+1];
int main()
{
    int n,am = 0;
    cin >> n;
    for(int i=0;i<n;i++)
    {
        cin >> cls[i].name;
        cin >> cls[i].p;
        cin >> cls[i].y;
        cin >> cls[i].g;
        cin >> cls[i].x;
        cin >> cls[i].paper;
    }
    for(int i=0;i<n;i++)
    {
        if(cls[i].p>80&&cls[i].paper>=1)
        {
            cls[i].money+=8000;
        }
        if(cls[i].p>85&&cls[i].y>80)
        {
            cls[i].money+=4000;
        }
        if(cls[i].p>90)
        {
            cls[i].money+=2000;
        }
        if(cls[i].p>85&&cls[i].x=='Y')
        {
            cls[i].money+=1000;
        }
        if(cls[i].y>80&&cls[i].g=='Y')
        {
            cls[i].money+=850;
        }
    }
    int Max=0;
    string Name;
    for(int i=0;i<n;i++)
    {
        if(Max<cls[i].money){
            Max=cls[i].money;
            Name=cls[i].name;
        }
        am+=cls[i].money;
    }
    cout << Name << endl;
    cout << Max << endl;
    cout << am;
    return 0;
}

结构体和if的简单练手题

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n,m,em,sum=0,max=0,total=0,x,i;
    char a,b;
    string name,dalao;
    cin>>n;
    for(i=1;i<=n;i++){
        cin>>name>>m>>em>>a>>b>>x;
        if(m>80 && x>0){
            sum+=8000;
        }
        if(m>85 && em>80){
            sum+=4000;
        }
        if(m>90){
            sum+=2000;
        }
        if(m>85 && b=='Y'){
            sum+=1000;
        }
        if(em>80 && a=='Y'){
            sum+=850;
        }
        total+=sum;
        if(sum>max){
            dalao=name,max=sum;
        }
        sum=0;
    }
    cout<<dalao<<endl;
    cout<<max<<endl;
    cout<<total;
}

谔谔

用结构体模拟即可
cpp
#include<iostream>
#include<string>
using namespace std;
struct student{
string a;
int o,oo,ooo;
char on,ok;
}b[100];
main()
{
int n,tmp[100]={0},max=0,sum=0,k,a,ba;
cin>>n;
for(int i=0;i<n;i++)
{
cin>>b[i].a>>b[i].o>>b[i].oo>>b[i].on>>b[i].ok>>b[i].ooo;
if(b[i].o>80&&b[i].ooo) tmp[i]+=8000;
if(b[i].o>85&&b[i].oo>80) tmp[i]+=4000;
if(b[i].o>90) tmp[i]+=2000;
if(b[i].o>85&&b[i].ok=='Y') tmp[i]+=1000;
if(b[i].oo>80&&b[i].on=='Y') tmp[i]+=850;
sum+=tmp[i];
if(tmp[i]>max)
{
max=tmp[i];
k=i;
}
}
cout<<b[k].a<<endl<<max<<endl<<sum;
return 0;
}

```

思路：暴力模拟，祝**AC**

#include <iostream>
#include <cstring>
using namespace std;

int main()
{
    /*
    没用什么高级语法，写给新手
    变量名解释
    N(题目中N)
    当前处理学生的：name(姓名),pj(平均成绩),bj(班级评议成绩),
                   gb(干部?),xb(西部省份学生?),lw(论文数),jj(奖金数)
    答案：zgjj(最高奖金),zgname(拿到最高奖金的学生姓名),zjj(总奖金)
    */
    char name[21], zgname[21], gb, xb;
    int N, pj, bj, lw, jj, zjj = 0, zgjj = 0;
    scanf("%d", &N);
    for (int i = 0; i < N; ++i)
    {
        jj = 0;
        scanf("%s %d %d %c %c %d\n", name, &pj, &bj, &gb, &xb, &lw);
        //win下模拟输入时 Ctrl+z 输入 EOF 
        if (pj > 80 && lw)          jj += 8000;
        if (pj > 85 && bj > 80)     jj += 4000;
        if (pj > 90)                jj += 2000;
        if (pj > 85 && xb == 'Y')   jj += 1000;
        if (bj > 80 && gb == 'Y')   jj += 850;
        if (jj > zgjj)              zgjj = jj, strcpy(zgname, name);
        zjj += jj;
    }
    printf("%s\n%d\n%d", zgname, zgjj, zjj);
}

#include<iostream>
#include<cmath>
#include<string>
#include<algorithm>
using namespace std;
int v[10001];
struct person
{
    string name;
    int qm,sl,py;
    int cnt;
    char b,c;
};
struct person a[10001];
int main()
{
    int i,n,j;
    long long sum=0;
    cin>>n;
    for(i=1;i<=n;i++)
    {
        cin>>a[i].name>>a[i].qm>>a[i].py>>a[i].b>>a[i].c>>a[i].sl;
        v[i]=i;
        a[i].cnt=0;
    }
    for(i=1;i<=n;i++)
    {
        if(a[i].qm>80 and a[i].sl>=1) a[i].cnt+=8000;
        if(a[i].qm>85 and a[i].py>80) a[i].cnt+=4000;
        if(a[i].qm>90) a[i].cnt+=2000;
        if(a[i].qm>85 and a[i].c=='Y') a[i].cnt+=1000;
        if(a[i].py>80 and a[i].b=='Y') a[i].cnt+=850;
    }
    for(i=1;i<=n;i++)
        sum+=a[i].cnt;
    for(i=1;i<n;i++)
    {
        for(j=i+1;j<=n;j++)
        {
            if(a[i].cnt<a[j].cnt)
                swap(a[i],a[j]);
            if(a[i].cnt==a[j].cnt and v[i]>v[j])
                swap(a[i],a[j]);
        }
    }
    cout<<a[1].name<<endl;
    cout<<a[1].cnt<<endl;
    cout<<sum;
    return 0;
}

#include <stdio.h>
#include <iostream>
#include <algorithm>
using namespace std;
struct stu {
    int id;
    char name[100];
    int qm,py;
    char gb,xb;
    int lw,jj;
}a[110];
int jxj (int qm,int py,char gb,char xb,int lw) {
    int jj=0;
    if (qm>80&&lw>=1) jj+=8000;
    if (qm>85&&py>80) jj+=4000;
    if (qm>90) jj+=2000;
    if (qm>85&&xb=='Y') jj+=1000;
    if (py>80&&gb=='Y') jj+=850;
    return jj;
}
bool operator <(const stu &p1,const stu &p2) {
    if (p1.jj!=p2.jj) return p1.jj<p2.jj;
    return p1.id>p2.id; 
}
int main () {
    int n,i,zq=0;
    scanf ("%d",&n);
    for (i=0;i<n;i++) {
        scanf ("%s%d%d %c %c%d",
        a[i].name,&a[i].qm,&a[i].py,&a[i].gb,&a[i].xb,&a[i].lw);
        a[i].jj=jxj(a[i].qm,a[i].py,a[i].gb,a[i].xb,a[i].lw);
        a[i].id=i+1;
        zq+=a[i].jj;
    }
    sort (a,a+n);
    printf ("%s\n",a[i-1].name);
    printf ("%d\n",a[i-1].jj);
    printf ("%d",zq);
    return 0;
}

some_stu = []
money_max = 0
money_count = 0
money_name = '0'
for i in range(int(input())):
    some_stu.append((input().split()))
for item in some_stu:
    money = 0
    money += 8000 if int(item[1]) > 80 and int(item[5]) >= 1 else 0
    money += 4000 if int(item[1]) > 85 and int(item[2]) > 80 else 0
    money += 2000 if int(item[1]) > 90 else 0
    money += 1000 if int(item[1]) > 80 and item[4] == 'Y' else 0
    money += 850 if int(item[2]) > 80 and item[3] == 'Y' else 0
    money_count += money
    if money > money_max:
        money_name = item[0]
        money_max = money
print(money_name)
print(money_max)
print(money_count)

python 不知道错哪了

这里用到了结构数组动态分配内存大家可以看看
#include<iostream>
#include<string>
#include<malloc.h>
#define LEN sizeof(struct Student)
using namespace std;
struct Student{
char name[100];
int gard_exam;
int gard_evaluate;
char student_leader[1];
int nums_paper;
char student_west[1];

};

int main(){
int n;
cin >> n;
struct Student *stu=NULL;
stu = (struct Student *)malloc(sizeof(struct Student)*n);
for (int i = 0; i < n; i++){
cin >> stu[i].name >> stu[i].gard_exam >> stu[i].gard_evaluate >> stu[i].student_leader >> stu[i].student_west >> stu[i].nums_paper;
}
int sum_grad=0;
int max_grad = 0;
string name_cout;
for (int i = 0; i < n; i++){
int t_grad = 0;
if (stu[i].gard_exam > 80 && stu[i].nums_paper >= 1){
t_grad += 8000;
}
if (stu[i].gard_exam > 85 && stu[i].gard_evaluate > 80){
t_grad += 4000;
}
if (stu[i].gard_exam > 90){
t_grad += 2000;
}
if (stu[i].gard_exam > 85 && stu[i].student_west[0]=='Y'){
t_grad += 1000;
}
if (stu[i].gard_exam > 80 && stu[i].student_leader[0] == 'Y'){
t_grad += 850;
}
sum_grad = sum_grad+t_grad;
if (max_grad < t_grad){
max_grad = t_grad;
name_cout = stu[i].name;
}
}
cout << name_cout << endl;
cout << max_grad << endl;
cout << sum_grad << endl;
}

暴力模拟，大H2O题目
祝大家全AC

#include<bits/stdc++.h>
#define FOR(i,n,m) for(int i=n;i<=m;i++)
using namespace std;
struct student{
    string name;
    int endtest,classtest,stu,west,lw,money;
}a[105];
int n,allmoney,ans=0,now=0;
int main()
{
    char s,w;
    cin>>n;
    FOR(i,1,n)
    {
        cin>>a[i].name;
        cin>>a[i].endtest>>a[i].classtest;
        cin>>s>>w>>a[i].lw;
        if(s=='Y')
        a[i].stu=1;
        else
        a[i].stu=0;//是否是学生干部 
        
        if(w=='Y')
        a[i].west=1;
        else
        a[i].west=0;//是否是西部学生 
        
        //开始颁发奖学金 
        if(a[i].endtest>80&&a[i].lw>=1)
        a[i].money+=8000;//院士奖学金
        
        if(a[i].endtest>85&&a[i].classtest>80)
        a[i].money+=4000;//五四奖学金
        
        if(a[i].endtest>90)
        a[i].money+=2000;//成绩优秀奖
        
        if(a[i].endtest>85&&a[i].west==1)
        a[i].money+=1000;//西部奖学金
        
        if(a[i].classtest>80&&a[i].stu==1)
        a[i].money+=850;//班级贡献奖
        
        allmoney+=a[i].money;//计算发出奖学金总和    
        
        if(now<a[i].money)
        {
            now=a[i].money;
            ans=i;
        }//查找奖学金最高者 
    }


    cout<<a[ans].name<<'\n'<<a[ans].money<<'\n'<<allmoney;
    return 0;
}

分析一下思路：
1. 输入各类数据
2. 算出每个人的奖金数，注意，在算的时候要使用if-if，不能使用if-else if - else结构，因为每个人都可以领多个奖学金，所以有些人符合多个条件
3. 遍历数组，寻找最多奖学金，求出全部奖金和
4. 输出有最多奖学金的人，最多的奖学金，以及总共奖学金

/*
    @createTime 2019.2.10
    @Author C++语言学习者青云
    @problemName 谁拿了最多奖学金
*/
#include <iostream>
using namespace std;

int main()
{
    
    int a;
    cin >> a;
    string name[a];
    int score[a];
    int pingyi[a];
    char ganbu[a];
    char xibu[a];
    int lunwen[a];
    int money[a];
    int w = 0,maxmoney = 0,allmoney = 0;
    for(int i = 0;i < a;i++)
    {
        cin >> name[i] >> score[i] >> pingyi[i] >> ganbu[i] >> xibu[i] >> lunwen[i];
    }
    for(int i = 0;i < a;i++)
    {
        money[i] = 0;
        if(score[i] > 80 && lunwen[i] >= 1)
        {
            money[i] += 8000;
        }
        if(score[i] > 85 && pingyi[i] > 80)
        {
            money[i] += 4000;
        }
        if(score[i]> 90)
        {
            money[i] += 2000;
        }
        if(score[i] > 85 && xibu[i] == 'Y')
        {
            money[i] += 1000;
        }
        if(pingyi[i] > 80 && ganbu[i] == 'Y')
        {
            money[i] += 850;
        }
        allmoney += money[i]; 
    }
    for(int i = 0;i < a;i++)
    {
        if(maxmoney < money[i])
        {
            maxmoney = money[i];
            w = i;
        }
    }
    cout << name[w] << endl << maxmoney << endl << allmoney;
    return 0;
}

一道很不错的模拟题，祝大家全部AC
最后吐槽一句：这是什么学校？发这么多奖学金？