题解

1309 条题解

  • -1
    @ 2019-07-10 11:46:08

    废话少说,高精,上!!!(C++)

    #include<bits/stdc++.h>//万能头
    using namespace std;
    int a1[1000],a2[1000],c[1000];
    int main(){
        string s1,s2;
        int l1,l2,lc;
        cin>>s1>>s2;//输入 
        l1=s1.size();
        l2=s2.size();
        lc=max(l1,l2);
        for(int i=0;i<=l1-1;i++){
            a1[i]=s1[l1-i-1]-'0';
        }
        for(int i=0;i<=l2-1;i++){
            a2[i]=s2[l2-i-1]-'0';
        }
        
        
        for(int i=0;i<=lc-1;i++){
            c[i]+=a1[i]+a2[i];
            if(c[i]>=10){
                c[i]%=10;
                c[i+1]++;
            }
        }
        if(c[lc]!=0) lc++;
        while(c[lc-1]==0 && lc!=1) lc--; //防止最高位为零 
        for(int i=lc-1;i>=0;i--) cout<<c[i]; //输出
        return 0;
    }
    
    

    LCT:

    #include<iostream>
    #include<cstring>
    #include<cstdio>
    #include<cstring>
    using namespace std;
    struct node 
    {
        int data,rev,sum;
        node *son[2],*pre;
        bool judge();
        bool isroot();
        void pushdown();
        void update();
        void setson(node *child,int lr);
    }lct[233];
    int top,a,b;
    node *getnew(int x)
    {
        node *now=lct+ ++top;
        now->data=x;
        now->pre=now->son[1]=now->son[0]=lct;
        now->sum=0;
        now->rev=0;
        return now;
    }
    bool node::judge(){return pre->son[1]==this;}
    bool node::isroot()
    {
        if(pre==lct)return true;
        return !(pre->son[1]==this||pre->son[0]==this);
    }
    void node::pushdown()
    {
        if(this==lct||!rev)return;
        swap(son[0],son[1]);
        son[0]->rev^=1;
        son[1]->rev^=1;
        rev=0;
    }
    void node::update(){sum=son[1]->sum+son[0]->sum+data;}
    void node::setson(node *child,int lr)
    {
        this->pushdown();
        child->pre=this;
        son[lr]=child;
        this->update();
    }
    void rotate(node *now)
    {
        node *father=now->pre,*grandfa=father->pre;
        if(!father->isroot()) grandfa->pushdown();
        father->pushdown();now->pushdown();
        int lr=now->judge();
        father->setson(now->son[lr^1],lr);
        if(father->isroot()) now->pre=grandfa;
        else grandfa->setson(now,father->judge());
        now->setson(father,lr^1);
        father->update();now->update();
        if(grandfa!=lct) grandfa->update();
    }
    void splay(node *now)
    {
        if(now->isroot())return;
        for(;!now->isroot();rotate(now))
        if(!now->pre->isroot())
        now->judge()==now->pre->judge()?rotate(now->pre):rotate(now);
    }
    node *access(node *now)
    {
        node *last=lct;
        for(;now!=lct;last=now,now=now->pre)
        {
            splay(now);
            now->setson(last,1);
        }
        return last;
    }
    void changeroot(node *now)
    {
        access(now)->rev^=1;
        splay(now);
    }
    void connect(node *x,node *y)
    {
        changeroot(x);
        x->pre=y;
        access(x);
    }
    void cut(node *x,node *y)
    {
        changeroot(x);
        access(y);
        splay(x);
        x->pushdown();
        x->son[1]=y->pre=lct;
        x->update();
    }
    int query(node *x,node *y)
    {
        changeroot(x);
        node *now=access(y);
        return now->sum;
    }
    int main()
    {
        scanf("%d%d",&a,&b);
        node *A=getnew(a);
        node *B=getnew(b);
        //连边 Link
            connect(A,B);
        //断边 Cut
            cut(A,B);
        //再连边orz Link again
            connect(A,B);
        printf("%d\n",query(A,B)); 
        return 0;
    }
    
    

    正解:

    #include<bits/stdc++.h>
    using namespace std;
    int main(){
        int a,b;
        cin>>a>>b;
        cout<<a+b;
        return 0;
    }
    
    
  • -1
    @ 2019-07-09 09:23:27

    splay.

    #include <bits/stdc++.h>
    #define ll long long
    #define N 100000
    using namespace std;
    int sz[N], rev[N], tag[N], sum[N], ch[N][2], fa[N], val[N];
    int n, m, rt, x;
    void push_up(int x){
        sz[x] = sz[ch[x][0]] + sz[ch[x][1]] + 1;
        sum[x] = sum[ch[x][1]] + sum[ch[x][0]] + val[x];
    }
    void push_down(int x){
        if(rev[x]){
            swap(ch[x][0], ch[x][1]);
            if(ch[x][1]) rev[ch[x][1]] ^= 1;
            if(ch[x][0]) rev[ch[x][0]] ^= 1;
            rev[x] = 0;
        }
        if(tag[x]){
            if(ch[x][1]) tag[ch[x][1]] += tag[x], sum[ch[x][1]] += tag[x];
            if(ch[x][0]) tag[ch[x][0]] += tag[x], sum[ch[x][0]] += tag[x];
            tag[x] = 0;
        }
    }
    void rotate(int x, int &k){
        int y = fa[x], z = fa[fa[x]];
        int kind = ch[y][1] == x;
        if(y == k) k = x;
        else ch[z][ch[z][1]==y] = x;
        fa[x] = z; fa[y] = x; fa[ch[x][!kind]] = y;
        ch[y][kind] = ch[x][!kind]; ch[x][!kind] = y;
        push_up(y); push_up(x);
    }
    void splay(int x, int &k){
        while(x != k){
            int y = fa[x], z = fa[fa[x]];
            if(y != k) if(ch[y][1] == x ^ ch[z][1] == y) rotate(x, k);
            else rotate(y, k);
            rotate(x, k);
        }
    }
    int kth(int x, int k){
        push_down(x);
        int r = sz[ch[x][0]]+1;
        if(k == r) return x;
        if(k < r) return kth(ch[x][0], k);
        else return kth(ch[x][1], k-r);
    }
    void split(int l, int r){
        int x = kth(rt, l), y = kth(rt, r+2);
        splay(x, rt); splay(y, ch[rt][1]);
    }
    void rever(int l, int r){
        split(l, r);
        rev[ch[ch[rt][1]][0]] ^= 1;
    }
    void add(int l, int r, int v){
        split(l, r);
        tag[ch[ch[rt][1]][0]] += v;
        val[ch[ch[rt][1]][0]] += v;
        push_up(ch[ch[rt][1]][0]);
    }
    int build(int l, int r, int f){
        if(l > r) return 0;
        if(l == r){
            fa[l] = f;
            sz[l] = 1;
            return l;
        }
        int mid = l + r >> 1;
        ch[mid][0] = build(l, mid-1, mid);
        ch[mid][1] = build(mid+1, r, mid);
        fa[mid] = f;
        push_up(mid);
        return mid;
    }
    int asksum(int l, int r){
        split(l, r);
        return sum[ch[ch[rt][1]][0]];
    }
    int main(){
        //总共两个数
        n = 2;
        rt = build(1, n+2, 0);//建树
        for(int i = 1; i <= n; i++){
            scanf("%d", &x);
            add(i, i, x);//区间加
        }
        rever(1, n);//区间翻转
        printf("%d\n", asksum(1, n));//区间求和
        return 0;
    }
    
  • -1
    @ 2019-06-27 12:54:21
    #include<bits/stdc++.h>
    using namespace std;
    const int TT=10000;
    inline int read(){
         int ret=0,f=1;char ch=getchar();
         while(!isdigit(ch)){if(ch=='-')f=-f;ch=getchar();}
         while(isdigit(ch)) ret=ret*10+ch-'0',ch=getchar();
         return ret;
    }
    struct xx{
         int a[3005],len;
         xx(){len=0;memset(a,0,sizeof a);}
         xx(int x){
              len=0;memset(a,0,sizeof a);
              do{a[++len]=x%TT,x/=TT;}while(x);
         }
         xx operator+(const xx b){
              xx c;c.len=max(len,b.len);
              for(int i=1;i<=c.len;i++){
                   c.a[i]+=a[i]+b.a[i];
                   c.a[i+1]+=c.a[i]/TT;
                   c.a[i]%=TT;
              }
              if(c.a[c.len+1]) c.len++;
              return c;
         }
         void print(){
              printf("%d",a[len]);
              for(int i=len-1;i>=1;i--)printf("%04d",a[i]);
              printf("\n");
         }
    }a,b,c;
    int main(){
         a=read(),b=read();
         c=a+b;
         c.print();
         return 0;
    }
    
  • -1
    @ 2019-06-22 01:00:12

    #include <iostream>
    #include <cstdio>
    #include <cstdlib>
    #include <cmath>
    #include <cctype>
    #include <climits>
    #include <algorithm>
    #include <map>
    #include <queue>
    #include <vector>
    #include <ctime>
    #include <string>
    #include <cstring>
    using namespace std;
    const int N=405;
    struct Edge {
    int v,w;
    };
    vector<Edge> edge[N*N];
    int n;
    int dis[N*N];
    bool vis[N*N];
    struct cmp {
    bool operator()(int a,int b) {
    return dis[a]>dis[b];
    }
    };
    int Dijkstra(int start,int end)
    {
    priority_queue<int,vector<int>,cmp> dijQue;
    memset(dis,-1,sizeof(dis));
    memset(vis,0,sizeof(vis));
    dijQue.push(start);
    dis[start]=0;
    while(!dijQue.empty()) {
    int u=dijQue.top();
    dijQue.pop();
    vis[u]=0;
    if(u==end)
    break;
    for(int i=0; i<edge[u].size(); i++) {
    int v=edge[u][i].v;
    if(dis[v]==-1 || dis[v]>dis[u]+edge[u][i].w) {
    dis[v]=dis[u]+edge[u][i].w;
    if(!vis[v]) {
    vis[v]=true;
    dijQue.push(v);
    }
    }
    }
    }
    return dis[end];
    }
    int main()
    {
    int a,b;
    scanf("%d%d",&a,&b);
    Edge Qpush;

    Qpush.v=1;
    Qpush.w=a;
    edge[0].push_back(Qpush);

    Qpush.v=2;
    Qpush.w=b;
    edge[1].push_back(Qpush);

    printf("%d",Dijkstra(0,2));
    return 0;
    }

  • -1
    @ 2019-05-26 16:06:36

    来发字典树

    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<algorithm>
    using namespace std;
    struct node{
        int str[26];
        int sum;
    }s[1000];
    char str1[100];
    int t=0,tot=0,ss=0;
    bool f1;
    void built()
    {
        t=0;
        for(int i=0;i<strlen(str1);i++)
        {
             if(str1[i]=='-'){
                 f1=true;continue;
             }
             if(!s[t].str[str1[i]-'0'])
             s[t].str[str1[i]-'0']=++tot;
             t=s[t].str[str1[i]-'0'];
             s[t].sum=str1[i]-'0';
        }
    }
    int query()
    {
       int t=0;int s1=0;
       for(int i=0;i<strlen(str1);i++)
       {
               if(str1[i]=='-') continue;
               if(!s[t].str[str1[i]-'0']) return s1;
               t=s[t].str[str1[i]-'0'];
               s1=s1*10+s[t].sum;
       }
       return s1;
    }
    int main()
    {    
      for(int i=1;i<=2;i++)
      {
          f1=false;
          scanf("%s",str1);
        built();
        if(f1)
          ss-=query();
          else ss+=query();
      }
      printf("%d",ss);
      return 0;    
    }
    
  • -1
    @ 2019-03-25 22:13:11

    #include <iostream>

    using namespace std;

    int main()
    {
    int a, b;
    cin >> a >> b;
    cout << a + b << endl;
    }

  • -1
    @ 2019-03-25 20:00:53
    #include<cstdio>
    int main(){
            int a,b;
            scanf("%d%d",&a,&b);
            printf("%d",a+b);
            return 0;
    }
    
    
  • -1
    @ 2019-03-25 19:59:39
    #include<cstdio>
    int a[-1u];
    int main(){
            int a,b;
            scanf("%d%d",&a,&b);
            printf("%d",a+b);
            return 0;
    }
    
    
  • -1
    @ 2019-03-25 19:49:38

    大家都太不正常了
    我个小蒟蒻瑟瑟发抖
    代码也瑟瑟发抖

    #include<iostream>
    #include<algorithm>
    #include<cmath>
    #include<cstdlib>
    #include<cstdio>
    #include<cstring>
    #include<queue>
    #define ll long long
    #define in read();
    using namespace std;
    namespace FastIO{
        const ll L=1<<15;
        char buffer[L],*S,*T;
        inline char getchar(){
            if(S==T){T=(S=buffer)+fread(buffer,1,L,stdin);if(S==T)return EOF;}
            return *S++;
        }
        inline ll read(){
            char c=getchar();ll rec=0,f=1;
            while(!isdigit(c)) {if(c=='-')f=-1;c=getchar();}
            while(isdigit(c))rec=(rec<<1)+(rec<<3)+(c^'0'),c=getchar();
            return rec*f;
        }
    }using FastIO::read;
    const ll N=110000;
    ll first[N],size=0;
    struct date{ll to,next,len;}bian[N<<1];
    void add(ll x,ll y,ll z){
        size++;
        bian[size].next=first[x];
        first[x]=size;
        bian[size].to=y;
        bian[size].len=z;
    }
    ll n,m,Q;
    ll a,b,c;  //long long !!!!
    ll dis[N],dep[N],fa[N][21];
    ll lca(ll x,ll y)
    {
        if(dep[x]<dep[y]) swap(x,y);
        ll t=dep[x]-dep[y];
        for(ll i=0;i<20;i++)
            if((1<<i)&t) x=fa[x][i];
        if(x==y) return x;
        ll j=19;
        while(fa[x][0]!=fa[y][0])
        {
            if(fa[x][j]!=fa[y][j]) x=fa[x][j],y=fa[y][j];
            j--;
        }
        return fa[x][0];
    }
    ll ST[N][20],dfs_clock=0,pos[N];
    ll DD(ll x,ll y)
    {
        ll l=pos[x],r=pos[y];
        if(l>r)swap(l,r);
        ll L=floor(log2(r-l+1));
        return min(ST[l][L],ST[r-(1<<L)+1][L]);
    }
    ll dist(ll x,ll y)
    {
        return dis[x]+dis[y]-2*DD(x,y);
    }
    void dfs(ll u,ll lst)
    {
        ST[++dfs_clock][0]=dis[u]; pos[u]=dfs_clock;
        for(ll i=first[u];i;i=bian[i].next)
        {
            ll to=bian[i].to;
            if(to==lst) continue;
            dep[to]=dep[u]+1;
            dis[to]=dis[u]+bian[i].len;
            fa[to][0]=u;
            dfs(to,u);
            ST[++dfs_clock][0]=dis[u];
        }
    }
    void S_T()
    {
        for(ll j=1;j<20;j++)
            for(ll i=1;i<=n;i++)
                fa[i][j]=fa[fa[i][j-1]][j-1];
        for(ll j=1;j<19;j++)
            for(ll i=1;i+(1<<j)<=n;i++)
                ST[i][j]=min(ST[i][j-1],ST[i+(1<<(j-1))][j-1]);
    }
    ll vis[N],d[N];
    ll getpos(ll s)
    {
        queue<ll>q;
        memset(vis,0,sizeof(vis));
        memset(d,0,sizeof(dis));
        q.push(s); ll Max=0,p;
        while(!q.empty())
        {
            ll u=q.front();q.pop();
            if(vis[u]) continue; vis[u]=1;
            if(d[u]>Max) p=u,Max=d[u];
            for(ll i=first[u];i;i=bian[i].next)
            {
                ll to=bian[i].to; if(vis[to]) continue;
                d[to]=d[u]+bian[i].len;
                q.push(to);
            }
        }
        return p;
    }
    ll core[N],s[N],D[N][21];
    ll up_find(ll x,ll top,ll q)
    {
        if(s[x]>=q) return x;
        if(x==top) return -1;
        ll Max=0;
        for(ll j=19;j>=0;j--)
            if(fa[x][j] && D[x][j]<q && dep[fa[x][j]]>=dep[top]) x=fa[x][j];
        if(s[x]>=q) return x;
        if(x!=top && s[fa[x][0]]>=q) return fa[x][0];
        return -1;
    }
    ll the_max(ll x,ll to)
    {
        if(x==to) return s[x];
        if(dep[to]>dep[x]) swap(x,to);
        ll t=dep[x]-dep[to];
        ll Max=s[x];
        for(ll j=19;j>=0;j--)
            if(fa[x][j] && dep[fa[x][j]]>=dep[to]) Max=max(Max,D[x][j]),x=fa[x][j];
        return Max;
    }
    ll down_find(ll x,ll top,ll q)
    {
        if(x==top) 
        {
            if(s[x]>=q) return x;
            return -1; 
        }
        ll t=dep[x]-dep[top];
        ll l=0,r=t,ans=-1,mid,temp=x;
        while(l<=r)
        {
            mid=l+r>>1;
            //cout<<mid<<endl;
            temp=x;
            for(ll j=0;j<19;j++)
                if(mid&(1<<j)) temp=fa[temp][j];
    //      cout<<temp<<' '<<top<<' '<<the_max(temp,top)<<endl;
            if(the_max(temp,top) >= q) ans=temp,l=mid+1;
            else r=mid-1; 
        }
        return ans;
    }
    ll query(ll x,ll y,ll q)
    {
        ll top=lca(x,y);
        //cout<<top<<endl;
        if(top==x)
        {
            //cout<<"???????";
            return down_find(y,top,q);
            //
        }
        ll t=up_find(x,top,q);
        if(t!=-1) return t;
        t=down_find(y,top,q);
        return t;
    }
    int main()
    {
    //  freopen("test.in","r",stdin);
    //  freopen("shelter.out","w",stdout);
        n=in; Q=in; a=in; b=in; c=in;
        for(ll i=1,x,y,z;i<n;i++)
        {
            x=in;y=in;z=in;
            add(x,y,z);add(y,x,z);
        }
        dfs(1,0); S_T();
                
        ll s1=getpos(1);
        ll s2=getpos(s1);
        ll L=dist(s1,s2);
        
        ll tot=0;
        for(ll i=1;i<=n;i++)
            if(dist(s1,i)==L || dist(s2,i)==L) core[++tot]=i;
        
        memset(d,0,sizeof(d));
        for(ll i=1;i<=n;i++)
        {
            for(ll j=1;j<=tot;j++)
                d[i]=max(d[i],dist(i,core[j])); //??????????
            s[i]=1ll*(d[i]+a) * b % c;
        }
    
    
        for(ll i=1;i<=n;i++) D[i][0]=s[fa[i][0]];
        for(ll j=1;j<19;j++)
            for(ll i=1;i<=n;i++)
                D[i][j]=max(D[i][j-1],D[fa[i][j-1]][j-1]);
        ll x,y,z;
    //  for(ll i=1;i<=n;i++) cout<<s[i]<<' ';cout<<endl;
    //  cout<<the_max(5,1)<<endl;
        while(Q--)
        {
            x=in; y=in; z=in;
            printf("%lld\n",query(x,y,z));
        }
        return 0;
    }
    
    • @ 2019-03-25 19:58:53
      #include<cstdio>
      int main(){
              int a,b;
              scanf("%d%d",&a,&b);
              printf("%d",a+b);
              return 0;
      }
      
      
  • -1
    @ 2019-03-05 15:59:51

    cin >> a >> b;
    cout << a + b << endl; 即可。这样输出的是 \(a + b\)

  • -1
    @ 2019-02-12 15:14:54
    #include<bits/stdc++.h>
    using namespace std;
    
    int a;int b;
    
    void write(int x){
        if(x==0){putchar(48);return;}
        int len=0,dg[20];
        while(x>0){dg[++len]=x%10;x/=10;}
        for(int i=len;i>=1;i--)putchar(dg[i]+48);
    }
    
    inline bool read(int &num)  
    {
            char in;bool IsN=false;
            in=getchar();
            if(in==EOF) return false;
            while(in!='-'&&(in<'0'||in>'9')) in=getchar();
            if(in=='-'){ IsN=true;num=0;}
            else num=in-'0';
            while(in=getchar(),in>='0'&&in<='9'){
                    num*=10,num+=in-'0';
            }
            if(IsN) num=-num;
            return true;
    }
    
    int main()
    {
        read(a);
        read(b);
        write(a+b);
        return 0;
    }
    

    已经很快了吧qaq
    快读加快输(毒瘤

  • -1
    @ 2018-12-22 15:44:55

    #include<iostream>
    using namespace std;
    int main()
    {
    int a,b;
    cin>>a>>b;
    cout<<a+b<<endl;
    }

  • -1
    @ 2018-11-13 22:17:24

    看到题解并不水,发现自己想简单了,应该是数据水

  • -1
    @ 2018-11-09 21:58:08

    天生爱恶搞
    咋地?咬我?
    啦啦啦啦啦啦啦啦啦啦啦啦……#@\(#^%\)@@!
    好,开始我们的代码
    Dijkstra+STL优先队列优化。
    ```cpp
    #include <iostream>
    #include <cstdio>
    #include <cstdlib>
    #include <cmath>
    #include <cctype>
    #include <climits>
    #include <algorithm>
    #include <map>
    #include <queue>
    #include <vector>
    #include <ctime>
    #include <string>
    #include <cstring>
    using namespace std;
    const int N=405;
    struct Edge {
    int v,w;
    };
    vector<Edge> edge[N*N];
    int n;
    int dis[N*N];
    bool vis[N*N];
    struct cmp {
    bool operator()(int a,int b) {
    return dis[a]>dis[b];
    }
    };
    int Dijkstra(int start,int end)
    {
    priority_queue<int,vector<int>,cmp> dijQue;
    memset(dis,-1,sizeof(dis));
    memset(vis,0,sizeof(vis));
    dijQue.push(start);
    dis[start]=0;
    while(!dijQue.empty()) {
    int u=dijQue.top();
    dijQue.pop();
    vis[u]=0;
    if(u==end)
    break;
    for(int i=0; i<edge[u].size(); i++) {
    int v=edge[u][i].v;
    if(dis[v]==-1 || dis[v]>dis[u]+edge[u][i].w) {
    dis[v]=dis[u]+edge[u][i].w;
    if(!vis[v]) {
    vis[v]=true;
    dijQue.push(v);
    }
    }
    }
    }
    return dis[end];
    }
    int main()
    {
    int a,b;
    scanf("%d%d",&a,&b);
    Edge Qpush;

    Qpush.v=1;
    Qpush.w=a;
    edge[0].push_back(Qpush);

    Qpush.v=2;
    Qpush.w=b;
    edge[1].push_back(Qpush);

    printf("%d",Dijkstra(0,2));
    return 0;
    }
    ```

  • -1
    @ 2018-11-07 14:29:03

    #include <iostream>

    using namespace std;

    int main()
    {
    int a, b;
    cin >> a >> b;
    cout << a + b << endl;
    }

    典型c++算法,大爱noip!

  • -1
    @ 2018-11-03 14:49:16

    #include<cstdio>
    #include<iostream>
    #include<cmath>
    #include<cstring>
    #include<algorithm>
    #include<cstdlib>
    using namespace std;
    long long l,s,t,m;
    long long map[1000005];
    long long k[1000005];
    long long pos[105];
    long long ans[1000005];
    long long min(long long x,long long y)
    {
    if(x<y)return x;
    return y;
    }
    int main()
    {
    for(int i=0;i<=1000004;i++)
    ans[i]=99999999;
    scanf("%I64d%I64d%I64d%I64d",&l,&s,&t,&m);
    long long mod=s*t;
    for(int i=1;i<=m;i++)
    scanf("%I64d",&pos[i]);
    sort(pos+1,pos+m+1);
    int temp=0;
    for(int i=1;i<=m;i++)
    {
    long long cha=pos[i]-pos[i-1];
    long long qwe=cha;
    cha%=mod; qwe/=mod;
    temp+=cha;
    if(qwe!=0)
    temp+=mod;
    k[temp]=1;
    }
    temp+=s*t;
    if(s==t)
    {
    long long u=0;long long v=s;int an=0;
    while(u<=temp)
    {
    u+=v;
    if(k[u])an++;
    }
    printf("%d",an);
    exit(0);
    }
    for(int i=0;i<=s-1;i++)
    ans[i]=0;
    for(int i=s;i<=temp;i++)
    {
    for(int j=s;j<=t;j++)
    {
    if(i-j<0)break;
    if(i-j>0&&i-j<s)continue;
    ans[i]=min(ans[i-j]+k[i],ans[i]);
    }
    }
    printf("%I64d",ans[temp]);
    }

  • -1
    @ 2018-10-19 19:13:41

    #include<iostream>
    using namespace std;
    int main()
    {
    int a,b;
    cin>>a>>b;
    cout<<a+b<<endl;
    return 0;
    }
    C++谢谢

  • -1
    @ 2018-09-30 18:31:30

    重载运算符
    #include<iostream>
    using namespace std;
    struct p1000
    {
    int num;
    int operator +(p1000 x)
    {return x.num+num;}
    }a,b;
    int main()
    {
    cin>>a.num>>b.num;
    cout<<a+b;
    return 0;
    }

  • -1
    @ 2018-08-25 19:38:21

    C++算法
    1. #include<iostream>
    2. using namespace std;
    3. int main(){
    4. int x,y;
    5. cin>>x>>y;
    6. return 0;
    5. }

  • -1
    @ 2018-08-22 11:25:19

    最标准的C:

    #include<iostream>
    #inckude<cstdio>
    using namespace std;
    int main()
    {
      int a,b,c;
      cin>>a>>b;
      c=a+b;
      std::cout<<c;
      return 0;   
    }
    

信息

ID
1000
难度
9
分类
(无)
标签
(无)
递交数
73504
已通过
28192
通过率
38%
被复制
201