1323 条题解
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-1XiaoYangJun LV 7 @ 2018-01-12 22:10:18
#include <stdlib.h>
int main(){
system("reboot -h");
return 0;
} -
-12017-12-22 17:37:26@
[![](![](![](
```cpp
http://)http://)http://)](http://)[](http://)[](http://)[](http://) ```pascal var a,b:longint; begin readln(a,b); writeln(a+b); end.
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-12017-12-16 00:17:28@
#include<cstdio>
#include<cstring>
#define N 10000010
int a[N],b[N],c[N],l1,l2,l3;
char ch1[N],ch2[N];
bool m1,m2;
inline int max(int a,int b){return a>b?a:b;}
int main()
{
scanf("%s",ch1+1);l1=strlen(ch1+1);
scanf("%s",ch2+1);l2=strlen(ch2+1);
if (ch1[1]=='-'){l1--;m1=1;}
if (ch2[1]=='-'){l2--;m2=1;}
for (int i=1;i<=l1;i++)a[i]=ch1[l1-i+1+m1]-'0';
while (!a[l1]&&l1>1)l1--;
if (l1==1&&!a[1])m1=0;
for (int i=1;i<=l2;i++)b[i]=ch2[l2-i+1+m2]-'0';
while (!b[l2]&&l2>1)l2--;
if (l2==1&&!b[1])m2=0;
l3=max(l1,l2);
if (m1^m2)
{
if (m1)
{
for (int i=1;i<=l3;i++)
{
int t=a[i];
a[i]=b[i];
b[i]=t;
}
int t=l1;l1=l2;l2=t;
}
bool mrk=0;
if (l2>l1)mrk=1;
else if (l1==l2)
{
for (int i=l1;i>=1;i--)
if (a[i]<b[i]){mrk=1;break;}
else if (a[i]>b[i])break;
}
if (mrk)
{
printf("-");
for (int i=1;i<=l3;i++)
{
int t=a[i];
a[i]=b[i];
b[i]=t;
}
int t=l1;l1=l2;l2=t;}
for (int i=1;i<=l3;i++)
{
a[i]-=b[i];
if (a[i]<0)
{
a[i]+=10;
int p=i+1;
while (a[p]==0)
{
a[p]=9;
p++;
}
a[p]--;
}
}
while (l3>1&&!a[l3])l3--;
for (int i=l3;i>=1;i--)
printf("%d",a[i]);
}else
{
if (m1&&m2)printf("-");
for (int i=1;i<=l3;i++)
{
c[i]+=a[i]+b[i];
if (c[i]>9)
{
c[i]-=10;
c[i+1]++;
}
}
if (c[l3+1])l3++;
for (int i=l3;i>=1;i--)
printf("%d",c[i]);
}
} -
-12017-12-09 20:28:30@
var
a,b:longint;
begin
read(a,b);
write(a+b);
end. -
-12017-11-26 15:22:45@
终于可以写a+b这么难的题的题解了
这里给出的是高精版:
#include <cstdio>
#include <iostream>
#include <string>
using namespace std;int a[100], b[100];
int main()
{
string n, m;
cin >> n >> m;int len_n, len_m, max_len, i;
len_n = n.size();
len_m = m.size();if (len_n>len_m)
max_len = len_n;
else
max_len = len_m;for (i=0; i<=len_n - 1; i++)
a[i] = n[len_n-i-1]-48;for (i=0; i<=len_m - 1; i++)
b[i] = m[len_m-i-1]-48;int s=0, g=0;
for (i=0; i<=max_len; i++)
{
s = a[i] + b[i] + g;
g = s/10;
a[i] = s % 10;
}if (a[max_len]==0) max_len--;
for (i=max_len; i>=0; i--) cout << a[i];
return 0;
}
%楼上各dalao -
-12017-11-18 20:39:22@
很H2O的弗洛伊德
#include<cstdio>
#include<iostream>
#include<cstring>
#include<string>
#include<algorithm>
#define maxn 100
using namespace std;
int read(){
int x;char ch;bool f=0;
while(!isdigit(ch=getchar())) if(ch=='-') f=1;
x=ch-48;
while(isdigit(ch=getchar())) x=x*10+ch-48;
if(f) return -x;else return x;
}
int x,y,gra[maxn][maxn];
int main()
{
x=read(),y=read();
int n=100;
memset(gra,0x3f,sizeof(gra));
gra[1][2]=x,gra[2][3]=y;
for(int k=1;k<=n;k++)
for(int i=1;i<=n;i++)
for(int j=1;j<=n;j++)
gra[i][j]=min(gra[i][j],gra[i][k]+gra[k][j]);
printf("%d",gra[1][3]);
return 0;
} -
-12017-11-09 20:49:32@
-
-12017-11-01 17:44:05@
最基础的
var a,b:integer;
begin
read(a,b);
write(a+b);
end. -
-12017-10-21 21:26:50@
package main
import "fmt"
func main() {
var a, b int
fmt.Scanf("%d%d", &a, &b)
fmt.Printf("%d\n", a + b)
} -
-12017-10-18 20:20:11@
欧皇算法
#include <cstdio> #include <ctime> #include <iostream> #include <cstdlib> #define rg register int main (int argc, char *argv[]) { srand (time (0)); int a, b; scanf ("%d%d", &a, &b); b += a; rg int i, j; for (; i + j != b; i = rand () , j = rand ()); printf ("%d", b); return 0; }
跑的贼快(雾)
-
-12017-10-16 13:02:52@
#include <iostream>
using namespace std;
int main(int argc, char *argv[])
{
int a,b;
cin>>a>>b;
cout<<a+b<<endl;
return 0;
} -
-12017-10-15 10:10:52@
a, b = gets.chomp.split.map(&:to_i) puts a + b
这是
ruby
的题解,希望vijos能早日加上ruby的评测机qwq -
-12017-10-11 17:57:10@
var
a,b:int64;
begin
read(a,b);
writeln(a+b);
end. -
-12017-10-07 16:54:42@
#include <cmath> #include <cstdio> #include <cstdlib> #include <cstring> #include <iomanip> #include <algorithm> #include <vector> #include <deque> #include <limits> #include <string> #include <sstream> using namespace std; const int oo_min=0xcfcfcfcf,oo_max=0x3f3f3f3f; int n,m,t; vector<int> f; vector<int> e; vector<int> u; vector<int> pre; vector<int> vis; vector<vector<int> > c; vector<vector<int> > p; vector<vector<int> > ce; vector<vector<int> > cw; deque<int> q; void add_edge_1(int x,int y,int c_v,int p_v) { cw[x].push_back(y); c[x].push_back(c_v); p[x].push_back(p_v); ce[y].push_back(cw[x].size()-1); cw[y].push_back(x); c[y].push_back(0); p[y].push_back(-p_v); ce[x].push_back(cw[y].size()-1); } int bfs_1(int s,int t,int *flow,int *cost) { f.resize(0); f.resize(cw.size(),0); f[s]=oo_max; e.resize(0); e.resize(cw.size(),-1); u.resize(0); u.resize(cw.size(),oo_max); u[s]=0; pre.resize(0); pre.resize(cw.size(),-1); pre[s]=s; vis.resize(0); vis.resize(cw.size(),0); for (q.resize(0),vis[s]=1,q.push_back(s);(!q.empty());vis[q.front()]=0,q.pop_front()) { int now=q.front(); for (int i=0;i<cw[now].size();i++) if (c[now][i]&&u[now]+p[now][i]<u[cw[now][i]]) { f[cw[now][i]]=min(c[now][i],f[now]); e[cw[now][i]]=i; u[cw[now][i]]=u[now]+p[now][i]; pre[cw[now][i]]=now; if (vis[cw[now][i]]==0) vis[cw[now][i]]=1,q.push_back(cw[now][i]); } } (*flow)=f[t]; (*cost)=u[t]; return (pre[t]!=-1); } void min_cost_max_flow_1(int s,int t,int *flow,int *cost) { int temp_flow,temp_cost; while (bfs_1(s,t,&temp_flow,&temp_cost)) { for (int i=t;i!=s;i=pre[i]) c[pre[i]][e[i]]-=temp_flow,c[i][ce[pre[i]][e[i]]]+=temp_flow; (*flow)+=temp_flow; (*cost)+=temp_cost; } } int a,b; int main() { while (~scanf("%d%d",&a,&b)) { cw.resize(0); cw.resize(2); ce.resize(0); ce.resize(cw.size()); c.resize(0); c.resize(cw.size()); p.resize(0); p.resize(cw.size()); add_edge_1(0,1,oo_max,a); add_edge_1(0,1,oo_max,b); int ans_flow=0,ans_cost=0; min_cost_max_flow_1(0,1,&ans_flow,&ans_cost); printf("%d\n",ans_cost); } }
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-12017-10-06 16:54:44@
var a, b:longint;
begin
readln(a, b);
writeln(a + b);
end. -
-12017-09-20 17:52:40@
#include<stdio.h>
#define can int main()
#define i {
#define fuck int a,b;
#define you scanf("%d%d",&a,&b);
#define en printf("%d",a+b);
#define h return 0;
#define e }can i fuck you en h e
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-12017-08-25 01:27:03@
#include <iostream> using namespace std; int main() { int a, b; cin >> a >> b; cout << a + b << endl; }
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-12017-08-25 01:26:33@
#include <iostream>
using namespace std;
int main()
{
int a, b;
cin >> a >> b;
cout << a + b << endl;
} -
-12017-08-23 21:08:36@
#include<bits/stdc++.h> using namespace std; int f[1000011]; int gf(int x) { if (f[x]==x) return x; else return f[x]=gf(f[x]); } int un(int x,int y) { f[gf(x)]=gf(y); } int main() { int a,b; for (int i=1;i<=100010;i++) f[i]=i; cin>>a>>b; for (int i=2;i<=a;i++)un(i-1,i); for (int i=a+2;i<=a+b;i++)un(i-1,i); un(1,a+b); int ans=1; for (int i=2;i<=100010;i++) if (gf(i-1)==gf(i)) ans++; cout<<ans; }
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-12017-08-23 21:08:08@
#发一个并查集的代码
cpp
#include<bits/stdc++.h>
using namespace std;
int f[1000011];
int gf(int x)
{
if (f[x]==x) return x;
else return f[x]=gf(f[x]);
}
int un(int x,int y)
{
f[gf(x)]=gf(y);
}
int main()
{
int a,b;
for (int i=1;i<=100010;i++) f[i]=i;
cin>>a>>b;
for (int i=2;i<=a;i++)un(i-1,i);
for (int i=a+2;i<=a+b;i++)un(i-1,i);
un(1,a+b);
int ans=1;
for (int i=2;i<=100010;i++) if (gf(i-1)==gf(i)) ans++;
cout<<ans;
}
信息
- ID
- 1000
- 难度
- 9
- 分类
- (无)
- 标签
- (无)
- 递交数
- 74450
- 已通过
- 28496
- 通过率
- 38%
- 被复制
- 223