题解

16 条题解

  • 0
    @ 2017-06-07 10:32:18
    /*C++强行水过*/
    #include <iostream>
     using namespace std;
     int main()
     {
        string str;
        int count = 0;
        while(str != "begin")
        {
            getline(cin, str);
            for(int i = 0; i < str.size(); i++)
                if(str[i] == ',' || str[i] == ':')
                    count++;
        }
        cout << count << endl;
        return 0;
     }
    
  • 0
    @ 2016-11-30 16:57:42
    #include <algorithm>
    #include <iostream>
    #include <string>
    using namespace std;
    int main() {
        int ans = 0;
        string str;
        while (getline(cin,str),str != "begin") ans += count(str.begin(),str.end(),',')+count(str.begin(),str.end(),':');
        cout << ans;
        return 0;
    }
    
  • 0
    @ 2016-07-14 09:52:34

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    using namespace std;
    string s;
    int main()
    {
    int n=0;
    while(cin>>s)
    {
    for(int i=1;i<=s.size();i++)
    {
    if(s[i]==','||s[i]==':')
    {
    n++;
    }
    }
    if(s=="begin")
    break;
    }

    cout<<n;
    }

  • 0
    @ 2016-03-27 09:06:44

    测试数据 #0: Accepted, time = 0 ms, mem = 568 KiB, score = 10
    测试数据 #1: Accepted, time = 0 ms, mem = 572 KiB, score = 10
    测试数据 #2: Accepted, time = 0 ms, mem = 572 KiB, score = 10
    测试数据 #3: Accepted, time = 0 ms, mem = 572 KiB, score = 10
    测试数据 #4: Accepted, time = 0 ms, mem = 572 KiB, score = 10
    测试数据 #5: Accepted, time = 0 ms, mem = 572 KiB, score = 10
    测试数据 #6: Accepted, time = 0 ms, mem = 572 KiB, score = 10
    测试数据 #7: Accepted, time = 0 ms, mem = 572 KiB, score = 10
    测试数据 #8: Accepted, time = 0 ms, mem = 572 KiB, score = 10
    测试数据 #9: Accepted, time = 0 ms, mem = 576 KiB, score = 10
    Accepted, time = 0 ms, mem = 576 KiB, score = 100
    代码
    #include<iostream>
    #include<cstdio>
    #include<string>
    using namespace std;
    int tot=0;
    string s;
    int main()
    {
    //freopen("water.in","r",stdin);
    //freopen("water.out","w",stdout);
    while(cin>>s,s!="begin")
    for(int i=0;i<s.size();i+=1)
    if(s[i]==',' || s[i]==':') tot+=1;
    printf("%d",tot);
    //fclose(stdin); fclose(stdout);
    return 0;
    }

  • 0
    @ 2016-03-13 12:11:59

    var s,i:longint;
    x:string;
    begin
    s:=0;
    while not eof do
    begin
    readln(x);
    for i:=1 to length(x) do
    if (x[i]=',')or(x[i]=':') then inc(s);
    if x='begin' then begin
    write(s);
    exit;
    end;
    end;
    end.

  • 0
    @ 2015-04-27 20:47:43

    真的有那么水么?

    ###pascal code
    program p1762;
    var s:string; ans:int64; i,j:longint;
    begin
    ans:=0;
    for i:=1 to 2000 do begin
    readln(s); for j:=length(s) downto 1 do if (s[j]=',') or (s[j]=':') then inc(ans);
    if s='begin' then break;
    end;
    write(ans);
    end.

  • 0
    @ 2015-04-27 20:44:54

    。。。AC....
    var a:char;
    k,ans:integer;
    o:boolean;
    Begin
    k:=1;
    ans:=0;
    o:=false;
    while not o do
    begin
    read(a);
    case k of
    1: begin if (a='b') or (a='B') then inc(k); end;
    2: begin if (a='e') or (a='E') then inc(k) else k:=1; end;
    3: begin if (a='g') or (a='G') then inc(k) else k:=1; end;
    4: begin if (a='i') or (a='I') then inc(k) else k:=1; end;
    5: begin if (a='n') or (a='N') then o:=true else k:=1; end;
    end;
    if (a=':') or (a=',') then ans:=ans+1;
    end;
    writeln(ans);
    End.

  • 0
    @ 2014-08-06 15:34:52

    AC
    (我不懂pascal)
    #include <iostream>
    #include <cstring>
    using namespace std;

    int main()
    {
    char line[256];
    bool p = true;
    int cnt = 0;

    ios::sync_with_stdio(false);
    cin.getline(line, 256);
    while(!(cin.getline(line, 256).fail()))
    {
    if (!p)
    continue;
    if (!strcmp(line, "begin"))
    {
    p = false;
    continue;
    }
    for (int i = 0; i < (int)strlen(line); i++)
    {
    if ((line[i] == ',') || (line[i] == ':'))
    cnt++;
    }
    }
    cout << cnt << endl;
    return 0;
    }

  • 0
    @ 2013-11-08 10:04:46

    var
    s,s1:ansistring;
    ans,i:longint;
    begin
    while not(eof) do
    begin
    readln(s1);
    if pos('begin',s1)>0 then break;
    s:=s+s1;
    end;
    ans:=0;
    for i:=1 to length(s) do
    if (s[i]=',') or (s[i]=':') then inc(ans);
    writeln(ans);
    end.
    这是我们绍一中的凌神出的题。
    虽然水,自然要顶!
    顶!!!!!!!!!!!!
    By JSB

  • 0
    @ 2013-11-03 10:30:13

    var
    i,j,n,m,ans:longint;
    s:ansistring;
    begin
    n:=0;m:=0;
    while pos('begin',s)=0 do
    begin
    readln(s);
    for i:=1 to length(s) do
    if s[i]=',' then ans:=ans+1;
    for i:=1 to length(s) do
    if s[i]=':' then ans:=ans+1;
    end;
    writeln(ans);
    end.
    var
    i,j,n,m,ans:longint;
    s:ansistring;
    begin
    n:=0;m:=0;
    while pos('begin',s)=0 do
    begin
    readln(s);
    for i:=1 to length(s) do
    if s[i]=',' then ans:=ans+1;
    for i:=1 to length(s) do
    if s[i]=':' then ans:=ans+1;
    end;
    writeln(ans);
    end.

    查找',' ':'的位置,统计数量即可。

  • 0
    @ 2012-11-09 20:05:47

    01 var

    02 s:string;

    03 q,v,b,e,l:integer;

    04 begin

    05 e:=0;

    06 v:=0;

    07 l:=0;

    08 b:=0;

    09 while pos('begin',s)=0 do begin

    10 readln(s);

    11 e:=v;

    12 for q:=1 to length(s) do if s[q]=','then v:=v+1;

    13 if ve then b:=b+1;

    14 if v=e then for q:=1 to length(s)do if s[q]=':'then l:=l+1;

    15 end;

    16 if v0 then writeln(l+v+b);

    17 if v=0 then writeln(l);

    18 end.

  • 0
    @ 2012-11-05 18:11:10

    这题是想逆天啊还是怎么的

  • 0
    @ 2012-11-04 21:44:34

    我只能说 数据不好。。。

    不过作为70T 留下名吧。。。

    我建议出题者 可以改成判断是否CE(偷笑)

  • 0
    @ 2012-11-04 21:21:54

    ├ 测试数据 01:答案正确... (0ms, 408KB)

    ├ 测试数据 02:答案正确... (0ms, 408KB)

    ├ 测试数据 03:答案正确... (0ms, 408KB)

    ├ 测试数据 04:答案正确... (0ms, 408KB)

    ├ 测试数据 05:答案正确... (0ms, 408KB)

    ├ 测试数据 06:答案正确... (0ms, 408KB)

    ├ 测试数据 07:答案正确... (0ms, 408KB)

    ├ 测试数据 08:答案正确... (0ms, 408KB)

    ├ 测试数据 09:答案正确... (0ms, 408KB)

    ├ 测试数据 10:答案正确... (0ms, 408KB)

    ---|---|---|---|---|---|---|---|-

    Accepted / 100 / 0ms / 408KB

    这题第三个点猥琐的在begin前加了空格

    于是我就WA了一次

    加上删前缀空格AC了……

    话说数据很弱啊,连个type、const什么的都没有

    begin只有前缀空格,没有后缀空格

  • 0
    @ 2012-11-09 19:22:48

    声明一下,begin前是没有空格的,第三个点是样例,楼下的自己搞错了吧

  • 0
    @ 2012-11-04 20:19:28

    不愧为通过率100%的题啊!

    真简单,连数组都不用考虑(更不用说过程和函数了)

    AC38题纪念!(这个)

    首先读入,读到begin就不用读了(不懂的可以研究P1000去,变量定义在主程序前)

    然后一行一行判断,有,或:就把累加变量加一......

    直到判断完为止

    第一次前十个AC题,第一次坐沙发)

  • 1

信息

ID
1762
难度
4
分类
模拟 点击显示
标签
(无)
递交数
396
已通过
181
通过率
46%
被复制
3
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