457 条题解
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0
oxforever LV 3 @ 2007-08-04 16:09:13
Program apple;
var
a:array[1..10] of integer;
b,c,d,e,i:integer;
begin
for i:=1 to 10 do
read(a[i]);
readln(b);
c:=b+30;
for e:=1 to 10 do
if a[e] -
0@ 2007-08-04 15:44:27
记录号 Flag 得分 记录信息 环境 评测机 程序提交时间
R410181 Accepted 100 From lzwhjl00-
P1102 FPC Vivid Puppy 2007-8-4 15:43:50编译通过...
├ 测试数据 01:答案正确... 0ms
├ 测试数据 02:答案正确... 0ms
├ 测试数据 03:答案正确... 0ms
├ 测试数据 04:答案正确... 0ms
├ 测试数据 05:答案正确... 0ms
├ 测试数据 06:答案正确... 0ms
├ 测试数据 07:答案正确... 0ms
├ 测试数据 08:答案正确... 0ms
├ 测试数据 09:答案正确... 0ms
├ 测试数据 10:答案正确... 0ms
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Accepted 有效得分:100 有效耗时:0ms -
0@ 2007-07-30 12:20:58
var
i,n,sum:longint;
a:array[1..10] of longint;
begin
for i:=1 to 10 do read(a[i]);
readln(n);
for i:=1 to 10 do
if n+30>=(a[i]) then inc(sum);
writeln(sum);
end. -
0@ 2007-07-24 10:55:14
这道题是幼儿园小朋友都会做的题,谁不会做谁就可以放心地去死了
此乃超级弱智题 -
0@ 2007-07-23 08:10:34
如果谁连这道题目都要用作弊来解决,那只能说明一个问题————这个人是个超级大傻瓜!
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0@ 2007-07-17 15:42:15
var a:array[1..10];
i,j,k:integer;
begin
for i:=1 to 10 do read(a[i]);
readln(j);
j:=j+30;
k:=0;
for i:=1 to 10 do
begin
if a[i] -
0@ 2007-08-05 16:20:16
var
a:array[1..10] of integer;
i,x,n:integer;
begin
for i:=1 to 10 do read(a[i]);
readln(n);
n:=n+30;
x:=0;
for i:=1 to 10 do
begin
if a[i] -
0@ 2007-07-15 11:18:22
var
p,n,i:integer;
a:array[1..10]of integer;
begin
for i:=1 to 10 do
read(a[i]);
readln(n);
n:=n+30;
p:=0;
for i:=1 to 10 do
if a[i] -
0@ 2007-07-15 11:07:49
var
p,n,i:integer;
a:array[1..10]of integer;
begin
for i:=1 to 10 do
read(a[i]);
readln(n);
n:=n+30;
p:=0;
for i:=1 to 10 do
if a[i] -
0@ 2007-07-14 21:49:33
var
ans,i,n:longint;
a:array[1..11] of longint;
begin
ans:=0;
for i:=1 to 10 do read(a[i]);
readln(n);
for i:=1 to 10 do if n+30>=a[i] then inc(ans);
writeln(ans);
end. -
0@ 2007-07-14 20:33:44
program pingguo;
var
a:array[1..10] of byte;
i,j,p,n:byte;
begin
for i:=1 to 10 do
read(a[i]);
readln(n);
p:=0;
for i:=1 to 10 do
if n+30>=a[i] then p:=p+1;
writeln(p);
end. -
0@ 2007-07-11 16:03:52
program P1102;
var
a:array[1..10] of real;
b,i,j,h:integer;
begin
j:=1;
for i:=1 to 10 do read(a[i]);
readln(h);
for i:=1 to 10 do
if h+30>a[i] then inc(j);
writeln(j);
end. -
0@ 2007-07-04 13:20:05
62%了...
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0@ 2007-06-28 17:18:59
大家共同创造AC神话!!
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0@ 2009-06-28 21:18:28
最大流
建立源点s,汇点t,插入一个点a,再插入十个点i1,i2...i10,如果A[i]>=k+30,连边G[a,i],容量为1。用ford-folkerson算法做即可。编译通过...
├ 测试数据 01:答案正确... 97ms
├ 测试数据 02:答案正确... 132ms
├ 测试数据 03:答案正确... 144ms
├ 测试数据 04:答案正确... 65ms
├ 测试数据 05:答案正确... 90ms
├ 测试数据 06:答案正确... 31ms
├ 测试数据 07:答案正确... 17ms
├ 测试数据 08:答案正确... 273ms
├ 测试数据 09:答案正确... 84ms
├ 测试数据 10:答案正确... 46ms
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Accepted 有效得分:100 有效耗时:979ms效率不是很高,但也能过...
[请神牛bs我]
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0@ 2007-06-22 21:13:47
var
ans,i,n:longint;
a:array[1..11] of longint;
begin
ans:=0;
for i:=1 to 10 do read(a[i]);
readln(n);
for i:=1 to 10 do if n+30>=a[i] then inc(ans);
writeln(ans);
end. -
0@ 2007-06-11 19:02:02
编译通过...
├ 测试数据 01:答案正确... 0ms
├ 测试数据 02:答案正确... 0ms
├ 测试数据 03:答案正确... 0ms
├ 测试数据 04:答案正确... 0ms
├ 测试数据 05:答案正确... 0ms
├ 测试数据 06:答案正确... 0ms
├ 测试数据 07:答案正确... 0ms
├ 测试数据 08:答案正确... 0ms
├ 测试数据 09:答案正确... 0ms
├ 测试数据 10:答案正确... 0ms
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Accepted 有效得分:100 有效耗时:0ms -
0@ 2007-06-03 09:42:11
var
a:array[1..11]of integer;
t,s:integer;
begin
for t:=1 to 11 do read(a[t]);
begin
for t:=1 to 10 do
if a[t] -
0@ 2007-06-08 16:03:15
var
a:array[1..12]of integer;
m,s,x:integer;
begin
for s:=1 to 12 do read(a);
read(m);
m:=m+30;
for s:=1 to 12 do
if a -
0@ 2007-05-27 12:18:19
就两字,弱智!