453 条题解
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0police~ LV 5 @ 2009-06-11 20:18:37
编译通过...
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Accepted 有效得分:100 有效耗时:0ms
A+B式的题 -
02009-06-10 20:30:09@
program s2;
var shengao :integer;
a:array[1..10]of 100..200;
i,k:integer;
begin
k:=0;
for i:=1 to 10 do
read(a[i]);
read(shengao);
for i:=1 to 10 do
begin
if shengao>=a[i] then inc(k)
else if shengao+30>=a[i] then inc(k);
end;
writeln(k);
end. -
02009-06-10 20:18:51@
program q1;
const b=30;
var tot,i:integer;
x:integer;
a:array[1..10] of integer;begin
for i:=1 to 10 do read(a[i]);
read(x);
tot:=0;
for i:=1 to 10 do
if a[i] -
02009-06-09 13:56:52@
编译通过...
├ 测试数据 01:答案正确... 0ms
├ 测试数据 02:答案正确... 0ms
├ 测试数据 03:答案正确... 0ms
├ 测试数据 04:答案正确... 0ms
├ 测试数据 05:答案正确... 0ms
├ 测试数据 06:答案正确... 0ms
├ 测试数据 07:答案正确... 0ms
├ 测试数据 08:答案正确... 0ms
├ 测试数据 09:答案正确... 0ms
├ 测试数据 10:答案正确... 0ms
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Accepted 有效得分:100 有效耗时:0ms -
02009-06-06 17:46:13@
var a:array[1..10] of integer;
j,i,l:integer;
begin
for i:=1 to 10 do read(a[i]);
readln(l);
j:=0;
for i:=1 to 10 do if (l+30>=a[i]) then inc(j);
writeln(j);
end. -
02009-06-02 13:49:03@
var a:array[100..200] of integer;
i,n,l,s:integer;
begin
for i:=1 to 10 do
read(a[i]);
read(n);
l:=n+30;
s:=0;
for i:=1 to 10 do
if a[i] -
02009-05-31 17:25:12@
program apple;
var ap:array[1..10] of integer;
i,ta,sum:integer;
begin
for i:=1 to 10 do
read(ap[i]);
readln;
read(ta);
sum:=0;
for i:=1 to 10 do if ap[i] -
02009-05-26 16:51:35@
program www;
var a:array[1..10] of integer;
h,s,i:integer;
begin
for i:=1 to 10 do readln(a[i]);
readln;
read(h);
s:=0;
for i:=1 to 10 do if a[i] -
02009-05-26 16:45:12@
program qqq;
var a:array[1..10] of integer;
i,h,s:integer;
begin
for i:=1 to 10 do read(a[i]);
readln;
read(h);
s:=0;
for i:=1 to 10 do if a[i] -
02009-05-26 16:33:02@
编译通过...
├ 测试数据 01:答案正确... 0ms
├ 测试数据 02:答案正确... 0ms
├ 测试数据 03:答案正确... 0ms
├ 测试数据 04:答案正确... 0ms
├ 测试数据 05:答案正确... 0ms
├ 测试数据 06:答案正确... 0ms
├ 测试数据 07:答案正确... 0ms
├ 测试数据 08:答案正确... 0ms
├ 测试数据 09:答案正确... 0ms
├ 测试数据 10:答案正确... 0ms
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Accepted 有效得分:100 有效耗时:0msvar
a:array[1..10]of integer;i,j,n:integer;
begin
for i:=1 to 10 do read(a[i]);
readln;
readln(n);
for i:=1 to 10 do
if n+30>=a[i] then inc(j);
writeln(j);
end. -
02009-06-02 14:15:25@
program njy;
var a:array[1..10] of integer;
i,h,s:integer;
begin
for i:=1 to 10 do read(a[i]);
readln;
read(h);
s:=0;
for i:=1 to 10 do if a[i] -
02009-05-26 12:53:43@
var
i,h,s:integer;
a:array[1..10] of integer;
begin
for i:=1 to 10 do
read(a[i]);
readln;
read(h);
s:=0;
h:=h+30;
for i:=1to 10 do
if h>a[i]
then s:=s+1;
writeln(s);
end. -
02009-05-26 12:51:46@
var
i,a,b,d:integer; c:array[1..10] of integer;
begin
a:=0;
d:=30;
for i:=1 to 10 do
read(c[i]);
readln;
readln(b);
for i:= 1 to 10 do
if b+d >= c[i]
then a:=a+1;
writeln(a);
end. -
02009-05-26 12:44:03@
var
a,i,sum:integer;
b:array[1..10]of integer;
begin
sum:=0;
for i:=1 to 10 do
readln(b[i]);
read(a);
a:=a+30;
for i:=1 to 10 do
if a>b[i]
then sum:=sum+1;
writeln(sum);
end. -
02009-06-02 14:20:57@
program ex1;
var
a:array[1..10] of integer;
b,i,n:integer;
begin
n:=0;
for i:=1 to 10 do
readln(a[i]);
readln(b);
b:=b+30;
for i:=1 to 10 do
if a[i] -
02009-05-26 14:16:04@
program ex;
var i,n,s:integer;
a:array[1..10] of integer;
begin
for i:=1 to 10 do read(a[i]);
read(n);
n:=n+30;
for i:=1 to 10 do if a[i] -
02009-05-26 12:28:04@
var
i,b,c:integer;
a:array[1..10]of integer;
begin
for i:=1 to 10 do
read(a[i]);
readln;
read(b);
b:=b+30;
c:=0;
for i:=1 to 10 do
if b>=a[i]
then c:=c+1;
write(c);
end. -
02009-05-24 14:26:40@
program ex;
var i,n,s:integer;
a:array[1..10] of integer;
begin
for i:=1 to 10 do read(a[i]);
read(n);
n:=n+30;
for i:=1 to 10 do if a[i] -
02009-05-22 19:42:39@
#include
#include
main()
{
int h,temp,i=0;
int a[10];
for(i=0;i -
02009-05-17 10:57:21@
var
a:array[1..100]of integer;
s,n:longint;
begin
for i:=1 to 10 do
read(a[i]);
readln(n);
s:=0;
for i:=1 to 10 do
if (a[i]>n)or(z[i]