题解

1309 条题解

  • -1
    @ 2016-07-29 22:23:49
    #include<stdio.h>
    #include<stdlib.h>
    int main()
    {
        int a,b;
        scanf("%d %d",&a,&b);
        printf("%d",a+b);
        return 0;
    }
    
  • -1
    @ 2016-07-26 17:28:09

    var
    a:array[0..201,0..201] of boolean;
    x,j,ans,i,n,m,t:longint;
    begin
    readln(n,m);
    for i:=1 to n do
    begin
    read(x);
    while x<>0 do
    begin
    a[i,x]:=true; a[x,i]:=true;
    read(x);
    end;
    end;
    for i:=1 to n do
    begin
    t:=0;
    for j:=1 to n do
    if a[i,j]=true then inc(t);
    if t>=m then inc(ans);
    end;
    writeln(ans);
    end.

  • -1
    @ 2016-07-24 15:45:29
    print(sum([int(x) for x in raw_input().split(' ')]))
    
  • -1
    @ 2016-07-24 15:45:16

    print(sum([int(x) for x in raw_input().split(' ')]))

  • -1
    @ 2016-07-12 11:46:17
    c++
    #include<cstdio>
    #include<iostream>
    #include<cmath>
    #include<cstring>
    
    using namespace std;
    int a[1000],b[1000],c[1000];char ch[1000];
    int k;
    void plus_(){
        int temp=0;
        
        for(int i = 1; i <= c[0]; i++){
            c[i]=temp+(a[i]+b[i])%k;
            temp=(a[i]+b[i])/k;
        }
        
        if((a[a[0]]+b[b[0]])/k>0){
            
            a[0]++;
            b[0]++;
            c[a[0]]=temp;
            
            c[0]=a[0];
            
        }   
        
    }
    void init(){
        cin>>k;
        cin>>ch;
        c[0]=strlen(ch);
        for(int i = 0; i < c[0]; i++){
            if(ch[i]<='9'&&ch[i]>='0'){
                c[c[0]-i]=ch[i]-'0';
            }
            else{
                c[c[0]-i]=ch[i]-'A'+11;
            }
        }
            
    }
    int main(){
        int flag=0;
        init();
        int ii;
        for(ii = 1; ii <= 30 &&flag==0; ii++){
                
            b[0]=c[0];
            a[0]=c[0];
            for(int i = 1; i <= c[0]; i++){
                a[i]=c[i];
                b[i]=c[c[0]-i+1];
            }
            plus_();
            
            for(int i = 1; i <= c[0]; i++){
                if(a[i]==b[i]){
                    flag=1;
                }
                else{
                    flag=0;
                    break;
                }
            }
            
        }
        
            if(flag==1)cout<<"STEP="<<ii-2;
    else cout<<"Impossible!";
        return 0;
    }
    
  • -1
    @ 2016-07-11 19:02:14
    #include<iostream>
    using namespace std;
    int main()
    {
        int a,b;
        cin>>a>>b;
        cout<<a+b;
        return 0;
    }```
    
  • -1
    @ 2016-07-04 19:30:26

    #include<stdio.h>
    int main()
    {
    int a,b;
    int sum;
    scanf("%d %d",&a,&b);
    sum=a+b;
    printf("%d",sum);
    }

  • -1
    @ 2016-06-20 11:36:50

    program ex1_1;
    var a,b,c:real;
    begin
    read(a,b);
    c:=a+b;
    writeln('c=',c);
    end.

  • -1
    @ 2016-06-04 17:02:32

    var
    a,b:integer;
    begin
    readln(a,b);
    writeln(a+b);
    end.
    这题“太难了”!!!

  • -1
    @ 2016-05-17 12:58:45

    var a,b;
    begin
    read(a,b);
    inc(a,b);
    write(a);
    end.

  • -1
    @ 2016-05-11 21:10:46

    我要在这里练一下

    A+B Problem题解


    ##**最简单**的做法!
    附上:度娘传送门
    太简单啦!
    话说代码高亮好像**不支持Java!!!**
    我要试一下
    java
    import java.util.Scanner;
    public class Main{
    public static void main(String []args){
    Scanner in=new Scanner(System.in);//新建扫描仪(其实就是输入用的啦)
    int a=in.nextInt(),b=in.nextInt();//使用刚刚新建的扫描仪来输入加数
    int ans=a+b;//这一个全国通用......
    System.out.println(ans);//输出不解释......
    }
    }

    现在看来话说好像**支持Java啊**

    • @ 2016-05-11 21:11:50

      怎么**那么多**都没有用好

  • -1
    @ 2015-10-23 19:38:09

    var
    a,b:integer;
    begin
    read(a,b);
    writeln(a+b);
    end.

  • -1
    @ 2015-10-18 21:13:47

    var
    a,b:integer;
    begin
    readln(a,b);
    writeln(a+b);
    end.

  • -1
    @ 2015-10-18 20:35:09

    var
    a,b:integer;
    begin
    readln(a,b);
    writeln(a+b);
    end.

  • -1
    @ 2015-10-18 09:09:06

    #include<stdio.h>
    main()
    {
    int a,b;
    scanf("%d %d",&a,&b);
    printf("%d",a+b);
    return 0;
    }

  • -1
    @ 2015-10-02 14:55:20

    谁会做啊!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

  • -1
    @ 2015-10-02 14:55:03

    太难了,我想了好长好长好长一段时间,太难了,不会做,难度是九啊,多学学高级知识才能做,太难了

  • -1
    @ 2015-09-29 13:34:03

    #include<cstdio>
    using namespace std;
    int main()
    {
    int a,b;
    scanf("%d%d",&a,&b);
    printf("%d",a+b);
    return 0;
    }
    史上最好,最完美,最厉害,最纯真,最无敌,最安全,最ac的题解

  • -1
    @ 2015-09-27 16:09:30

    被坑了!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!不是高精度加法!!!!!!!!!!!!!太简单了!!!!!!!!!!!!!!!!!!!!!!111

  • -1
    @ 2015-09-25 21:21:18

    #include <iostream>
    using namespace std;
    int main()
    {
    int a, b;
    cin >> a >> b;
    cout << a + b << endl;
    return 0;
    }

信息

ID
1000
难度
9
分类
(无)
标签
(无)
递交数
73496
已通过
28188
通过率
38%
被复制
200