- 回文日期
- 2017-02-18 13:41:59 @
Var
f:array[1..12]of integer=((31),(28),(31),(30),(31),(30),(31),(31),(30),(31),(30),(31));
i,d1,d2,dy1,dy2,ri1,ri2,num:longint;
s,t:string;
Function pd(x:longint):boolean;
Var
ri,yue:longint;
rn:boolean;
Begin
ri:=x div 1000+(x div 100 mod 10)*10;
yue:=(x mod 10*10)+(x div 10 mod 10);
if (x mod 4=0) and (x mod 100<>0) or (x mod 400=0) then
rn:=true;
if (x=d1) then
if yue<dy1 then
exit(false)
else
if ri<ri1 then
exit(false);
if x=d2 then
if yue>dy2 then
exit(false)
else
if ri>ri2 then
exit(false);
if (yue>=1) and (yue<=12) then
begin
if yue=2 then
begin
if rn then
if (ri>=1) and (ri<=29) then
exit(true)
else
if (ri>=1) and (ri<=28) then
exit(true);
end
else
if (ri>=1) and (ri<=f[yue]) then
exit(true);
end;
exit(false);
End;
Begin
readln(s);
readln(t);
for i:=1 to 4 do
begin
d1:=d1*10+(ord(s[i])-48);
d2:=d2*10+(ord(t[i])-48);
end;
dy1:=(ord(s[5])-48)*10+(ord(s[6])-48);
dy2:=(ord(t[5])-48)*10+(ord(t[6])-48);
ri1:=(ord(s[7])-48)*10+(ord(s[8])-48);
ri2:=(ord(t[7])-48)*10+(ord(t[8])-48);
num:=0;
for i:=d1 to d2 do
if pd(i) then
inc(num);
writeln(num);
readln;
End.
求解
4 条评论
-
唐复之 LV 8 @ 2017-08-16 21:12:51
莫非vijos数据比NOIP都强?!
-
2017-08-15 18:29:18@
我也是啊,第七个点错了
-
2017-02-18 17:01:27@
#include <iostream>
#include <string>
using namespace std;
int get(string s,bool x)
{
if(x==true)
return (s[0]-48)*1000+(s[1]-48)*100+(s[2]-48)*10+(s[3]-48);
else
return (s[7]-48)*1000+(s[6]-48)*100+(s[5]-48)*10+(s[4]-48);
}
void change(int x,int a[])
{
int i,xx=x;
for(i=0;i<4;i++)
a[i]=xx%10,xx/=10;
}
bool judge(int a[],int year)
{
int month=a[0]*10+a[1],day=a[2]*10+a[3];
if(month==1||month==3||month==5||month==7||month==8||month==10||month==12)
{
if(day<=31)
{
return true;
}
}
if(month==4||month==6||month==9||month==11)
{
if(day<=30)
{
return true;
}
}
if(month==2)
{
if(year%4==0&&year%100!=0||year%400==0)
{
if(day<=29)
{
return true;
}
}
else
{
if(day<=28)
{
return true;
}
}
}
return false;
}
int main ()
{
string start,end;
cin>>start>>end;
int s=get(start,true),e=get(end,true),a[4],sum=0;
if(get(start,true)<get(start,false))
s++;
if(get(end,true)<get(end,false))
e--;
while(s<=e)
{
change(s,a);
if(judge(a,s)==true)
sum++;
s++;
}
cout<<sum;
return 0;
}
不用枚举就行了
测试数据 #0: Accepted, time = 0 ms, mem = 732 KiB, score = 10
测试数据 #1: Accepted, time = 0 ms, mem = 736 KiB, score = 10
测试数据 #2: Accepted, time = 0 ms, mem = 736 KiB, score = 10
测试数据 #3: Accepted, time = 0 ms, mem = 732 KiB, score = 10
测试数据 #4: Accepted, time = 0 ms, mem = 732 KiB, score = 10
测试数据 #5: Accepted, time = 0 ms, mem = 732 KiB, score = 10
测试数据 #6: Accepted, time = 0 ms, mem = 736 KiB, score = 10
测试数据 #7: Accepted, time = 0 ms, mem = 736 KiB, score = 10
测试数据 #8: Accepted, time = 0 ms, mem = 732 KiB, score = 10
测试数据 #9: Accepted, time = 0 ms, mem = 732 KiB, score = 10
Accepted, time = 0 ms, mem = 736 KiB, score = 100 -
2017-02-18 17:01:26@
#include <iostream>
#include <string>
using namespace std;
int get(string s,bool x)
{
if(x==true)
return (s[0]-48)*1000+(s[1]-48)*100+(s[2]-48)*10+(s[3]-48);
else
return (s[7]-48)*1000+(s[6]-48)*100+(s[5]-48)*10+(s[4]-48);
}
void change(int x,int a[])
{
int i,xx=x;
for(i=0;i<4;i++)
a[i]=xx%10,xx/=10;
}
bool judge(int a[],int year)
{
int month=a[0]*10+a[1],day=a[2]*10+a[3];
if(month==1||month==3||month==5||month==7||month==8||month==10||month==12)
{
if(day<=31)
{
return true;
}
}
if(month==4||month==6||month==9||month==11)
{
if(day<=30)
{
return true;
}
}
if(month==2)
{
if(year%4==0&&year%100!=0||year%400==0)
{
if(day<=29)
{
return true;
}
}
else
{
if(day<=28)
{
return true;
}
}
}
return false;
}
int main ()
{
string start,end;
cin>>start>>end;
int s=get(start,true),e=get(end,true),a[4],sum=0;
if(get(start,true)<get(start,false))
s++;
if(get(end,true)<get(end,false))
e--;
while(s<=e)
{
change(s,a);
if(judge(a,s)==true)
sum++;
s++;
}
cout<<sum;
return 0;
}
不用枚举就行了
测试数据 #0: Accepted, time = 0 ms, mem = 732 KiB, score = 10
测试数据 #1: Accepted, time = 0 ms, mem = 736 KiB, score = 10
测试数据 #2: Accepted, time = 0 ms, mem = 736 KiB, score = 10
测试数据 #3: Accepted, time = 0 ms, mem = 732 KiB, score = 10
测试数据 #4: Accepted, time = 0 ms, mem = 732 KiB, score = 10
测试数据 #5: Accepted, time = 0 ms, mem = 732 KiB, score = 10
测试数据 #6: Accepted, time = 0 ms, mem = 736 KiB, score = 10
测试数据 #7: Accepted, time = 0 ms, mem = 736 KiB, score = 10
测试数据 #8: Accepted, time = 0 ms, mem = 732 KiB, score = 10
测试数据 #9: Accepted, time = 0 ms, mem = 732 KiB, score = 10
Accepted, time = 0 ms, mem = 736 KiB, score = 100
- 1
信息
- ID
- 2010
- 难度
- 4
- 分类
- (无)
- 标签
- 递交数
- 1321
- 已通过
- 328
- 通过率
- 25%
- 被复制
- 21
- 上传者