TLE?求教这道题的时间限制&优化方法

……无奈

测试数据 #0: TimeLimitExceeded, time = 609 ms, mem = 568 KiB, score = 0
测试数据 #1: TimeLimitExceeded, time = 593 ms, mem = 572 KiB, score = 0
测试数据 #2: TimeLimitExceeded, time = 609 ms, mem = 572 KiB, score = 0
测试数据 #3: TimeLimitExceeded, time = 593 ms, mem = 572 KiB, score = 0
测试数据 #4: TimeLimitExceeded, time = 609 ms, mem = 572 KiB, score = 0
测试数据 #5: TimeLimitExceeded, time = 609 ms, mem = 572 KiB, score = 0
测试数据 #6: TimeLimitExceeded, time = 609 ms, mem = 572 KiB, score = 0
测试数据 #7: TimeLimitExceeded, time = 593 ms, mem = 572 KiB, score = 0
测试数据 #8: TimeLimitExceeded, time = 609 ms, mem = 572 KiB, score = 0
测试数据 #9: TimeLimitExceeded, time = 609 ms, mem = 572 KiB, score = 0

#include<iostream>
using namespace std;
int n,m,xx[8]={0,0,-1,1,-1,-1,1,1},yy[8]={1,-1,0,0,1,-1,1,-1}; 
char c[100][100],ans[100][100];
int main(){
    cin>>n>>m;
    for(int i=1;i<=n;i++)
        for(int j=1;j<=m;j++) cin>>c[i][j];
    for(int i=1;i<=n;i++){
        for(int j=1;j<=m;j++){
            if(c[i][j]=='*'){
                ans[i][j]='*';cout<<'*';continue;
            }
            int tmp=0;
            for(int k=0;k<8;k++){
                if(i+xx[k]>0&&i+xx[k]<=n&&j+yy[k]>0&&j+yy[k]<=m)
                    if(c[i+xx[k]][j+yy[k]]=='*') tmp++;
            }
            ans[i][j]=tmp+48;
            cout<<ans[i][j];
        }
        cout<<endl;
    }
}

2 条评论

  • @ 2016-10-04 19:58:56

    ……刚用同样的代码AC了……30ms……我只能说评测机……

  • @ 2016-10-04 19:25:41

    这种题都能被卡T我也是醉了

  • 1

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