- 陶陶摘苹果
- 2014-01-18 11:15:25 @
var
a:array[1..10] of integer;
hand :longint;
i,total :integer;
begin
readln (a[1],a[2],a[3],a[4],a[5],a[6],a[7],a[8],a[9],a[10]);
readln (hand);
for i:=1 to 10 do
begin
if hand+30>=a[i] then total:=total+1;
end;
writeln (total);
end.
5 条评论
-
马海塬 LV 7 @ 2016-10-05 16:05:00
好厉害
-
2015-06-02 19:21:27@
第一个题解
program tao;
var
a:array[1..1000] of integer;
b,c,d:integer;
begin
for b:=1 to 10 do
read(a[b]);
readln;
read(c);
for b:=1 to 10 do
if a[b]<=c+30 then
d:=d+1;
write(d);
end.
简单的方法 -
2014-07-24 21:09:17@
var
a:array[1..10] of longint;
n,i,s:longint;
begin
for i:=1 to 10 do read (a[i]);
readln;
read (n);
n:=n+30;
s:=0;
for i:=1 to 10 do if a[i]<=n then inc(s);
writeln (s);
end. -
2014-07-15 15:50:05@
var
a:array[1..10] of longint;
x,i,count:longint;
beginfor i:=1 to 10 do
read(a[i]);
readln(x);
x:=x+30;for i:=1 to 10 do
begin
if x>=a[i] then
count:=count+1;
end;write(count);
readln
end. -
2014-03-06 21:23:29@
赞!!!!!!!!!!
- 1