测试数据 #0: Accepted, time = 0 ms, mem = 448 KiB, score = 10
测试数据 #1: WrongAnswer, time = 15 ms, mem = 448 KiB, score = 0
测试数据 #2: Accepted, time = 0 ms, mem = 448 KiB, score = 10
测试数据 #3: Accepted, time = 0 ms, mem = 452 KiB, score = 10
测试数据 #4: Accepted, time = 0 ms, mem = 452 KiB, score = 10
测试数据 #5: Accepted, time = 0 ms, mem = 452 KiB, score = 10
测试数据 #6: Accepted, time = 0 ms, mem = 448 KiB, score = 10
测试数据 #7: Accepted, time = 0 ms, mem = 452 KiB, score = 10
测试数据 #8: Accepted, time = 15 ms, mem = 448 KiB, score = 10
测试数据 #9: Accepted, time = 0 ms, mem = 448 KiB, score = 10
WrongAnswer, time = 30 ms, mem = 452 KiB, score = 90

#include<stdio.h>
typedef struct
{
char name[20];
int score1;
int score2;
char gan;
char west;
int essay;
int sum;

}stu;
int main()
{
int n;
scanf("%d",&n);
stu list[n];
int i,j;
char temp;
for(i=0;i<n;i++)
{
j=0;
while(scanf("%c",&temp),temp!=' ')
{
list[i].name[j] = temp;
j++;
}
list[i].name[j] = '\0';
scanf("%d",&list[i].score1);//printf("%d\n",list[i].score1);
scanf("%d",&list[i].score2);scanf("%c",&temp);//printf("%d\n",list[i].score2);
scanf("%c",&list[i].gan);scanf("%c",&temp);//printf("%c\n",list[i].gan);
scanf("%c",&list[i].west);//printf("%c\n",list[i].west);
scanf("%d",&list[i].essay);//printf("%d\n",list[i].essay);
list[i].sum = 0;
if(list[i].score1 > 80 && list[i].essay>=1)list[i].sum+=8000;
if(list[i].score1 > 85 && list[i].score2>80)list[i].sum+=4000;
if(list[i].score1 > 90)list[i].sum+=2000;
if(list[i].score1 > 85 && list[i].west=='Y')list[i].sum+=1000;
if(list[i].score2 > 80 && list[i].gan=='Y')list[i].sum+=850;
}
int biao,max = 0;
int sum = 0;
for(i=0;i<n;i++)
{
if(list[i].sum>max)
{
max = list[i].sum;
biao = i;
}
sum+=list[i].sum;
}
//printf("%d",biao);
int len = strlen(list[biao].name);
for(i=0;i<len;i++)
{
printf("%c",list[biao].name[i]);
}
printf("\n");
printf("%d\n",list[biao].sum);
printf("%d",sum);
system("pause");
return 0;
}

求解 用了noip的数据没问题啊！