- 津津的储蓄计划
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zhshcheng1 LV 8 @ 2012-10-05 21:22:03
var
a,b,c,e:integer; d:array[1..12]of integer;
begin b:=0; c:=0;
for a:=1 to 12 do read(d[a]);
for a:=1 to 12 do begin
b:=b+300;
b:=b-(d[a]);
if b0 then begin
b:=b-(b div 100); c:=c+(b div 100)*100;
end;
if e=0 then write(c*1.2);
end.
3 条评论
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ERICFXY LV 8 @ 2014-07-20 10:03:22
var
i,b,m,n:longint;
a:array[0..12] of longint;
begin
for i:=1 to 12 do
readln(a[i]);
i:=0;b:=0;m:=0;
repeat
inc(i);
b:=b+300;
b:=b-a[i];
if b<0 then begin
writeln(-i);
exit;
end else begin
n:=b div 100;
m:=m+n*100;
b:=b-n*100;
end;
until i=12;
if b>=0 then writeln(m*1.2+b:0:0);
end. -
@ 2013-07-09 15:57:50
var
i,j,bank,x,y:longint;
moon,now:array[0..12]of integer;
begin
bank:=0;
for i:=1 to 12 do readln(moon[i]);
now[0]:=0;
for i:= 1 to 12 do
begin
now[i]:=now[i-1]+300;
x:=now[i]-moon[i];
if x<0 then y:=-1
else y:=x div 100;
case y of
-1:begin writeln(-i);halt;end;
0:now[i]:=x;
1..5:begin inc(bank,y*100); now[i]:=x-y*100; end;
end;
end;
writeln(now[12]+bank*1.2:0:0);
end. -
@ 2012-10-07 00:00:04
为什么还错？
- 1
