有三个数据过不去,帮忙看看。

program liwu;

type point=^node;

node=record

mame:string;

shou,chu:longint;

end;

var n,i:integer;

money,m,ch:longint;

a:array[1..10] of point;

s,b:string;

procedure give(num,z,np:longint);

var i,j:integer;

c:string;

begin

a[num]^.chu:=z-z mod np;

for i:=1 to np do

begin

readln(c);

for j:=1 to n do

if c=a[j]^.mame then a[j]^.shou:=a[j]^.shou+z div np;

end;

end;

begin

readln(n);

for i:=1 to n do begin readln(b);new(a[i]);

a[i]^.mame:=b;

a[i]^.chu:=0;

a[i]^.shou:=0;

end;

while not eof do

begin

readln(s);

readln(money,m);

if (money=0) or (m=0) then break;

for i:=1 to n do

if s=a[i]^.mame then give(i,money,m);

end;

for i:=1 to n do

begin

write(a[i]^.mame,' ');

ch:=a[i]^.shou-a[i]^.chu;

writeln(ch);

end;

end.

3 条评论

  • @ 2009-10-27 22:08:35

    干吗要用指针?!

  • @ 2009-07-08 07:49:13

    chegxu

    program aas;

    var

    s:array[1..10] of string;

    p,j:string;

    a,b,c,d,e,i,i1,i2,i3,i4:integer;

    chu:array[1..10] of integer;

    ru:array[1..10] of integer;

    baoliu:array[1..10] of integer;

    begin

    readln(a);

    for i:=1 to a do

    readln(s[i]);

    for i:=1 to a do

    begin

    readln(p);

    for i1:=1 to a do if p=s[i1] then b:=i1;

    read(chu);

    readln(c);

    if c0 then

    begin

    e:=chu div c;

    baoliu:=chu mod c;

    end

    else

    begin

    e:=0;

    baoliu:=chu;

    end;

    for i1:=1 to c do

    begin

    readln(j);

    for i2:=1 to a do

    if j=s[i2] then ru[i2]:=ru[i2]+e;

    end;

    end;

    for i:=1 to a do

    begin

    write(s[i]);

    write(' ');

    writeln(ru[i]-chu[i]+baoliu[i]);

    end;

    end.

  • @ 2009-07-07 20:53:52

    这是什么题?

    偶连题都不懂

  • 1

信息

ID
1035
难度
2
分类
模拟 点击显示
标签
(无)
递交数
5216
已通过
2897
通过率
56%
被复制
19
上传者