题解

158 条题解

  • -1
    @ 2016-07-14 17:00:38
    # include <cstdio>
    # include <cmath>
    # include <cstdlib>
    # include <cctype>
    # include <ctime>
    # include <iostream>
    # include <cstring>
    # include <string>
    # include <algorithm>
    # include <sstream>
    //# define MAX 30001
    using namespace std;
    struct student{
        int Math,Chinese,English;
        int num;
        int score;
    };
    inline bool comparator(const student&s1,const student&s2){
        if(s1.score!=s2.score)return s1.score>s2.score;
        else if(s1.Chinese!=s2.Chinese) return s1.Chinese>s2.Chinese;
        return s1.num<s2.num;
    }
    int main() {
        //freopen("in.in","r",stdin);
        //freopen("in.out","w",stdout);
        int num;
        cin>>num;
        int Math,English,Chinese;
        student*s=new student[num];
        for(int i=0;i<num;i++){
            cin>>Chinese>>Math>>English;
            s[i].Chinese=Chinese;
            s[i].Math=Math;
            s[i].English=English;
            s[i].score=Chinese+Math+English;
            s[i].num=i+1;
        }
        sort(s,s+num,comparator);
        for(int i=0;i<5;i++)
            cout<<s[i].num<<" "<<s[i].score<<"\n";
        delete[]s;
        return 0;
    }
    
  • -1
    @ 2016-06-24 13:06:10
    评测结果
    编译成功
    
    测试数据 #0: Accepted, time = 0 ms, mem = 520 KiB, score = 10
    测试数据 #1: Accepted, time = 0 ms, mem = 520 KiB, score = 10
    测试数据 #2: Accepted, time = 0 ms, mem = 520 KiB, score = 10
    测试数据 #3: Accepted, time = 0 ms, mem = 520 KiB, score = 10
    测试数据 #4: Accepted, time = 0 ms, mem = 520 KiB, score = 10
    测试数据 #5: Accepted, time = 0 ms, mem = 516 KiB, score = 10
    测试数据 #6: Accepted, time = 0 ms, mem = 520 KiB, score = 10
    测试数据 #7: Accepted, time = 0 ms, mem = 516 KiB, score = 10
    测试数据 #8: Accepted, time = 0 ms, mem = 516 KiB, score = 10
    测试数据 #9: Accepted, time = 0 ms, mem = 516 KiB, score = 10
    Accepted, time = 0 ms, mem = 520 KiB, score = 100
    代码
    #include <cstdio>
    #include <algorithm>
    using std :: sort;
    struct Stu {
      int c,m,e;
      int sum,num;
    }pupil[301];
    bool cmp(Stu x,Stu y) {
      if (x.sum != y.sum)
        return x.sum > y.sum;
      if (x.c != y.c)
        return x.c > y.c;
      return x.num < y.num;
    }
    int n;
    int main() {
      scanf("%d",&n);
      for (int i = 1;i <= n;i++) {
        scanf("%d%d%d",&pupil[i].c,&pupil[i].m,&pupil[i].e);
        pupil[i].sum = pupil[i].c+pupil[i].m+pupil[i].e;
        pupil[i].num = i;
      }
      sort(pupil + 1,pupil + n + 1,cmp);
      for (int i = 1;i <= 5;i++)
        printf("%d %d\n",pupil[i].num,pupil[i].sum);
      return 0;
    }
    
  • -1
    @ 2016-06-04 09:09:00

    var
    a:array[1..1000] of longint;
    i,n,x,num:longint;
    begin
    fillchar(a,sizeof(a),0);
    readln(n);
    for i:=1 to n do
    begin
    read(x);
    a[x]:=1;
    end;
    for i:=1 to 1000 do
    if a[i]=1 then num:=num+1;
    writeln(num);
    for i:=1 to 100 do
    if a[i]=1 then write(i,' ');
    end.

  • -1
    @ 2016-05-21 15:42:44

    type
    student=record
    num:integer;
    ch:0..100;
    ma:0..100;
    en:0..100;
    total:integer;
    end;
    var a:array[1..300]of student;
    i,j,n:integer; empty:student;
    begin
    readln(n);
    for i:=1 to n do
    begin
    a[i].num:=i;
    read(a[i].ch,a[i].ma,a[i].en);
    a[i].total:=(a[i].ch+a[i].ma+a[i].en);
    end;
    for i:=1 to n-1 do
    for j:=i+1 to n do
    begin
    if a[i].total<a[j].total then
    begin
    empty:=a[i];
    a[i]:=a[j];
    a[j]:=empty;
    end;
    if (a[i].total=a[j].total)and(a[i].ch<a[j].ch) then
    begin
    empty:=a[i];
    a[i]:=a[j];
    a[j]:=empty;
    end;
    if (a[i].total=a[j].total)and(a[i].ch=a[j].ch)and(a[i].num<a[j].num) then
    begin
    empty:=a[i];
    a[i]:=a[j];
    a[j]:=empty;
    end;
    end;
    for i:=1 to 5 do
    writeln(a[i].num,' ',a[i].total);
    end.

  • -1
    @ 2016-05-21 15:18:37

    program money;
    type pro=record
    ch:0..100;
    ma:0..100;
    en:0..100;
    tot:0..300;
    st:0..300;
    end;
    var
    i,j,n:integer;
    t:pro;
    a:array[0..300] of pro;
    b:array[0..300] of integer;
    begin
    readln(n);
    for i:= 1 to n do
    begin
    with a[i] do
    begin
    read(ch,ma,en);
    tot:=ch+ma+en;
    st:=i;
    end;
    end;
    for i:= 1 to n-1 do
    for j:= i+1 to n do
    begin
    if a[i].tot<a[j].tot
    then begin
    t:=a[i];
    a[i]:=a[j];
    a[j]:=t;
    end;
    if a[i].tot=a[j].tot
    then
    begin
    if a[i].ch<a[j].ch
    then
    begin
    t:=a[i];
    a[i]:=a[j];
    a[j]:=t;
    end;
    end;
    end;
    for i:= 1 to 5 do
    begin
    with a[i] do
    begin
    writeln(st,tot:4);
    end;
    end;
    readln;
    end.

  • -1
    @ 2016-03-02 15:11:28

    #include <iostream>
    #include <string.h>
    #include <stdlib.h>
    #include <stdio.h>
    #include <algorithm>
    #include <math.h>

    using namespace std;

    struct qwq{
    int sum,chi,num;
    }a[305];
    int n;

    int cmp(qwq x,qwq y){
    if(x.sum == y.sum && x.chi == y.chi) return x.num < y.num;
    if(x.sum == y.sum) return x.chi > y.chi;
    return x.sum > y.sum;
    }

    void init(){
    scanf("%d",&n);
    int tmp2,tmp3;
    for(int i = 1;i <= n;i ++){
    scanf("%d%d%d",&a[i].chi,&tmp2,&tmp3);
    a[i].num = i;
    a[i].sum = tmp2 + tmp3 + a[i].chi;
    }
    }

    void solve(){
    sort(a + 1,a + 1 + n,cmp);
    for(int i = 1;i <= 5;i ++){
    printf("%d %d\n",a[i].num,a[i].sum);
    }
    }

    int main(){
    init();
    solve();
    return 0;
    }

  • -1
    @ 2016-01-30 16:34:01

    #include<iostream>
    using namespace std;
    int main()
    {
    int n,hu,a,b,c,y[301],h[301],z[301];
    cin>>n;
    for (int i=1;i<=n;i++)
    {
    cin>>a>>b>>c;
    y[i]=a;
    h[i]=i;
    z[i]=a+b+c;
    }
    for (int i=1;i<=n-1;i++)
    for (int j=i+1;j<=n;j++)
    if (z[j]>z[i]||(z[j]==z[i]&&y[j]>y[i])||(z[j]==z[i]&&y[j]==y[i]&&h[j]<h[i]))
    {
    hu=z[i];
    z[i]=z[j];
    z[j]=hu;
    hu=y[i];
    y[i]=y[j];
    y[j]=hu;
    hu=h[i];
    h[i]=h[j];
    h[j]=hu;
    }
    for (int i=1;i<=5;i++)
    cout<<h[i]<<" "<<z[i]<<endl;
    }
    水题哈哈哈

  • -1
    @ 2015-10-13 20:29:34

    记录信息
    评测状态 Accepted
    题目 P1398 奖学金
    递交时间 2015-10-13 20:29:19
    代码语言 C++
    评测机 VijosEx
    消耗时间 35 ms
    消耗内存 536 KiB
    评测时间 2015-10-13 20:29:22
    评测结果
    编译成功

    测试数据 #0: Accepted, time = 15 ms, mem = 532 KiB, score = 10
    测试数据 #1: Accepted, time = 15 ms, mem = 532 KiB, score = 10
    测试数据 #2: Accepted, time = 0 ms, mem = 532 KiB, score = 10
    测试数据 #3: Accepted, time = 0 ms, mem = 532 KiB, score = 10
    测试数据 #4: Accepted, time = 0 ms, mem = 532 KiB, score = 10
    测试数据 #5: Accepted, time = 0 ms, mem = 532 KiB, score = 10
    测试数据 #6: Accepted, time = 0 ms, mem = 528 KiB, score = 10
    测试数据 #7: Accepted, time = 0 ms, mem = 532 KiB, score = 10
    测试数据 #8: Accepted, time = 0 ms, mem = 536 KiB, score = 10
    测试数据 #9: Accepted, time = 5 ms, mem = 532 KiB, score = 10
    Accepted, time = 35 ms, mem = 536 KiB, score = 100
    代码
    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    using namespace std;
    struct point {
    int a,b,c,pos,sum;
    }per[310];
    bool cmp(point x,point y)
    {
    if(x.sum!=y.sum)
    return x.sum>y.sum;
    if(x.a!=y.a)
    return x.a>y.a;
    return x.pos<y.pos;
    }
    int main()
    {
    //freopen("","r",stdin);
    //freopen("","w",stdout);
    int n;
    scanf("%d",&n);
    for(int i=1;i<=n;i++){
    scanf("%d%d%d",&per[i].a,&per[i].b,&per[i].c);
    per[i].pos=i;
    per[i].sum=per[i].a+per[i].b+per[i].c;
    }
    sort(per+1,per+n+1,cmp);
    for(int i=1;i<=5;i++)printf("%d %d\n",per[i].pos,per[i].sum);
    return 0;
    }

  • -1
    @ 2015-09-11 19:16:36

    #include<algorithm>
    #include<cstdio>
    using namespace std;
    const int MAXN = 300 + 10;

    int sum[MAXN];

    struct Stu{
    int a, b, c, num;
    }s[MAXN];

    bool cmp(Stu x, Stu y){
    if(sum[x.num] != sum[y.num])
    return sum[x.num] > sum[y.num];
    else if(x.a != y.a)
    return x.a > y.a;
    else
    return x.num < y.num;
    }

    int main()
    {
    int n;
    scanf("%d", &n);
    for(int i=1; i<=n; i++){
    scanf("%d%d%d", &s[i].a, &s[i].b, &s[i].c);
    sum[i] = s[i].a + s[i].b + s[i].c;
    s[i].num = i;
    }
    sort(&s[1], &s[1]+n, cmp);

    for(int i=1; i<=5; i++)
    printf("%d %d\n", s[i].num, sum[s[i].num]);
    return 0;
    }
    注意是学号小的在前。。。。被坑了

  • -1
    @ 2015-08-17 17:31:04

    #include<iostream>
    #include<cstdio>
    #include<algorithm>
    using namespace std;
    struct student{
    int Chinese;
    int math;
    int English;
    int sum;
    int number;
    }a[30000];
    int comp(const student&a,const student&b)
    {
    if(a.sum>b.sum)return 1;
    if(a.sum<b.sum)return 0;
    if(a.Chinese>b.Chinese)return 1;
    if(a.Chinese<b.Chinese)return 0;
    if(a.number<b.number)return 1;
    if(a.number>b.number)return 0;
    return 0;
    }
    int main()
    {
    int n,i;
    scanf("%d",&n);
    for(i=1;i<=n;i++){
    scanf("%d%d%d",&a[i].Chinese,&a[i].math,&a[i].English);
    a[i].sum=a[i].Chinese+a[i].math+a[i].English;
    a[i].number=i;
    }
    sort(a+1,a+n+1,comp);
    if(n>5){
    n=5;
    }
    for(i=1;i<=n;i++){
    printf("%d",a[i].number);
    printf(" ");
    printf("%d\n",a[i].sum);
    }

    return 0;
    }

  • -1
    @ 2015-08-10 16:09:52

    program exam;
    var i,j,m,n,k,l:longint;
    a,b,c,d,y:array[0..10000] of longint;
    procedure qt(l,r:longint);
    var i,j,m,p,m1,m2,m3:longint;
    begin
    i:=l; j:=r;
    m:=a[(l+r) div 2];
    m2:=y[(l+r) div 2];
    m3:=d[(l+r) div 2];
    repeat
    while (a[i]>m) or ((a[i]=m) and (y[i]>m2)) or ((a[i]=m) and (y[i]=m2) and (d[i]<m3)) do inc(i);
    while (a[j]<m) or ((a[j]=m) and (y[j]<m2)) or ((a[j]=m) and (y[j]=m2) and (d[j]>m3)) do dec(j);
    if i<=j then
    begin
    p:=a[i]; a[i]:=a[j]; a[j]:=p;
    p:=d[i]; d[i]:=d[j]; d[j]:=p;
    p:=y[i]; y[i]:=y[j]; y[j]:=p;
    inc(i); dec(j);
    end;
    until i>j;
    if i<r then qt(i,r);
    if l<j then qt(l,j);
    end;

    begin
    readln(n);
    for i:=1 to n do
    begin
    readln(y[i],b[i],c[i]);
    a[i]:=y[i]+b[i]+c[i];
    d[i]:=i;
    end;
    qt(1,n);
    for i:=1 to 5 do
    writeln(d[i],' ',a[i]);
    end.

  • -1
    @ 2015-08-04 14:33:20

    无聊排序

  • -1
    @ 2015-05-02 14:53:40

    小练一下排序算法

    #include<cmath>
    #include<vector>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #define sz 310
    #define LL long long
    #define for1(v,a,b) for (int v=a;v<=b;v++)
    #define for2(v,a,b) for (int v=a;v>=b;v--)
    using namespace std;
    struct Type{
    int ch,sum,pos;
    }a[sz];
    int n;
    int my_comp(const Type &x,const Type &y){
    if (x.sum>y.sum) return 1;
    if (x.sum<y.sum) return 0;
    if (x.ch>y.ch) return 1;
    if (x.ch<y.ch) return 0;
    if (x.pos<y.pos) return 1;
    if (x.pos>y.pos) return 0;
    }
    int main(){
    //freopen("p1.in","r",stdin);
    int ma,en;
    scanf("%d",&n);
    for1(i,1,n){
    scanf("%d%d%d",&a[i].ch,&ma,&en);
    a[i].sum=a[i].ch+ma+en;
    a[i].pos=i;
    }
    sort(a+1,a+n+1,my_comp);
    for1(i,1,5)
    printf("%d %d\n",a[i].pos,a[i].sum);
    return 0;
    }

  • -1
    @ 2014-11-02 20:14:07

    var i,j,k,l,m,n,yw,sx,yy:longint; xs:array[1..10000,1..3]of longint;procedure qs(q,h:longint);var i,j,mid1,mid2,mid3:longint; t:array[1..3]of longint;begin i:=q; j:=h; mid1:=xs[(q+h) div 2,1]; mid2:=xs[(q+h)div 2,2]; mid3:=xs[(q+h)div 2,3]; repeat while (xs[i,1]>mid1)or((xs[i,1]=mid1)and(xs[i,2]>mid2)) or((xs[i,1]=mid1)and(xs[i,2]=mid2)and(xs[i,3]<mid3)) do inc(i); while (xs[j,1]<mid1)or((xs[j,1]=mid1)and(xs[j,2]<mid2)) or((xs[j,1]=mid1)and(xs[j,2]=mid2)and(xs[j,3]>mid3)) do dec(j); if i<=j then begin t:=xs[i]; xs[i]:=xs[j]; xs[j]:=t; inc(i);dec(j); end; until i>j; if q<j then qs(q,j); if h>i then qs(i,h);end;begin readln(n); for i:=1 to n do begin read(yw,sx,yy); xs[i,1]:=yw+sx+yy; xs[i,2]:=yw; xs[i,3]:=i; end; qs(1,n); for i:=1 to 5 do writeln(xs[i,3],' ',xs[i,1]); end.
    多关键字排序

  • -1
    @ 2014-10-26 11:49:15

    var
    yu,shu,wai,yu1,shu1,wai1:array[1..300] of integer; i,j,k,t,s,n:longint; zong,kong,ans:array[1..300] of longint; begin
    readln(n);
    for i:=1 to n do
    begin
    read(yu[i],shu[i],wai[i]); yu1[i]:=yu[i]; shu1[i]:=shu[i]; wai1[i]:=wai[i]; readln; end;
    for i:=1 to n do
    begin
    kong[i]:=yu[i]+shu[i]+wai[i]; zong[i]:=kong[i]; end;
    for i:=1 to n-1 do
    for j:=i+1 to n do begin
    if (zong[i]<zong[j]) then begin t:=zong[i];zong[i]:=zong[j];zong[j]:=t; t:=yu1[i];yu1[i]:=yu1[j];yu1[j]:=t; t:=shu1[i];shu1[i]:=shu1[j];shu1[j]:=t; t:=wai1[i];wai1[i]:=wai1[j];wai1[j]:=t; end; end;
    for i:=1 to n do
    for j:=1 to n do begin if (zong[i]=kong[j]) and (yu1[i]=yu[j]) and (shu1[i]=shu[j]) and (wai1[i]=wai[j]) then ans[i]:=j; end; for i:=1 to 10 do
    begin
    if (zong[i]=zong[i+1]) and ((yu1[i]<yu1[i+1]) or (ans[i]>ans[i+1])) then begin
    t:=zong[i];zong[i]:=zong[i+1];zong[i+1]:=t; t:=yu1[i];yu1[i]:=yu1[i+1];yu1[i+1]:=t; t:=ans[i];ans[i]:=ans[i+1];ans[i+1]:=t; end; end;
    for i:=1 to 5 do
    begin
    writeln(ans[i],' ',zong[i]); end;
    end.

  • -1
    @ 2014-08-28 23:17:44

    绝妙的算法,在结构体里设一个变量,是总分数*1000000+语文*1000+总人数-学号,然后对它排序,保证了排序的唯一性
    #include<iostream>
    using namespace std;
    struct student
    {
    int c;
    int m;
    int e;
    long long int sum;
    int k;
    int num;

    }a[305];
    int n,t;
    int main()
    {
    student a[305];
    cin>>n;
    for(int i=0;i<n;i++)
    {
    cin>>a[i].c>>a[i].m>>a[i].e;
    a[i].k=a[i].c+a[i].m+a[i].e;
    a[i].num=i+1;
    a[i].sum=a[i].k*1000000+a[i].c*1000+n-i;

    }
    for(int i=0;i<n;i++)
    for(int j=0;j<n-i-1;j++)
    if(a[j].sum<a[j+1].sum)
    {
    t=a[j].sum;a[j].sum=a[j+1].sum;a[j+1].sum=t;
    t=a[j].num;a[j].num=a[j+1].num;a[j+1].num=t;
    t=a[j].k;a[j].k=a[j+1].k;a[j+1].k=t;
    }
    for(int i=0;i<5;i++)
    cout<<a[i].num<<" "<<a[i].k<<"\n";
    cout<<endl;
    //system("pause");
    return 0;

    }

  • -1
    @ 2014-08-08 18:40:02

    var
    yu,shu,wai,yu1,shu1,wai1:array[1..300] of integer;
    i,j,k,t,s,n:longint;
    zong,kong,ans:array[1..300] of longint;
    begin
    readln(n);
    for i:=1 to n do
    begin
    read(yu[i],shu[i],wai[i]);
    yu1[i]:=yu[i];
    shu1[i]:=shu[i];
    wai1[i]:=wai[i];
    readln;
    end;
    for i:=1 to n do
    begin
    kong[i]:=yu[i]+shu[i]+wai[i];
    zong[i]:=kong[i];
    end;
    for i:=1 to n-1 do
    for j:=i+1 to n do
    begin
    if (zong[i]<zong[j]) then begin
    t:=zong[i];zong[i]:=zong[j];zong[j]:=t;
    t:=yu1[i];yu1[i]:=yu1[j];yu1[j]:=t;
    t:=shu1[i];shu1[i]:=shu1[j];shu1[j]:=t;
    t:=wai1[i];wai1[i]:=wai1[j];wai1[j]:=t;
    end;
    end;
    for i:=1 to n do
    for j:=1 to n do
    begin
    if (zong[i]=kong[j]) and (yu1[i]=yu[j]) and (shu1[i]=shu[j]) and (wai1[i]=wai[j]) then ans[i]:=j;
    end;
    for i:=1 to 10 do
    begin
    if (zong[i]=zong[i+1]) and ((yu1[i]<yu1[i+1]) or (ans[i]>ans[i+1])) then begin
    t:=zong[i];zong[i]:=zong[i+1];zong[i+1]:=t;
    t:=yu1[i];yu1[i]:=yu1[i+1];yu1[i+1]:=t;
    t:=ans[i];ans[i]:=ans[i+1];ans[i+1]:=t;
    end;
    end;
    for i:=1 to 5 do
    begin
    writeln(ans[i],' ',zong[i]);
    end;
    end.

  • -1
    @ 2014-08-07 09:11:25

    #include<iostream>
    #include<cstdio>
    using namespace std;
    struct st
    {
    int xh;
    int yw;
    int sx;
    int yy;
    int zf;
    };
    void jh(int&a,int&b)
    {
    int t=a;
    a=b;
    b=t;
    }
    void aa(st&a,st&b)
    {
    jh(a.zf,b.zf);
    jh(a.yw,b.yw);
    jh(a.xh,b.xh);
    }
    main()
    {
    int i,j,n;
    st a[301];
    cin>>n;
    for(i=1;i<=n;i++)
    {
    a[i].xh=i;
    cin>>a[i].yw>>a[i].sx>>a[i].yy;
    a[i].zf=a[i].yw+a[i].sx+a[i].yy;
    }
    for(i=1;i<n;i++)
    for(j=i+1;j<=n;j++)
    {
    if(a[i].zf<a[j].zf)
    aa(a[i],a[j]);
    else
    if(a[i].zf==a[j].zf&&a[i].yw<a[j].yw)
    aa(a[i],a[j]);
    else
    if(a[i].zf==a[j].zf&&a[i].yw==a[j].yw&&a[i].xh>a[j].xh)
    aa(a[i],a[j]);
    }
    for(i=1;i<=5;i++)
    cout<<a[i].xh<<" "<<a[i].zf<<endl;
    }

信息

ID
1398
难度
4
分类
其他 | 排序 点击显示
标签
递交数
6456
已通过
2669
通过率
41%
被复制
22
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