2 条题解
-
112234洪子昊 (12234洪子昊) LV 8 @ 2021-12-14 10:49:41
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int x,y;
cin>>x>>y;
if(abs(x)<=1&&abs(y)<=1)
cout<<"yes";
else
cout<<"no";
} -
02021-12-04 11:28:55@
#include<iostream> #include<cstdio> #include<cmath> using namespace std; int main() { int a,b; cin>>a>>b; if(abs(a)<=1&&abs(b)<=1) cout<<"yes"; else cout<<"no"; }
- 1
信息
- ID
- 2347
- 难度
- 5
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- (无)
- 标签
- 递交数
- 223
- 已通过
- 80
- 通过率
- 36%
- 被复制
- 2
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