啊，很久没见到这么简单的题了

#include<iostream>
using namespace std;
int main(){
    unsigned long long a, b;
    cin >> a >> b;
    cout << a*b;
    return 0;
}

#include<iostream>
using namespace std;
int main()
{
long a,b;
cin>>a>>b;
cout<<a*b<<endl;
return 0;
}

//我是对的！！！

#include<iostream>
using namespace std;
int main()
{
long a,b;
cin>>a>>b;
cout<<a*b<<endl;
return 0;
}

#include<iostream>
#include<cmath>
using namespace std;
const double PI=3.14159;
int main(){
long long h,r;
cin >> h >> r;
cout<<h*r;
return 0;
}

#include <iostream>
using namespace std;
int main()
{
long long A,B;
cin>>A>>B;
cout<<A*B;
return 0;
}

@戴铖翔 遇事不决用long long
#include<iostream>
using namespace std;
int main()
{
long long A,B;
cin>>A>>B;
cout<<A*B;
return 0;
}