25 条题解
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312206戴爱佳 (12206戴爱佳) LV 7 @ 2022-01-07 16:01:46
#include<iostream>
using namespace std;
int main()
{
int hb,st,kl,x;
cin>>hb>>st>>kl;
if(hb<st)
if(kl<hb)
x=kl;
else
x=hb;
else
if(kl<st)
x=kl;
else
x=st;
cout<<x*2;
return 0;
}
家人们绝对正确 -
22021-12-25 11:38:38@
#include<iostream> using namespace std; int main() { int han,shu,ke,x; cin>>han>>shu>>ke; if(han<shu) if(ke<han) x=ke; else x=han; else if(ke<shu) x=ke; else x=shu; cout<<x*2; return 0; }
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12024-07-20 11:27:25@
#include<bits/stdc++.h>
using namespace std;
int main()
{
int a,b,c,minn=10000;
cin>>a>>b>>c;
if(minn>a)
minn=a;
if(minn>b)
minn=b;
if(minn>c)
minn=c;
cout<<minn*2;
} -
12024-06-25 18:40:57@
省的钱数取决于套餐数,而套餐数又取决于购买数量最少的那种商品
#include<iostream> using namespace std; int main(){ ios::sync_with_stdio(false); int a, b, c; cin >> a >> b >> c; cout << 2*(min(min(a, b), c)); return 0; }
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02023-07-22 21:58:50@
#include<bits/stdc++.h> using namespace std; int main() { int a,b,c,n; cin>>a>>b>>c; n=min(a,min(b,c)); cout<<n*2; }
保证正确 !!!
-
02022-07-01 14:28:10@
#include<iostream>
using namespace std;
int main()
{
int a,b,c,min;
cin>>a>>b>>c;
if(a<b)
if(c<a)
min=c;
else
min=a;
else
if(c<b)
min=c;
else
min=b;
cout<<min*2<<endl;
return 0;
} -
-22021-12-14 20:36:24@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2;
return 0;
} -
-22021-12-14 20:36:06@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2<<endl;
return 0;
} -
-32021-12-14 20:37:45@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2;
return 0;
} -
-32021-12-14 20:37:41@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2;
return 0;
} -
-32021-12-14 20:37:38@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2;
return 0;
} -
-32021-12-14 20:37:35@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2;
return 0;
} -
-32021-12-14 20:37:32@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2;
return 0;
} -
-32021-12-14 20:37:09@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2;
return 0;
} -
-32021-12-14 20:37:06@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2;
return 0;
} -
-32021-12-14 20:37:02@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2;
return 0;
} -
-32021-12-14 20:36:31@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2;
return 0;
} -
-32021-12-14 20:36:28@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2;
return 0;
} -
-32021-12-14 20:36:19@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2;
return 0;
} -
-42021-12-14 20:37:29@
#include<iostream>
using namespace std;
int main()
{
int han,shu,ke,x;
cin>>han>>shu>>ke;
if(han<shu)
if(ke<han)
x=ke;
else
x=han;
else
if(ke<shu)
x=ke;
else
x=shu;
cout<<x*2;
return 0;
}
信息
- ID
- 1698
- 难度
- 1
- 分类
- (无)
- 标签
- 递交数
- 176
- 已通过
- 112
- 通过率
- 64%
- 被复制
- 2
- 上传者