1 条题解
-
-212237余傲寒 (12237余傲寒) LV 8 @ 2021-11-29 09:40:11
#include<iostream>
#include<cmath>
using namespace std;int chongzu_max(int n);
int chongzu_min(int n);int main()
{
int n;
cin>>n;
int n2 = n;
while(n2 != 495)
{
int n0 = chongzu_max(n2);
int n1 = chongzu_min(n2);
n2 = n0 - n1;
cout<<n0<<" - "<<n1<<" = "<<n2<<endl;
if(n2 < 100 && n2 >= 10) n2 *= 10;
if(n2 < 10) n *= 100;
if(n2 == 0) return 0;
}
return 0;
}int chongzu_max(int x)
{
int a = x % 10;
x /= 10;
int b = x % 10;
x /= 10;
int c = x % 10;
int n[6];
n[0] = a * 100 + b * 10 + c;
n[1] = a * 100 + c * 10 + b;
n[2] = b * 100 + a * 10 + c;
n[3] = b * 100 + c * 10 + a;
n[4] = c * 100 + a * 10 + b;
n[5] = c * 100 + b * 10 + a;
int max = 0;
for(int i = 0; i <= 5; i++)
if(n[i] > max) max = n[i];
return max;
}int chongzu_min(int x)
{
int a = x % 10;
x /= 10;
int b = x % 10;
x /= 10;
int c = x % 10;
int n[6];
n[0] = a * 100 + b * 10 + c;
n[1] = a * 100 + c * 10 + b;
n[2] = b * 100 + a * 10 + c;
n[3] = b * 100 + c * 10 + a;
n[4] = c * 100 + a * 10 + b;
n[5] = c * 100 + b * 10 + a;
int min = n[0];
for(int i = 1; i <= 5; i++)
if(n[i] < min) min = n[i];
return min;
}
- 1
信息
- ID
- 1204
- 难度
- 1
- 分类
- (无)
- 标签
- 递交数
- 31
- 已通过
- 26
- 通过率
- 84%
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