3 条题解

  • 0
    @ 2023-11-25 11:18:33

    #include<bits/stdc++.h>
    using namespace std;
    int d1,d2,d3,d4;
    int month(int k)
    {
    if(k==1||k==3||k==5||k==7||k==8||k==10||k==12)
    return 31;
    else if(k==4||k==6||k==9||k==11)
    return 30;
    else if(k==2)
    return 28;
    }
    int tianshu(int d1,int d2,int d3,int d4)
    {
    int p1=month(d1)-d2;
    int ans=0;
    if(d3-d1==0) return d4-d2;
    else if(d3-d1==1) return p1+d4;
    else if(d3-d1!=0||d3-d1!=1)
    {
    for(int i=d1+1;i<=d3-1;i++)
    {
    ans+=month(i);
    }
    return (month(d1)-d2)+ans+d4;
    }
    }
    int main()
    {
    cin>>d1>>d2>>d3>>d4;
    cout<<tianshu(d1,d2,d3,d4);
    return 0;
    }

  • 0

    #include<bits/stdc++.h>
    using namespace std;

    int main()
    {
    int n,n1,a,b,s=0,s1=0;
    cin>>n>>a>>n1>>b;
    switch(n)
    {
    case 1:s+=a;break;
    case 2:s=s+a+31;break;
    case 3:s=s+a+59;break;
    case 4:s=s+a+90;break;
    case 5:s=s+a+120;break;
    case 6:s=s+a+151;break;
    case 7:s=s+a+181;break;
    case 8:s=s+a+212;break;
    case 9:s=s+a+243;break;
    case 10:s=s+a+273;break;
    case 11:s=s+a+304;break;
    case 12:s=s+a+334;break;
    }
    switch(n1)
    {
    case 1:s1+=b;break;
    case 2:s1=s1+b+31;break;
    case 3:s1=s1+b+59;break;
    case 4:s1=s1+b+90;break;
    case 5:s1=s1+b+120;break;
    case 6:s1=s1+b+151;break;
    case 7:s1=s1+b+181;break;
    case 8:s1=s1+b+212;break;
    case 9:s1=s1+b+243;break;
    case 10:s1=s1+b+273;break;
    case 11:s1=s1+b+304;break;
    case 12:s1=s1+b+334;break;
    }
    cout<<s1-s;
    return 0;

    }

  • -9
    #include <iostream>
    using namespace std;
    int a[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
    int main()
    {
        int
                month,day,zhongjiancha,cha;cin>>month>>day;
        int month1,day1;cin>>month1>>day1;
        int benyuecha=a[month]-day;
        if(month+1==month1)
        {
            cha=a[month]-day;
            cout<<cha+day1;
        }
        if(month==month1)
            cout<<day1-day;
        if(month+1!=month1&&month!=month1)
        {
            for(int i=month+1;i<month1;i++)
                zhongjiancha+=a[i];
            cout<<zhongjiancha+benyuecha+day1;
        }
        return 0;
    }
    
    
  • 1

信息

ID
1036
难度
4
分类
(无)
标签
递交数
143
已通过
61
通过率
43%
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