简单，统计有多少不是空格的字符即可
#include<iostream>
#include<cstdio>
#include<cmath>
#include<algorithm>
#include<cstring>
#include<string>
#include<fstream>
using namespace std;
string s;
int i,n,j,k=0,m,l,o,p;
//ifstream fin("title.in");
//ofstream fout("title.out");
int main()
{
getline(cin,s);
for(i=0;i<s.length();i++)
{
if(s[i]!=' ') k++;

}
cout<<k;
//fin.close();
//fout.close();
return 0;
}