Wrong Answer
foo.c: In function 'main':
foo.c:14:5: warning: ignoring return value of 'scanf', declared with attribute warn_unused_result [-Wunused-result]
scanf("%d", &T);
^~~~~~~~~~~~~~~
foo.c:16:9: warning: ignoring return value of 'scanf', declared with attribute warn_unused_result [-Wunused-result]
scanf("%d",&n);
^~~~~~~~~~~~~~
foo.c:18:13: warning: ignoring return value of 'scanf', declared with attribute warn_unused_result [-Wunused-result]
scanf("%d",&m1[j]);
^~~~~~~~~~~~~~~~~~
foo.c:21:17: warning: ignoring return value of 'scanf', declared with attribute warn_unused_result [-Wunused-result]
scanf("%d",&m2[k]);
^~~~~~~~~~~~~~~~~~
代码
#include<stdio.h>
int MIN(int n,int m){
if (n>m) {
return n;
}else return m;
}
int main(){
int T,n;
int i=0,j=0,k=0,f=1;
int m1[9999],m2[9999];
scanf("%d", &T);
for (i=0; i<T; i++) {//组数
scanf("%d",&n);
for (j=0; j<=n; j++) {
scanf("%d",&m1[j]);
}
for (k=0; k<=n; k++) {
scanf("%d",&m2[k]);
}
for (k=n; k>=0; k--) {
if (m1[k]==0&&m2[k]!=0) {//上是0
printf("0 1\n");
break;
}else if (m1[k]==0&&m2[k]==0){//都是0
continue;
}else if (m2[k]==0&&m1[k]!=0){//下是0
printf("infty\n");
break;
}else if (m1[k]!=0&&m2[k]!=0){//都不0
for (f=1; f<MIN(m1[k],m2[k]); f++) {
if (m1[k]%f==0&&m2[k]%f==0) {
m1[k]/=f;
m2[k]/=f;
}
}
printf("%d %d\n",m1[k],m2[k]);
break;
}
}
}
return 0;}
信息
- 递交者
-
simplebrick LV 4
- 类型
- 递交
- 题目
- P1000 hitwh 2019 新生赛 A ∞
- 语言
- C
- 递交时间
- 2020-12-20 17:52:51
- 评测时间
- 2020-12-20 17:52:51
- 评测机
-
undefined
- 分数
- 0
- 总耗时
- 165ms
- 峰值内存
- 388.0 KiB