Sumdiv
Description
求A^B的所有约数(即因子)之和,并对其取模 9901再输出。(1<=A,B<=5×10^7)
Format
Input
输入两个自然数A,B。
Output
输出答案 mod 9901 。
Sample 1
Input
2 3
Output
15
【样例说明】
2^3 = 8.
The natural divisors of 8 are: 1,2,4,8. Their sum is 15.
15 modulo 9901 is 15 (that should be output).
Limitation
1s, 32MiB for each test case.
Source
poj1845