7 条题解

  • 1
    @ 2024-04-12 15:35:26

    #include <iostream>
    using namespace std;
    int main()
    {
    int a,b,c,sum=0,d;
    a=1; b=1;
    cin>>d;
    sum=a+b;
    for(int i=3; i<=d; i++)
    {

    c=a+b; sum=sum+c;

    a=b; b=c;
    }
    cout<<sum<<endl;
    return 0;
    }

  • 1

    include <iostream>
    using namespace std;
    int main()
    {
    int a,b,c,sum,d;
    a=1; b=1;
    cin>>d;
    sum=a+b;
    for(int i=3; i<=d; i++)
    {

    c=a+b; sum=sum+c;

    a=b; b=c;
    }
    cout<<sum<<endl;
    return 0;
    }

  • 1
    @ 2019-10-19 21:32:46

    直接通过变量迭代实现……

    #include<stdio.h>
    int main()
    {
        int a=0,b=1;
        int sum=0;
        int i;
        int n;
        scanf("%d",&n);
        for(i=0;i<n;i++)
        {
            sum+=b;
            b+=a;
            a=b-a;
        }
        printf("%d",sum);
        return 0;
    }
    
  • 1
    @ 2019-10-05 02:10:45
    #include <iostream>
    using namespace std;
    int num=0; //存储总和
    int FLine(int n);
    int FLine(int n)
    {
        int x;
        if(n==1 || n==2)
            x=1;
        else
            x=FLine(n-1)+FLine(n-2);  
        return x;
    }
    int main()
    {
        int n;
        cin>>n;
        for(int i=1;i<=n;i++)
            num+=FLine(i);
        cout<<num;
        return 0;
    }
    
  • 0
    @ 2022-09-30 11:32:58

    #include <stdio.h>
    //斐波拉契 i hate you!
    int main() {
    int a = 1, b = 1, c;
    unsigned int n;
    scanf("%ld", &n);
    unsigned int sum = 2;
    if (n == 1)
    printf("1");
    if (n == 2)
    printf("2");
    if (n > 2) {
    for (int i = 3; i <= n; i++) {
    c = a + b;
    sum+=c;
    a = b;
    b = c;
    }
    printf("%ld", sum);
    }

    return 0;
    }

  • -1

    #include <iostream>
    using namespace std;
    int main()
    {
    int a,b,c,xs,x=2,m=1,d;
    cin>>d;

    a=1;
    b=1;

    while(m<=d-2)
    {
    c=a;
    a=b;
    b=a+c;
    m++;

    xs=b;
    x=x+xs;
    }

    cout<<x;

    return 0;
    }

  • -1
    #include<iostream>
    using namespace std;
    
    int fib(int n)
    {
        int x=0;
        if(n==1 || n==2)
            x=1;
        else 
            x=fib(n-2)+fib(n-1);
        return x;
    };
    
    int main()
    {
        int sum=0;
        int n;
        cin>>n;
        for(int i=1;i<=n;i++)
        {
            sum=sum+fib(i);
        }
    
        cout<<sum<<endl;
    
        system("pause");
        return 0;
    }
    
    
    
    
  • 1

A2-3 循环结构入门:斐波拉契数列的和

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