2 条题解

  • 3
    @ 2018-12-25 15:34:04

    #include <stdio.h>

    int f(int a,int b);
    int main()
    {
    int x;scanf("%d",&x);
    int count=0;
    for(int i=2;i<x;i++)
    {
    int ii=i;
    for(int j=ii+1;j<=x;j++)
    if(f(ii,j)==-1) count++;
    }
    printf("%d",count);
    }

    int f(int a,int b)
    {
    int t;
    if(a < b)
    {
    t = a;a = b;b = t;
    }
    while(t=a%b)
    {
    a = b;b = t;
    }
    if(b == 1)
    return -1;
    return 0;
    }

  • 1
    @ 2023-12-26 15:04:59

    #include<iostream>
    using namespace std;

    int gcd(int a,int b)
    {
    if (b == 0)return a;
    else return gcd(b, a % b);
    }

    int main()
    {
    //(2,3), (2,5), (3,4), (3,5), (4,5), (5,6)观察知j>i
    int n; cin >> n;
    int cnt = 0;
    for (int i = 2; i <= n; i++)
    for (int j = i+1; j <= n; j++)
    if (gcd(i, j) == 1 )cnt++;//3 4 4 3 3 5 5 3 重复计算

    cout << cnt;
    return 0;
    }

  • 1

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