3 条题解
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6Drac0nids LV 5 @ 2019-04-09 21:54:15
#include<stdio.h> #include<stdlib.h> int main() { int n, a; int first; scanf("%d", &n); scanf("%d", &first); for (int i = 1; i < n; i++) { scanf("%d", &a); printf("%d ", a); } printf("%d", first); } /* // 动态数组的方法 int main() { int n; int *arr; scanf("%d", &n); arr = (int *)malloc(sizeof(int)*n); for (int i = 0; i < n; i++) { scanf("%d", arr + i); } for (int i = 1; i < n; i++) { printf("%d ", *(arr + i)); } printf("%d", *arr); free(arr); } */ /* // 链表的方法 typedef struct node { int data; struct node *next; }Node, *pNode; int main() { pNode head, p, s, q; int n; int x; head = (pNode)malloc(sizeof(Node)); p = head; head->next = NULL; scanf("%d", &n); for (int i = 0; i < n; i++) { scanf("%d", &x); s = (pNode)malloc(sizeof(Node)); s->data = x; s->next = NULL; p->next = s; p = s; } p = head->next; x = p->data; p = p->next; for (int i = 0; i < n-1; i++) { printf("%d ", p->data); p = p->next; } printf("%d", x); } */
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12021-01-22 21:53:03@
#include <iostream>
using namespace std;
int main()
{
int x,y,z;
cin>>x;
cin>>y;
for(int a=1; a<x; a++)
{
cin>>z;
cout<<z<<" ";
}
cout<<y<<" ";
return 0;
} -
02022-10-09 14:27:56@
#include <stdio.h>
//有warning
int main(){
long long int n;
scanf("%lld",&n);
int a[n];
for(long long int i=0;i<n;i++){
scanf("%lld",&a[i]);
}
for(long long int i=1;i<n;i++){
printf("%lld ",a[i]);
}
printf("%lld",a[0]);
return 0;
}
- 1
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