3 条题解
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0黄辰飞 (njnu19180237) LV 9 @ 2019-03-31 13:27:01
#include <iostream> #include <math.h> using namespace std; class Complex { float real, image; public: Complex() { } Complex(float r, float i) { real = r; image = i; } double Modulo() { return sqrt(real * real + image * image); } friend ostream& operator<<(ostream &o, Complex &c) { if (c.image > 0) return o << c.real << "+" << c.image << "i" << endl; else { if (c.image == 0) return o << c.real << endl; else return o << c.real << c.image << "i" << endl; } } }; int main() { int r1, r2, r3, i1, i2, i3; cin >> r1 >> i1 >> r2 >> i2 >> r3 >> i3; Complex c1(r1, i1), c2(r2, i2), c3(r3, i3); if (c1.Modulo() <= c2.Modulo()) { if (c2.Modulo() <= c3.Modulo()) { cout << c1 << c2 << c3; } else { if (c1.Modulo() <= c3.Modulo()) { cout << c1 << c3 << c2; } else { cout << c3 << c1 << c2; } } } else { if (c1.Modulo() <= c3.Modulo()) { cout << c2 << c1 << c3; } else { if (c2.Modulo() < c3.Modulo()) { cout << c2 << c3 << c1; } else { cout << c3 << c2 << c1; } } } return 0; }
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-12019-06-16 22:35:37@
#include <iostream>
using namespace std;
class Complex
{
int a, b;
public:
Complex(int x = 0, int y = 0)
{
a = x;
b = y;
}int operator<(const Complex& c2)
{
if ((a*a + b * b)<(c2.a*c2.a + c2.b*c2.b))
return 1;
else
return 0;
}Complex operator=(const Complex &c2)
{
a = c2.a;
b = c2.b;
return *this;
}void print()
{
if (b>0)
cout << a << "+" << b << "i" << endl;
if (b<0)
cout << a << b << "i" << endl;
if (b == 0)
cout << a << endl;
}
};int main()
{
int a1, b1, a2, b2, a3, b3;
cin >> a1 >> b1;
cin >> a2 >> b2;
cin >> a3 >> b3;
Complex c1(a1, b1);
Complex c2(a2, b2);
Complex c3(a3, b3);
Complex t;
if (!(c1 < c2))
{
t = c1;
c1 = c2;
c2 = t;
}
if (!(c2 < c3))
{
t = c2;
c2 = c3;
c3 = t;
}
if (!(c1 < c2))
{
t = c1;
c1 = c2;
c2 = t;
}
c1.print();
c2.print();
c3.print();
} -
-22021-01-24 19:49:34@
#include <iostream>
#include <math.h>
using namespace std;
class Complex
{
float real, image;
public:
Complex()
{}
Complex(float r, float i)
{
real = r;
image = i;
}
double Modulo()
{
return sqrt(real * real + image * image);
}
friend ostream& operator<<(ostream &o, Complex &c)
{
if (c.image > 0)
return o << c.real << "+" << c.image << "i" << endl;
else
{
if (c.image == 0)
return o << c.real << endl;
else
return o << c.real << c.image << "i" << endl;
}}
};
int main()
{
int r1, r2, r3, i1, i2, i3;
cin >> r1 >> i1 >> r2 >> i2 >> r3 >> i3;
Complex c1(r1, i1), c2(r2, i2), c3(r3, i3);
if (c1.Modulo() <= c2.Modulo())
{
if (c2.Modulo() <= c3.Modulo())
{
cout << c1 << c2 << c3;
}
else
{
if (c1.Modulo() <= c3.Modulo())
{
cout << c1 << c3 << c2;
}
else
{
cout << c3 << c1 << c2;
}
}
}
else
{
if (c1.Modulo() <= c3.Modulo())
{
cout << c2 << c1 << c3;
}
else
{
if (c2.Modulo() < c3.Modulo())
{
cout << c2 << c3 << c1;
}
else
{
cout << c3 << c2 << c1;
}
}
}return 0;
}
- 1
信息
- ID
- 1012
- 难度
- 3
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- (无)
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- 317
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- 153
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