3 条题解
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0端木俁 (房佳坤) LV 10 @ 2021-03-26 20:21:43
#include<iostream> using namespace std; const int N=13; bool isleap(int n) { if(n%4==0&&n%100!=0||n%400==0) return true; else return false; } int main() { int year,month,day;cin>>year>>month>>day; int a[N]={0,31,28,31,30,31,30,31,31,30,31,30,31}; if(isleap(year)==true) a[2]=29; int x;cin>>x; while(x!=0) { day++; if(day>a[month]){ day=1; month++; } if(month>12){ month=1; year++; if(isleap(year)==true) a[2]=29; else a[2]=28; } x--; } cout<<year<<" "<<month<<" "<<day; return 0; }
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02019-03-31 13:22:27@
#include <iostream> using namespace std; class Date { int year; int month; int day; public: void init(int y, int m, int d) { year = y; month = m; day = d; } int isLeapYear() { if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)) return 1; else return 0; } void add(int num) { int Month[13] = { 0,31,28 + isLeapYear(),31,30,31,30,31,31,30,31,30,31 }; day += num; while (day > Month[month]) { day -= Month[month]; month++; if (month > 12) { month -= 12; year++; Month[2] = 28 + isLeapYear(); } } } void print() { cout << year << " " << month << " " << day; } }; int main() { int y, mon, d; cin >> y >> mon >> d; int num; cin >> num; Date date; date.init(y, mon, d); date.add(num); date.print(); return 0; }
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-32021-01-29 14:47:14@
#include<iostream> using namespace std; int main() { int month_day[13]={0,31,28,31,30,31,30,31,31,30,31,30,31}; int year,month,day; int mum; cin>>year>>month>>day>>mum; if((year%4==0&&year%100!=0)||(year%400==0)) month_day[2]=29; for(int i=1;i<=mum;i++) { day++; if(day>month_day[month]) { day=1; month++; } if(month>12) { month=1; year++; if((year%4==0&&year%100!=0)||(year%400==0)) month_day[2]=29; else month_day[2]=28; } } cout<<year<<" "<<month<<" "<<day; return 0; }
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- ID
- 1003
- 难度
- 6
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- (无)
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- 193
- 通过率
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