3 条题解
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0房佳坤 LV 10 @ 2022-04-01 20:55:00
#include <iostream> #include <functional> using namespace std; int main() { int n; cin >> n; n = 100 - n; int cnt(0); function<void(int&, int)> Main = [=](int& cnt, int x) -> void { for (int i = 0; i <= 20; i ++ ) for (int j = 0; j <= 50; j ++ ) if (5 * i + 2 * j == x) printf("%d %d\n", i, j), cnt ++ ; }; Main(cnt, n); if (!cnt) puts("N"); return 0; }
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02019-04-19 14:46:32@
转自毛老师的穷举法
n=100-int(input())
if n==1 or n==3:
print("N")
else:
for a in range(n//5+1):
for b in range(n//2+1):
if(5*a+b*2==n):
print(a,b) -
02019-04-04 22:17:47@
c=5
d=0
a=int(input())
b=a
if a<97 or a==98:
if a%2==0:
while b<=100:
c=(100-b)/2
print(int(d), int(c))
b=b+10
d=d+2
else :
if a<=95:
b=a+5
while b<=100:
c=(100-b)/2
print(int(d+1), int(c))
b=b+10
d=d+2
else :
print("N")haoren
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