7 条题解

  • 2
    @ 2017-10-31 12:21:07

    -*- coding: utf-8 -*-

    """
    Spyder Editor

    This is a temporary script file.
    """

    import math
    a=int(input())
    b=a/3.1415
    c=math.sqrt(b)
    print(round(c,3))

  • 1
    @ 2019-10-25 16:33:14
    print(round((int(input())/3.1415)**0.5,3))
    #python3
    

    一行代码解决问题(smirk

  • 1
    @ 2019-04-15 20:27:11

    import math
    n=int(input())
    r=math.sqrt(n/3.1415)
    print(round(r,3))
    #python3

  • 1
    @ 2018-11-07 13:23:19
    #include <stdio.h>
    #include<cmath>
    #include<iostream>
    using namespace std;
    double n;
    int main()
    {
        cin>>n;
        printf("%.3f",sqrt(n/3.1415));
        return 0;
    }
    
  • 0
    @ 2023-06-19 22:08:27

    import math;print(round(math.sqrt((eval(input())/3.1415)),3))

  • 0
    @ 2023-06-16 23:26:32

    s=int(input())
    r=(s/3.1415)**0.5
    print(round(r,3))

  • 0
    @ 2022-05-24 17:39:53

    import math
    s=int(input("请输入圆的面积:"))
    r=math.sqrt(s/3.1415)
    print("圆的半径为",round(r,2))

  • 1

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