8 条题解
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1房佳坤 LV 10 @ 2021-02-27 14:35:18
#include<iostream> using namespace std; int main() { char a[1000]; int i=0,n=0; while((a[n]=getchar())!='\n') n++; n--; while(a[i]==a[n-i]) i++; if(i>n/2) cout<<"yes"; else cout<<"no"; return 0; }
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12020-09-16 22:53:34@
#python3
s=input() a=s[::-1] if a==s: print("yes") else: print("no")
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02020-09-21 16:12:05@
string=str(input("input string")) length=len(string) count=0 for i in range(0,length-1): if string[i]!=string[-1-i]: count=1 break else: continue if count==0: print("yes") else: print("no")
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02020-09-21 16:11:41@
Gene20191 LV 8 @ 5 天前
python
a = input()
p = len(a)
def decide(a):
for i in range(int(p/2)):
if a[i] == a[p-i-1]:
continue
else:
return False
return True
if decide(a)==True:
print("yes")
else:
print("no")
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02020-09-21 16:08:11@
a = input()
b = a[::-1]
if a == b:
print('yes')
else:
print('no') -
02020-09-21 16:08:04@
s=input()
c=s[::-1]
if c==s:
print('yes')
else:
print('no') -
02020-09-16 16:20:10@
from math import floor n = str(input()) m = floor((1/2)*len(n)) x = n[len(n)-m:] if n[:m] == x[::-1]: print("yes") else: print("no")
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02020-09-16 11:18:03@
a = input()
p = len(a)
def decide(a):
for i in range(int(p/2)):
if a[i] == a[p-i-1]:
continue
else:
return False
return Trueif decide(a)==True:
print("yes")
else:
print("no")
- 1
信息
- ID
- 1027
- 难度
- 4
- 分类
- (无)
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- 递交数
- 86
- 已通过
- 35
- 通过率
- 41%
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