题解

1 条题解

  • 0
    @ 2017-11-07 17:21:12
    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<vector>
    #include<queue>
    #define INF 2<<27
    #define maxn 5000
    using namespace std;
    int n,k,m;
    struct Edge
    {
        int from,to,cap,flow,cost;
    };
    struct MCMF
    {
        int from,n,m,s,t;
        vector<Edge> edges;
        vector<int> G[maxn];
        int inq[maxn];
        int d[maxn];
        int p[maxn];
        int a[maxn];
        void init(int n)
        {
            this->n=n;
            for (int i=0;i<n;i++)
                G[i].clear();
            edges.clear();
        }
        void AddEdge(int from,int to,int cap,int cost)
        {
            edges.push_back((Edge){from,to,cap,0,cost});
            edges.push_back((Edge){to,from,0,0,-cost});
            m=edges.size();
            G[from].push_back(m-2);
            G[to].push_back(m-1);
        }
        //其他成员函数 
        bool BellmanFord(int s,int t,int &flow,int &cost)
    {
        for (int i=0;i<=t;i++)
            d[i]=-INF;
        memset(inq, 0,sizeof(inq));
        d[s]=0;inq[s]=1;p[s]=-1;a[s]=INF;
        
        queue<int> Q;
        Q.push(s);
        while(!Q.empty())
        {
            int u=Q.front();
            Q.pop();
            inq[u]=0;
            for (int i=0;i<G[u].size();i++)
            {
                Edge& e=edges[G[u][i]];
                if (e.cap> e.flow&&d[e.to]<d[u]+e.cost)
                {
                    d[e.to]=d[u]+e.cost;
                    p[e.to]=G[u][i];
                    a[e.to]=min(a[u],e.cap-e.flow);
                    if (!inq[e.to])
                    {
                        Q.push(e.to);
                        inq[e.to]=1;
                    }
                }
            }
        }
        if (d[t]==-INF) return 0;
        flow +=a[t];
        cost +=d[t]*a[t];
        int u=t;
        while (u!=s)
        {
            edges[p[u]].flow+=a[t];
            edges[p[u]^1].flow-=a[t];
            u=edges[p[u]].from;
        }
        return 1;
    }
    } net;
    
    int mincost(int s,int t)
    {
        int flow=0,cost=0;
        while(net.BellmanFord(s,t,flow,cost));
        return cost;
    }
    int xx[21],yy[21];
    int main()
    {
        scanf("%d%d",&n,&m);
        int ww=0;
        for (int i=1;i<=n;i++)
            xx[i]=++ww;
        for (int i=1;i<=m;i++)
            yy[i]=++ww;
        for (int i=1;i<=n;i++)
            for (int j=1;j<=m;j++)
            {
                scanf("%d",&k);
                net.AddEdge(xx[i],yy[j],1,k);
            }
        for (int i=1;i<=n;i++)
            net.AddEdge(0,xx[i],2,0);  
        for (int i=1;i<=m;i++)
            net.AddEdge(yy[i],n+m+1,2,0);  
        printf("%d",mincost(0,n+m+1));
     
        return 0;
    }
    
  • 1

信息

难度
9
分类
(无)
标签
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递交数
1
已通过
1
通过率
100%
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