迭代器好耶!
#include <bits/stdc++.h>
using namespace std;
int main()
{
istream_iterator<long long> in(cin),end; ++in;
cout<<accumulate(in,end,0LL);
return 0;
}
#include<bits/stdc++.h>
using namespace std;
int main(){
unsigned long long n , sum = 0;
cin >> n;
unsigned long long a[n];
for(int i = 0 ; i < n ; i++){
cin >> a[i];
sum += a[i];
}
cout << sum;
return 0;
}
这题像 A+B 吗?
#include <iostream>
using namespace std;
typedef long long Num;
int main()
{
Num n,danielLele=0ll,duLiu;
cin>>n;
if(!n){cout<<"0"<<endl;return 0;}
for(Num i=1ll;i<=n;i++)
{
cin>>duLiu;
danielLele+=duLiu;
}
cout<<danielLele<<endl;
return 0;
}
这题和你谷的A+B
很像。代码:
include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin >> n;
int temp, ans = 0;
for(int i = 0; i < n; i++)
{
cin >> temp;
ans += temp;
}
cout << ans;
return 0;
}