#include <iostream>
using namespace std;
class DateTime
{
    int year, month, day, hour, minute, second;
public:
    void init(int y, int mon, int d, int h, int min, int s)
    {
        year = y;
        month = mon;
        day = d;
        hour = h;
        minute = min;
        second = s;
    }
    int isLeapYear()
    {
        if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0))
            return 1;
        else
            return 0;
    }
    void add(int num)
    {
        second = second + num;
        if (second >= 60)
        {
            minute += second / 60;
            second = second % 60;
        }

        if (minute >= 60)
        {
            hour += minute / 60;
            minute = minute % 60;
        }
        if (hour >= 24)
        {
            day += hour / 24;
            hour = hour % 24;
        }
        int Month[13] = { 0,31,28 + isLeapYear(),31,30,31,30,31,31,30,31,30,31 };
        while (day > Month[month])
        {
            day -= Month[month];
            month++;
            if (month > 12)
            {
                month -= 12;
                year++;
                Month[2] = 28 + isLeapYear();
            }
        }
    }
    void print()
    {
        cout << year << " " << month << " " << day << " " << hour << " " << minute << " " << second;
    }
};
int main()
{
    int y, mon, d, h, min, s;
    cin >> y >> mon >> d >> h >> min >> s;
    int num;
    cin >> num;
    DateTime t;
    t.init(y, mon, d, h, min, s);
    t.add(num);
    t.print();
    return 0;
}

//这个题思路和1-3一致 时分秒的进率是固定的所以没有比较特别的点
#include<iostream>
using namespace std;
int main()
{
    int month_day[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};//利用下标的便利之处记录每月天数上限^^b
    int year,month,day,shi,fen,miao;
    int mum;
    cin>>year>>month>>day>>shi>>fen>>miao>>mum;
    if((year%4==0&&year%100!=0)||(year%400==0))//开局先判断闰年
        month_day[2]=29;//修改二月上限
    for(int i=1;i<=mum;i++)//我一秒一秒加好做一点( ￣︶￣)
    {
        miao++;//每次加一秒后判断是否要进位
        if(miao==60)
        {
            miao=0;
            fen++;
        }
        if(fen==60)
        {
            fen=0;
            shi++;
        }
        if(shi==24)
        {
            shi=0;
            day++;
        }
        if(day>month_day[month])
        { 
            day=1;
            month++;
        }
        if(month>12)
        {
            month=1;
            year++;
            if((year%4==0&&year%100!=0)||(year%400==0))//年份改变时要再判断二月上限是否改变
                month_day[2]=29;
            else
                month_day[2]=28;
            
        }
    }
    cout<<year<<" "<<month<<" "<<day<<" "<<shi<<" "<<fen<<" "<<miao;
    
    return 0;