- 回文串
- 2023-05-27 00:24:28 @
#include<bits/stdc++.h>
using namespace std;
int main()
{
int len;
char a[101]={};
cin>>a;
len=strlen(a);
for(int j=0;j<len/2;j++){
if(a[j]!=a[len-j-1]){
cout<<"No";
return 0;
}
}
cout<<"Yes";
}
1 条评论
-
唐子瞳 LV 8 @ 2023-05-27 00:24:57
就是逊呀!这题!
- 1