foo.cc: In function 'int main()':
foo.cc:4:20: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
    4 | #define rep(i,a,b) for (int i=(a); i<=(b); i++)
      |                    ^~~
foo.cc:17:5: note: in expansion of macro 'rep'
   17 |     rep(i,1,m) scanf("%d",&a[i]); a[0]=0; a[m+1]=n+1;
      |     ^~~
foo.cc:17:35: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
   17 |     rep(i,1,m) scanf("%d",&a[i]); a[0]=0; a[m+1]=n+1;
      |                                   ^
foo.cc:16:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   16 |     scanf("%d%d",&n,&m); clr(f);
      |     ~~~~~^~~~~~~~~~~~~~
foo.cc:17:21: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   17 |     rep(i,1,m) scanf("%d",&a[i]); a[0]=0; a[m+1]=n+1;
      |                ~~~~~^~~~~~~~~~~~

Found 10 testcases.
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