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Background

Special for beginners, ^_^
输入N个字符串，创建一个单链表，并打印出来。

Description

Given two integers x and y, print the sum.
要求：

Format

Input

Two integers x and y, satisfying 0 <= x, y <= 32767.
两行：
第一行：n
第二行：n个整型数，以空格分开

Output

One integer, the sum of x and y.
n个整型数，以空格分开

Sample 1

Input

4
1 3 4 5

Output

1 3 4 5

Limitation

1s, 1024KiB for each test case.

Hint

Free Pascal Code

var a,b:longint;
begin
    readln(a,b);
    writeln(a+b);
end.

C Code

#include <stdio.h>
int main(void)
{
    int a, b;
    scanf("%d%d", &a, &b);
    printf("%d\n", a + b);
    return 0;
}

C++ Code

#include <iostream>
using namespace std;
int main()
{
    int a, b;
    cin >> a >> b;
    cout << a + b << endl;
    return 0;
}

Python Code

a, b = [int(i) for i in raw_input().split()]
print(a + b)

Java Code

import java.io.*;
import java.util.Scanner;

public class Main {

    /**
     * @param args
     * @throws IOException 
     */
    public static void main(String[] args) throws IOException {
        Scanner sc = new Scanner(System.in);
        int a = sc.nextInt();
        int b = sc.nextInt();
        System.out.println(a + b);
    }
}

Source

Vijos Original