Description

输入两个数字，输出它们之和

Input

一行两个数字 \(A, B(0 \le A, B<100)\)。

Output

输出这两个数字之和

Sample Input

1 2

Sample Output

3

Hint

Q: Where are the input and the output? A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout. You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer". User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer" if you try to do so. Here is a sample solution for problem 1000 using C++/G++:

#include <bits/stdc++.h>

using namespace std;

int  main()

{

    int a,b;

    cin >> a >> b;

    cout << a+b << endl;

    return 0;

}

It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error. Here is a sample solution for problem 1000 using C/GCC:

#include <stdio.h>

int main()

{

    int a,b;

    scanf("%d %d",&a, &b);

    printf("%d\n",a+b);

    return 0;

}

Here is a sample solution for problem 1000 using PASCAL:

program p1000(Input,Output); 

var 

  a,b:Integer; 

begin 

   Readln(a,b); 

   Writeln(a+b); 

end.

Here is a sample solution for problem 1000 using JAVA: Now java compiler is jdk 1.5, next is program for 1000

import java.io.*;

import java.util.*;

public class Main

{

            public static void main(String args[]) throws Exception

            {

                    Scanner cin=new Scanner(System.in);

                    int a=cin.nextInt(),b=cin.nextInt();

                    System.out.println(a+b);

            }

}

Old program for jdk 1.4

import java.io.*;

import java.util.*;



public class Main

{

    public static void main (String args[]) throws Exception

    {

        BufferedReader stdin = 

            new BufferedReader(

                new InputStreamReader(System.in));



        String line = stdin.readLine();

        StringTokenizer st = new StringTokenizer(line);

        int a = Integer.parseInt(st.nextToken());

        int b = Integer.parseInt(st.nextToken());

        System.out.println(a+b);

    }

}

Source

Vijos Original_BZOJ